如何在React.js中执行debounce ?

我想撤消handleOnChange。

我尝试debounce(这。handleOnChange, 200)但它不起作用。

function debounce(fn, delay) {
  var timer = null;
  return function() {
    var context = this,
      args = arguments;
    clearTimeout(timer);
    timer = setTimeout(function() {
      fn.apply(context, args);
    }, delay);
  };
}

var SearchBox = React.createClass({
  render: function() {
    return <input type="search" name="p" onChange={this.handleOnChange} />;
  },

  handleOnChange: function(event) {
    // make ajax call
  }
});

当前回答

我们需要将setter传递给debpublished方法:

以下是StackBlitz的一个例子:

import React from "react";
import debounce from "lodash/debounce";

export default function App() {
  const [state, setState] = React.useState({
    debouncedLog: ""
  });

  const debouncedLog = React.useCallback(
    debounce((setState, log) => {
      setState(prevState => ({
        ...prevState,
        debouncedLog: log
      }));
    }, 500),
    []
  );

  const onChange = React.useCallback(({ target: { value: log } }) => {
    debouncedLog(setState, log); // passing the setState along...
  }, []);
  return (
    <div>
      <input onChange={onChange} style={{ outline: "1px blue solid" }} />

      <pre>Debounced Value: {state.debouncedLog}</pre>
    </div>
  );
}

祝你好运…

其他回答

你试过吗?

function debounce(fn, delay) {
  var timer = null;
  return function() {
    var context = this,
      args = arguments;
    clearTimeout(timer);
    timer = setTimeout(function() {
      fn.apply(context, args);
    }, delay);
  };
}

var SearchBox = React.createClass({
  render: function() {
    return <input type="search" name="p" onChange={this.handleOnChange} />;
  },

  handleOnChange: function(event) {
    debounce(\\ Your handleChange code , 200);
  }
});

今天遇到了这个问题。使用setTimeout和clearTimeout解决。

我将给出一个你可以适应的例子:

import React, { Component } from 'react'

const DEBOUNCE_TIME = 500

class PlacesAutocomplete extends Component {
  debounceTimer = null;

  onChangeHandler = (event) => {
    // Clear the last registered timer for the function
    clearTimeout(this.debounceTimer);

    // Set a new timer
    this.debounceTimer = setTimeout(
      // Bind the callback function to pass the current input value as arg
      this.getSuggestions.bind(null, event.target.value), 
      DEBOUNCE_TIME
    )
  }

  // The function that is being debounced
  getSuggestions = (searchTerm) => {
    console.log(searchTerm)
  }

  render() {
    return (
      <input type="text" onChange={this.onChangeHandler} />
    )
  }
}

export default PlacesAutocomplete

你也可以在它自己的函数组件中重构它:

import React from 'react'

function DebouncedInput({ debounceTime, callback}) {
  let debounceTimer = null
  return (
    <input type="text" onChange={(event) => {
      clearTimeout(debounceTimer);

      debounceTimer = setTimeout(
        callback.bind(null, event.target.value), 
        debounceTime
      )
    }} />
  )
}

export default DebouncedInput

像这样使用它:

import React, { Component } from 'react'
import DebouncedInput from '../DebouncedInput';

class PlacesAutocomplete extends Component {
  debounceTimer = null;

  getSuggestions = (searchTerm) => {
    console.log(searchTerm)
  }

  render() {
    return (
      <DebouncedInput debounceTime={500} callback={this.getSuggestions} />
    )
  }
}

export default PlacesAutocomplete

与其在debounce()中包装handleOnChange,不如在debounce()中包装回调函数中的ajax调用,从而不破坏事件对象。就像这样:

handleOnChange: function (event) {
   debounce(
     $.ajax({})
  , 250);
}

使用ES6 CLASS和React 15.x。X & lodash.debounce 我在这里使用React的refs,因为事件在内部失去了这个绑定。

class UserInput extends React.Component { constructor(props) { super(props); this.state = { userInput: "" }; this.updateInput = _.debounce(this.updateInput, 500); } updateInput(userInput) { this.setState({ userInput }); //OrderActions.updateValue(userInput);//do some server stuff } render() { return ( <div> <p> User typed: { this.state.userInput } </p> <input ref = "userValue" onChange = {() => this.updateInput(this.refs.userValue.value) } type = "text" / > </div> ); } } ReactDOM.render( < UserInput / > , document.getElementById('root') ); <script src="https://cdn.jsdelivr.net/npm/lodash@4.17.5/lodash.min.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script> <div id="root"></div>

避免使用event.persist()——你想让React回收合成事件。我认为无论你使用类还是钩子,最干净的方法是将回调函数分成两部分:

没有deboundation的回调 只使用您需要的事件片段调用已撤销的函数(这样合成的事件就可以循环使用)

handleMouseOver = throttle(target => {
  console.log(target);
}, 1000);

onMouseOver = e => {
  this.handleMouseOver(e.target);
};

<div onMouseOver={this.onMouseOver} />

功能

const handleMouseOver = useRef(throttle(target => {
  console.log(target);
}, 1000));

function onMouseOver(e) {
  handleMouseOver.current(e.target);
}

<div onMouseOver={this.onMouseOver} />

注意,如果你的handleMouseOver函数从组件中使用状态,你应该使用usemo而不是useRef,并将它们作为依赖项传递,否则你将使用过时的数据(当然不适用于类)。