是否有一种方法可以确定一个方法需要执行多少时间(以毫秒为单位)?


当前回答

这里有另一种方法,在Swift中,使用defer关键字来做到这一点

func methodName() {
  let methodStart = Date()
  defer {
    let executionTime = Date().timeIntervalSince(methodStart)
    print("Execution time: \(executionTime)")
  }
  // do your stuff here
}

来自苹果的文档:defer语句用于在将程序控制权转移到该defer语句出现的范围之外之前执行代码。

这类似于try/finally块,优点是将相关代码分组。

其他回答

NSDate *methodStart = [NSDate date];

/* ... Do whatever you need to do ... */

NSDate *methodFinish = [NSDate date];
NSTimeInterval executionTime = [methodFinish timeIntervalSinceDate:methodStart];
NSLog(@"executionTime = %f", executionTime);

迅速:

let methodStart = NSDate()

/* ... Do whatever you need to do ... */

let methodFinish = NSDate()
let executionTime = methodFinish.timeIntervalSinceDate(methodStart)
print("Execution time: \(executionTime)")

Swift3:

let methodStart = Date()

/* ... Do whatever you need to do ... */

let methodFinish = Date()
let executionTime = methodFinish.timeIntervalSince(methodStart)
print("Execution time: \(executionTime)")

易于使用,具有亚毫秒精度。

下面是我使用的两个单行宏:

#define TICK   NSDate *startTime = [NSDate date]
#define TOCK   NSLog(@"Time: %f", -[startTime timeIntervalSinceNow])

像这样使用它:

TICK;

/* ... Do Some Work Here ... */

TOCK;
struct TIME {

    static var ti = mach_timebase_info()
    static var k: Double = 1
    static var mach_stamp: Double {

        if ti.denom == 0 {
            mach_timebase_info(&ti)
            k = Double(ti.numer) / Double(ti.denom) * 1e-6
        }
        return Double(mach_absolute_time()) * k
    }
    static var stamp: Double { return NSDate.timeIntervalSinceReferenceDate() * 1000 }
}

do {
    let mach_start = TIME.mach_stamp
    usleep(200000)
    let mach_diff = TIME.mach_stamp - mach_start

    let start = TIME.stamp
    usleep(200000)
    let diff = TIME.stamp - start

    print(mach_diff, diff)
}

对于Swift 4,添加一个委托到你的类:

public protocol TimingDelegate: class {
    var _TICK: Date?{ get set }
}

extension TimingDelegate {
    var TICK: Date {
        _TICK = Date()
        return(_TICK)!
     }

    func TOCK(message: String)  {

        if (_TICK == nil){
            print("Call 'TICK' first!")
        }

        if (message == ""){
            print("\(Date().timeIntervalSince(_TICK!))")
        }
        else{
            print("\(message): \(Date().timeIntervalSince(_TICK!))")
        }
    }
}

加入我们班:

class MyViewcontroller: UIViewController, TimingDelegate

然后添加到你的类:

var _TICK: Date?

当你想为某事计时时,可以从以下开始:

TICK

最后:

TOCK("Timing the XXX routine")

我用这个:

clock_t start, end;
double elapsed;
start = clock();

//Start code to time

//End code to time

end = clock();
elapsed = ((double) (end - start)) / CLOCKS_PER_SEC;
NSLog(@"Time: %f",elapsed);

但我不确定iPhone上的CLOCKS_PER_SEC。你还是别打了吧。