如何在React.js中执行debounce ?
我想撤消handleOnChange。
我尝试debounce(这。handleOnChange, 200)但它不起作用。
function debounce(fn, delay) {
var timer = null;
return function() {
var context = this,
args = arguments;
clearTimeout(timer);
timer = setTimeout(function() {
fn.apply(context, args);
}, delay);
};
}
var SearchBox = React.createClass({
render: function() {
return <input type="search" name="p" onChange={this.handleOnChange} />;
},
handleOnChange: function(event) {
// make ajax call
}
});
我们需要将setter传递给debpublished方法:
以下是StackBlitz的一个例子:
import React from "react";
import debounce from "lodash/debounce";
export default function App() {
const [state, setState] = React.useState({
debouncedLog: ""
});
const debouncedLog = React.useCallback(
debounce((setState, log) => {
setState(prevState => ({
...prevState,
debouncedLog: log
}));
}, 500),
[]
);
const onChange = React.useCallback(({ target: { value: log } }) => {
debouncedLog(setState, log); // passing the setState along...
}, []);
return (
<div>
<input onChange={onChange} style={{ outline: "1px blue solid" }} />
<pre>Debounced Value: {state.debouncedLog}</pre>
</div>
);
}
祝你好运…
你试过吗?
function debounce(fn, delay) {
var timer = null;
return function() {
var context = this,
args = arguments;
clearTimeout(timer);
timer = setTimeout(function() {
fn.apply(context, args);
}, delay);
};
}
var SearchBox = React.createClass({
render: function() {
return <input type="search" name="p" onChange={this.handleOnChange} />;
},
handleOnChange: function(event) {
debounce(\\ Your handleChange code , 200);
}
});
今天遇到了这个问题。使用setTimeout和clearTimeout解决。
我将给出一个你可以适应的例子:
import React, { Component } from 'react'
const DEBOUNCE_TIME = 500
class PlacesAutocomplete extends Component {
debounceTimer = null;
onChangeHandler = (event) => {
// Clear the last registered timer for the function
clearTimeout(this.debounceTimer);
// Set a new timer
this.debounceTimer = setTimeout(
// Bind the callback function to pass the current input value as arg
this.getSuggestions.bind(null, event.target.value),
DEBOUNCE_TIME
)
}
// The function that is being debounced
getSuggestions = (searchTerm) => {
console.log(searchTerm)
}
render() {
return (
<input type="text" onChange={this.onChangeHandler} />
)
}
}
export default PlacesAutocomplete
你也可以在它自己的函数组件中重构它:
import React from 'react'
function DebouncedInput({ debounceTime, callback}) {
let debounceTimer = null
return (
<input type="text" onChange={(event) => {
clearTimeout(debounceTimer);
debounceTimer = setTimeout(
callback.bind(null, event.target.value),
debounceTime
)
}} />
)
}
export default DebouncedInput
像这样使用它:
import React, { Component } from 'react'
import DebouncedInput from '../DebouncedInput';
class PlacesAutocomplete extends Component {
debounceTimer = null;
getSuggestions = (searchTerm) => {
console.log(searchTerm)
}
render() {
return (
<DebouncedInput debounceTime={500} callback={this.getSuggestions} />
)
}
}
export default PlacesAutocomplete
避免使用event.persist()——你想让React回收合成事件。我认为无论你使用类还是钩子,最干净的方法是将回调函数分成两部分:
没有deboundation的回调
只使用您需要的事件片段调用已撤销的函数(这样合成的事件就可以循环使用)
类
handleMouseOver = throttle(target => {
console.log(target);
}, 1000);
onMouseOver = e => {
this.handleMouseOver(e.target);
};
<div onMouseOver={this.onMouseOver} />
功能
const handleMouseOver = useRef(throttle(target => {
console.log(target);
}, 1000));
function onMouseOver(e) {
handleMouseOver.current(e.target);
}
<div onMouseOver={this.onMouseOver} />
注意,如果你的handleMouseOver函数从组件中使用状态,你应该使用usemo而不是useRef,并将它们作为依赖项传递,否则你将使用过时的数据(当然不适用于类)。