是否有一种方法可以确定一个方法需要执行多少时间(以毫秒为单位)?


当前回答

一个在Swift 4中使用mach_absolute_time()的细粒度计时的例子:

let start = mach_absolute_time()

// do something

let elapsedMTU = mach_absolute_time() - start
var timebase = mach_timebase_info()
if mach_timebase_info(&timebase) == 0 {
    let elapsed = Double(elapsedMTU) * Double(timebase.numer) / Double(timebase.denom)
    print("render took \(elapsed)")
}
else {
    print("timebase error")
}

其他回答

这里有一个Swift 3的解决方案,可以在任何地方对代码进行等分,以找到长时间运行的进程。

var increment: Int = 0

var incrementTime = NSDate()

struct Instrumentation {
    var title: String
    var point: Int
    var elapsedTime: Double

    init(_ title: String, _ point: Int, _ elapsedTime: Double) {
        self.title = title
        self.point = point
        self.elapsedTime = elapsedTime
    }
}

var elapsedTimes = [Instrumentation]()

func instrument(_ title: String) {
    increment += 1
    let incrementedTime = -incrementTime.timeIntervalSinceNow
    let newPoint = Instrumentation(title, increment, incrementedTime)
    elapsedTimes.append(newPoint)
    incrementTime = NSDate()
}

用法:-

instrument("View Did Appear")

print("ELAPSED TIMES \(elapsedTimes)")

样例输出:

[MyApp.SomeViewController.]仪器仪表(标题:“开始视图 Did Load", point: 1, elapsedTime: 0.040504038333892822), MyApp.SomeViewController。检测(标题:“完成添加 SubViews", point: 2, elapsedTime: 0.010585010051727295), MyApp.SomeViewController。仪器仪表(标题:“视图已出现”, 点:3,elapsedTime: 0.56564098596572876)]

下面是我使用的两个单行宏:

#define TICK   NSDate *startTime = [NSDate date]
#define TOCK   NSLog(@"Time: %f", -[startTime timeIntervalSinceNow])

像这样使用它:

TICK;

/* ... Do Some Work Here ... */

TOCK;

这里有另一种方法,在Swift中,使用defer关键字来做到这一点

func methodName() {
  let methodStart = Date()
  defer {
    let executionTime = Date().timeIntervalSince(methodStart)
    print("Execution time: \(executionTime)")
  }
  // do your stuff here
}

来自苹果的文档:defer语句用于在将程序控制权转移到该defer语句出现的范围之外之前执行代码。

这类似于try/finally块,优点是将相关代码分组。

你可以得到很好的时间(秒。部分秒)使用这个StopWatch类。它使用了iPhone的高精度计时器。使用NSDate只能获得秒级精度。这个版本是专门为自动发布和objective-c设计的。如果需要的话,我也有一个c++版本。你可以在这里找到c++版本。

StopWatch.h

#import <Foundation/Foundation.h>


@interface StopWatch : NSObject 
{
    uint64_t _start;
    uint64_t _stop;
    uint64_t _elapsed;
}

-(void) Start;
-(void) Stop;
-(void) StopWithContext:(NSString*) context;
-(double) seconds;
-(NSString*) description;
+(StopWatch*) stopWatch;
-(StopWatch*) init;
@end

StopWatch.m

#import "StopWatch.h"
#include <mach/mach_time.h>

@implementation StopWatch

-(void) Start
{
    _stop = 0;
    _elapsed = 0;
    _start = mach_absolute_time();
}
-(void) Stop
{
    _stop = mach_absolute_time();   
    if(_stop > _start)
    {
        _elapsed = _stop - _start;
    }
    else 
    {
        _elapsed = 0;
    }
    _start = mach_absolute_time();
}

-(void) StopWithContext:(NSString*) context
{
    _stop = mach_absolute_time();   
    if(_stop > _start)
    {
        _elapsed = _stop - _start;
    }
    else 
    {
        _elapsed = 0;
    }
    NSLog([NSString stringWithFormat:@"[%@] Stopped at %f",context,[self seconds]]);

    _start = mach_absolute_time();
}


-(double) seconds
{
    if(_elapsed > 0)
    {
        uint64_t elapsedTimeNano = 0;

        mach_timebase_info_data_t timeBaseInfo;
        mach_timebase_info(&timeBaseInfo);
        elapsedTimeNano = _elapsed * timeBaseInfo.numer / timeBaseInfo.denom;
        double elapsedSeconds = elapsedTimeNano * 1.0E-9;
        return elapsedSeconds;
    }
    return 0.0;
}
-(NSString*) description
{
    return [NSString stringWithFormat:@"%f secs.",[self seconds]];
}
+(StopWatch*) stopWatch
{
    StopWatch* obj = [[[StopWatch alloc] init] autorelease];
    return obj;
}
-(StopWatch*) init
{
    [super   init];
    return self;
}

@end

该类有一个返回自动释放对象的静态stopWatch方法。

调用start后,使用seconds方法获取运行时间。再次调用start来重新启动它。或者停下来停下来。在调用stop后,您仍然可以随时读取时间(调用秒数)。

函数中的示例(执行的定时调用)

-(void)SomeFunc
{
   StopWatch* stopWatch = [StopWatch stopWatch];
   [stopWatch Start];

   ... do stuff

   [stopWatch StopWithContext:[NSString stringWithFormat:@"Created %d Records",[records count]]];
}

许多答案很奇怪,并没有真正以毫秒为单位给出结果(而是以秒或其他单位):

这里是我用来获得MS(毫秒):

迅速:

let startTime = NSDate().timeIntervalSince1970 * 1000

// your Swift code

let endTimeMinusStartTime = NSDate().timeIntervalSince1970 * 1000 - startTime
print("time code execution \(endTimeMinStartTime) ms")

objective - c:

double startTime = [[NSDate date] timeIntervalSince1970] * 1000.0;

// your Objective-C code

double endTimeMinusStartTime = [[NSDate date] timeIntervalSince1970] * 1000.0 - startTime;
printf("time code execution %f ms\n", endTimeMinusStartTime );