如何在React.js中执行debounce ?
我想撤消handleOnChange。
我尝试debounce(这。handleOnChange, 200)但它不起作用。
function debounce(fn, delay) {
var timer = null;
return function() {
var context = this,
args = arguments;
clearTimeout(timer);
timer = setTimeout(function() {
fn.apply(context, args);
}, delay);
};
}
var SearchBox = React.createClass({
render: function() {
return <input type="search" name="p" onChange={this.handleOnChange} />;
},
handleOnChange: function(event) {
// make ajax call
}
});
使用React Hooks和响应式编程(RxJS)的React ajax debounce和cancel示例解决方案:
import React, { useEffect, useState } from "react";
import { ajax } from "rxjs/ajax";
import { debounceTime, delay, takeUntil } from "rxjs/operators";
import { Subject } from "rxjs/internal/Subject";
const App = () => {
const [items, setItems] = useState([]);
const [loading, setLoading] = useState(true);
const [filterChangedSubject] = useState(() => {
// Arrow function is used to init Singleton Subject. (in a scope of a current component)
return new Subject<string>();
});
useEffect(() => {
// Effect that will be initialized once on a react component init.
const subscription = filterChangedSubject
.pipe(debounceTime(200))
.subscribe((filter) => {
if (!filter) {
setLoading(false);
setItems([]);
return;
}
ajax(`https://swapi.dev/api/people?search=${filter}`)
.pipe(
// current running ajax is canceled on filter change.
takeUntil(filterChangedSubject)
)
.subscribe(
(results) => {
// Set items will cause render:
setItems(results.response.results);
},
() => {
setLoading(false);
},
() => {
setLoading(false);
}
);
});
return () => {
// On Component destroy. notify takeUntil to unsubscribe from current running ajax request
filterChangedSubject.next("");
// unsubscribe filter change listener
subscription.unsubscribe();
};
}, []);
const onFilterChange = (e) => {
// Notify subject about the filter change
filterChangedSubject.next(e.target.value);
};
return (
<div>
Cards
{loading && <div>Loading...</div>}
<input onChange={onFilterChange}></input>
{items && items.map((item, index) => <div key={index}>{item.name}</div>)}
</div>
);
};
export default App;
你也可以使用自己编写的mixin,就像这样:
var DebounceMixin = {
debounce: function(func, time, immediate) {
var timeout = this.debouncedTimeout;
if (!timeout) {
if (immediate) func();
this.debouncedTimeout = setTimeout(function() {
if (!immediate) func();
this.debouncedTimeout = void 0;
}.bind(this), time);
}
}
};
然后像这样在你的组件中使用它:
var MyComponent = React.createClass({
mixins: [DebounceMixin],
handleClick: function(e) {
this.debounce(function() {
this.setState({
buttonClicked: true
});
}.bind(this), 500, true);
},
render: function() {
return (
<button onClick={this.handleClick}></button>
);
}
});
有点晚了,但应该有帮助。
创建这个类(它是用typescript写的,但是很容易转换成javascript)
export class debouncedMethod<T>{
constructor(method:T, debounceTime:number){
this._method = method;
this._debounceTime = debounceTime;
}
private _method:T;
private _timeout:number;
private _debounceTime:number;
public invoke:T = ((...args:any[])=>{
this._timeout && window.clearTimeout(this._timeout);
this._timeout = window.setTimeout(()=>{
(this._method as any)(...args);
},this._debounceTime);
}) as any;
}
要使用
var foo = new debouncedMethod((name,age)=>{
console.log(name,age);
},500);
foo.invoke("john",31);
避免使用event.persist()——你想让React回收合成事件。我认为无论你使用类还是钩子,最干净的方法是将回调函数分成两部分:
没有deboundation的回调
只使用您需要的事件片段调用已撤销的函数(这样合成的事件就可以循环使用)
类
handleMouseOver = throttle(target => {
console.log(target);
}, 1000);
onMouseOver = e => {
this.handleMouseOver(e.target);
};
<div onMouseOver={this.onMouseOver} />
功能
const handleMouseOver = useRef(throttle(target => {
console.log(target);
}, 1000));
function onMouseOver(e) {
handleMouseOver.current(e.target);
}
<div onMouseOver={this.onMouseOver} />
注意,如果你的handleMouseOver函数从组件中使用状态,你应该使用usemo而不是useRef,并将它们作为依赖项传递,否则你将使用过时的数据(当然不适用于类)。