是否有一种方法可以确定一个方法需要执行多少时间(以毫秒为单位)?


当前回答

我用这个:

clock_t start, end;
double elapsed;
start = clock();

//Start code to time

//End code to time

end = clock();
elapsed = ((double) (end - start)) / CLOCKS_PER_SEC;
NSLog(@"Time: %f",elapsed);

但我不确定iPhone上的CLOCKS_PER_SEC。你还是别打了吧。

其他回答

我使用这个代码:

#import <mach/mach_time.h>

float TIME_BLOCK(NSString *key, void (^block)(void)) {
    mach_timebase_info_data_t info;
    if (mach_timebase_info(&info) != KERN_SUCCESS)
    {
        return -1.0;
    }

    uint64_t start = mach_absolute_time();
    block();
    uint64_t end = mach_absolute_time();
    uint64_t elapsed = end - start;

    uint64_t nanos = elapsed * info.numer / info.denom;
    float cost = (float)nanos / NSEC_PER_SEC;

    NSLog(@"key: %@ (%f ms)\n", key, cost * 1000);
    return cost;
}

一个在Swift 4中使用mach_absolute_time()的细粒度计时的例子:

let start = mach_absolute_time()

// do something

let elapsedMTU = mach_absolute_time() - start
var timebase = mach_timebase_info()
if mach_timebase_info(&timebase) == 0 {
    let elapsed = Double(elapsedMTU) * Double(timebase.numer) / Double(timebase.denom)
    print("render took \(elapsed)")
}
else {
    print("timebase error")
}
NSDate *methodStart = [NSDate date];

/* ... Do whatever you need to do ... */

NSDate *methodFinish = [NSDate date];
NSTimeInterval executionTime = [methodFinish timeIntervalSinceDate:methodStart];
NSLog(@"executionTime = %f", executionTime);

迅速:

let methodStart = NSDate()

/* ... Do whatever you need to do ... */

let methodFinish = NSDate()
let executionTime = methodFinish.timeIntervalSinceDate(methodStart)
print("Execution time: \(executionTime)")

Swift3:

let methodStart = Date()

/* ... Do whatever you need to do ... */

let methodFinish = Date()
let executionTime = methodFinish.timeIntervalSince(methodStart)
print("Execution time: \(executionTime)")

易于使用,具有亚毫秒精度。

对于OS X上的细粒度计时,您应该使用在<mach/mach_time.h>中声明的mach_absolute_time():

#include <mach/mach_time.h>
#include <stdint.h>

// Do some stuff to setup for timing
const uint64_t startTime = mach_absolute_time();
// Do some stuff that you want to time
const uint64_t endTime = mach_absolute_time();

// Time elapsed in Mach time units.
const uint64_t elapsedMTU = endTime - startTime;

// Get information for converting from MTU to nanoseconds
mach_timebase_info_data_t info;
if (mach_timebase_info(&info))
   handleErrorConditionIfYoureBeingCareful();

// Get elapsed time in nanoseconds:
const double elapsedNS = (double)elapsedMTU * (double)info.numer / (double)info.denom;

当然,关于细粒度度量的通常警告也适用;您可能最好多次调用测试中的例程,并求平均值/取最小值/一些其他形式的处理。

此外,请注意,您可能会发现使用Shark等工具对应用程序运行进行概要分析更有用。这不会为您提供确切的时间信息,但它会告诉您应用程序的时间在哪里花费了多少百分比,这通常更有用(但并不总是如此)。

我使用基于Ron的解决方案的宏。

#define TICK(XXX) NSDate *XXX = [NSDate date]
#define TOCK(XXX) NSLog(@"%s: %f", #XXX, -[XXX timeIntervalSinceNow])

对于代码行:

TICK(TIME1);
/// do job here
TOCK(TIME1);

我们将在控制台中看到如下内容:TIME1: 0.096618