是否有一种方法可以确定一个方法需要执行多少时间(以毫秒为单位)?
当前回答
下面是我使用的两个单行宏:
#define TICK NSDate *startTime = [NSDate date]
#define TOCK NSLog(@"Time: %f", -[startTime timeIntervalSinceNow])
像这样使用它:
TICK;
/* ... Do Some Work Here ... */
TOCK;
其他回答
一个在Swift 4中使用mach_absolute_time()的细粒度计时的例子:
let start = mach_absolute_time()
// do something
let elapsedMTU = mach_absolute_time() - start
var timebase = mach_timebase_info()
if mach_timebase_info(&timebase) == 0 {
let elapsed = Double(elapsedMTU) * Double(timebase.numer) / Double(timebase.denom)
print("render took \(elapsed)")
}
else {
print("timebase error")
}
这里有一个Swift 3的解决方案,可以在任何地方对代码进行等分,以找到长时间运行的进程。
var increment: Int = 0
var incrementTime = NSDate()
struct Instrumentation {
var title: String
var point: Int
var elapsedTime: Double
init(_ title: String, _ point: Int, _ elapsedTime: Double) {
self.title = title
self.point = point
self.elapsedTime = elapsedTime
}
}
var elapsedTimes = [Instrumentation]()
func instrument(_ title: String) {
increment += 1
let incrementedTime = -incrementTime.timeIntervalSinceNow
let newPoint = Instrumentation(title, increment, incrementedTime)
elapsedTimes.append(newPoint)
incrementTime = NSDate()
}
用法:-
instrument("View Did Appear")
print("ELAPSED TIMES \(elapsedTimes)")
样例输出:
[MyApp.SomeViewController.]仪器仪表(标题:“开始视图 Did Load", point: 1, elapsedTime: 0.040504038333892822), MyApp.SomeViewController。检测(标题:“完成添加 SubViews", point: 2, elapsedTime: 0.010585010051727295), MyApp.SomeViewController。仪器仪表(标题:“视图已出现”, 点:3,elapsedTime: 0.56564098596572876)]
对于OS X上的细粒度计时,您应该使用在<mach/mach_time.h>中声明的mach_absolute_time():
#include <mach/mach_time.h>
#include <stdint.h>
// Do some stuff to setup for timing
const uint64_t startTime = mach_absolute_time();
// Do some stuff that you want to time
const uint64_t endTime = mach_absolute_time();
// Time elapsed in Mach time units.
const uint64_t elapsedMTU = endTime - startTime;
// Get information for converting from MTU to nanoseconds
mach_timebase_info_data_t info;
if (mach_timebase_info(&info))
handleErrorConditionIfYoureBeingCareful();
// Get elapsed time in nanoseconds:
const double elapsedNS = (double)elapsedMTU * (double)info.numer / (double)info.denom;
当然,关于细粒度度量的通常警告也适用;您可能最好多次调用测试中的例程,并求平均值/取最小值/一些其他形式的处理。
此外,请注意,您可能会发现使用Shark等工具对应用程序运行进行概要分析更有用。这不会为您提供确切的时间信息,但它会告诉您应用程序的时间在哪里花费了多少百分比,这通常更有用(但并不总是如此)。
我使用这个代码:
#import <mach/mach_time.h>
float TIME_BLOCK(NSString *key, void (^block)(void)) {
mach_timebase_info_data_t info;
if (mach_timebase_info(&info) != KERN_SUCCESS)
{
return -1.0;
}
uint64_t start = mach_absolute_time();
block();
uint64_t end = mach_absolute_time();
uint64_t elapsed = end - start;
uint64_t nanos = elapsed * info.numer / info.denom;
float cost = (float)nanos / NSEC_PER_SEC;
NSLog(@"key: %@ (%f ms)\n", key, cost * 1000);
return cost;
}
NSDate *methodStart = [NSDate date];
/* ... Do whatever you need to do ... */
NSDate *methodFinish = [NSDate date];
NSTimeInterval executionTime = [methodFinish timeIntervalSinceDate:methodStart];
NSLog(@"executionTime = %f", executionTime);
迅速:
let methodStart = NSDate()
/* ... Do whatever you need to do ... */
let methodFinish = NSDate()
let executionTime = methodFinish.timeIntervalSinceDate(methodStart)
print("Execution time: \(executionTime)")
Swift3:
let methodStart = Date()
/* ... Do whatever you need to do ... */
let methodFinish = Date()
let executionTime = methodFinish.timeIntervalSince(methodStart)
print("Execution time: \(executionTime)")
易于使用,具有亚毫秒精度。
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