是否有一种方法可以确定一个方法需要执行多少时间(以毫秒为单位)?
当前回答
在Swift中,我使用:
在我的Macros.swift中,我刚刚添加了
var startTime = NSDate()
func TICK(){ startTime = NSDate() }
func TOCK(function: String = __FUNCTION__, file: String = __FILE__, line: Int = __LINE__){
println("\(function) Time: \(startTime.timeIntervalSinceNow)\nLine:\(line) File: \(file)")
}
你现在可以在任何地方打电话
TICK()
// your code to be tracked
TOCK()
斯威夫特5.0
var startTime = NSDate()
func TICK(){ startTime = NSDate() }
func TOCK(function: String = #function, file: String = #file, line: Int = #line){
print("\(function) Time: \(startTime.timeIntervalSinceNow)\nLine:\(line) File: \(file)")
}
这段代码是基于Ron的代码翻译成Swift的,他有功劳 我在全球范围内使用开始日期,任何改进建议都是欢迎的
其他回答
一个在Swift 4中使用mach_absolute_time()的细粒度计时的例子:
let start = mach_absolute_time()
// do something
let elapsedMTU = mach_absolute_time() - start
var timebase = mach_timebase_info()
if mach_timebase_info(&timebase) == 0 {
let elapsed = Double(elapsedMTU) * Double(timebase.numer) / Double(timebase.denom)
print("render took \(elapsed)")
}
else {
print("timebase error")
}
我使用非常少的,一页的类实现,灵感来自这篇博客文章的代码:
#import <mach/mach_time.h>
@interface DBGStopwatch : NSObject
+ (void)start:(NSString *)name;
+ (void)stop:(NSString *)name;
@end
@implementation DBGStopwatch
+ (NSMutableDictionary *)watches {
static NSMutableDictionary *Watches = nil;
static dispatch_once_t OnceToken;
dispatch_once(&OnceToken, ^{
Watches = @{}.mutableCopy;
});
return Watches;
}
+ (double)secondsFromMachTime:(uint64_t)time {
mach_timebase_info_data_t timebase;
mach_timebase_info(&timebase);
return (double)time * (double)timebase.numer /
(double)timebase.denom / 1e9;
}
+ (void)start:(NSString *)name {
uint64_t begin = mach_absolute_time();
self.watches[name] = @(begin);
}
+ (void)stop:(NSString *)name {
uint64_t end = mach_absolute_time();
uint64_t begin = [self.watches[name] unsignedLongLongValue];
DDLogInfo(@"Time taken for %@ %g s",
name, [self secondsFromMachTime:(end - begin)]);
[self.watches removeObjectForKey:name];
}
@end
它的用法很简单:
调用[DBGStopwatch start:@"slow-operation"];一开始 然后[DBGStopwatch stop:@"slow-operation"];做完之后,才能得到时间
下面是我使用的两个单行宏:
#define TICK NSDate *startTime = [NSDate date]
#define TOCK NSLog(@"Time: %f", -[startTime timeIntervalSinceNow])
像这样使用它:
TICK;
/* ... Do Some Work Here ... */
TOCK;
struct TIME {
static var ti = mach_timebase_info()
static var k: Double = 1
static var mach_stamp: Double {
if ti.denom == 0 {
mach_timebase_info(&ti)
k = Double(ti.numer) / Double(ti.denom) * 1e-6
}
return Double(mach_absolute_time()) * k
}
static var stamp: Double { return NSDate.timeIntervalSinceReferenceDate() * 1000 }
}
do {
let mach_start = TIME.mach_stamp
usleep(200000)
let mach_diff = TIME.mach_stamp - mach_start
let start = TIME.stamp
usleep(200000)
let diff = TIME.stamp - start
print(mach_diff, diff)
}
对于Swift 4,添加一个委托到你的类:
public protocol TimingDelegate: class {
var _TICK: Date?{ get set }
}
extension TimingDelegate {
var TICK: Date {
_TICK = Date()
return(_TICK)!
}
func TOCK(message: String) {
if (_TICK == nil){
print("Call 'TICK' first!")
}
if (message == ""){
print("\(Date().timeIntervalSince(_TICK!))")
}
else{
print("\(message): \(Date().timeIntervalSince(_TICK!))")
}
}
}
加入我们班:
class MyViewcontroller: UIViewController, TimingDelegate
然后添加到你的类:
var _TICK: Date?
当你想为某事计时时,可以从以下开始:
TICK
最后:
TOCK("Timing the XXX routine")
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