如何在React.js中执行debounce ?

我想撤消handleOnChange。

我尝试debounce(这。handleOnChange, 200)但它不起作用。

function debounce(fn, delay) {
  var timer = null;
  return function() {
    var context = this,
      args = arguments;
    clearTimeout(timer);
    timer = setTimeout(function() {
      fn.apply(context, args);
    }, delay);
  };
}

var SearchBox = React.createClass({
  render: function() {
    return <input type="search" name="p" onChange={this.handleOnChange} />;
  },

  handleOnChange: function(event) {
    // make ajax call
  }
});

当前回答

只是最近react和lodash的另一个变体。

class Filter extends Component {
  static propTypes = {
    text: PropTypes.string.isRequired,
    onChange: PropTypes.func.isRequired
  }

  state = {
    initialText: '',
    text: ''
  }

  constructor (props) {
    super(props)

    this.setText = this.setText.bind(this)
    this.onChange = _.fp.debounce(500)(this.onChange.bind(this))
  }

  static getDerivedStateFromProps (nextProps, prevState) {
    const { text } = nextProps

    if (text !== prevState.initialText) {
      return { initialText: text, text }
    }

    return null
  }

  setText (text) {
    this.setState({ text })
    this.onChange(text)
  }

  onChange (text) {
    this.props.onChange(text)
  }

  render () {
    return (<input value={this.state.text} onChange={(event) => this.setText(event.target.value)} />)
  }
}

其他回答

使用React Hooks和响应式编程(RxJS)的React ajax debounce和cancel示例解决方案:

import React, { useEffect, useState } from "react";
import { ajax } from "rxjs/ajax";
import { debounceTime, delay, takeUntil } from "rxjs/operators";
import { Subject } from "rxjs/internal/Subject";

const App = () => {
  const [items, setItems] = useState([]);
  const [loading, setLoading] = useState(true);
  const [filterChangedSubject] = useState(() => {
    // Arrow function is used to init Singleton Subject. (in a scope of a current component)
    return new Subject<string>();
  });

  useEffect(() => {
    // Effect that will be initialized once on a react component init.
    const subscription = filterChangedSubject
      .pipe(debounceTime(200))
      .subscribe((filter) => {
        if (!filter) {
          setLoading(false);
          setItems([]);
          return;
        }
        ajax(`https://swapi.dev/api/people?search=${filter}`)
          .pipe(
            // current running ajax is canceled on filter change.
            takeUntil(filterChangedSubject)
          )
          .subscribe(
            (results) => {
              // Set items will cause render:
              setItems(results.response.results);
            },
            () => {
              setLoading(false);
            },
            () => {
              setLoading(false);
            }
          );
      });

    return () => {
      // On Component destroy. notify takeUntil to unsubscribe from current running ajax request
      filterChangedSubject.next("");
      // unsubscribe filter change listener
      subscription.unsubscribe();
    };
  }, []);

  const onFilterChange = (e) => {
    // Notify subject about the filter change
    filterChangedSubject.next(e.target.value);
  };
  return (
    <div>
      Cards
      {loading && <div>Loading...</div>}
      <input onChange={onFilterChange}></input>
      {items && items.map((item, index) => <div key={index}>{item.name}</div>)}
    </div>
  );
};

export default App;

与其在debounce()中包装handleOnChange,不如在debounce()中包装回调函数中的ajax调用,从而不破坏事件对象。就像这样:

handleOnChange: function (event) {
   debounce(
     $.ajax({})
  , 250);
}

你也可以使用自己编写的mixin,就像这样:

var DebounceMixin = {
  debounce: function(func, time, immediate) {
    var timeout = this.debouncedTimeout;
    if (!timeout) {
      if (immediate) func();
      this.debouncedTimeout = setTimeout(function() {
        if (!immediate) func();
        this.debouncedTimeout = void 0;
      }.bind(this), time);
    }
  }
};

然后像这样在你的组件中使用它:

var MyComponent = React.createClass({
  mixins: [DebounceMixin],
  handleClick: function(e) {
    this.debounce(function() {
      this.setState({
        buttonClicked: true
      });
    }.bind(this), 500, true);
  },
  render: function() {
    return (
      <button onClick={this.handleClick}></button>
    );
  }
});

有点晚了,但应该有帮助。 创建这个类(它是用typescript写的,但是很容易转换成javascript)

export class debouncedMethod<T>{
  constructor(method:T, debounceTime:number){
    this._method = method;
    this._debounceTime = debounceTime;
  }
  private _method:T;
  private _timeout:number;
  private _debounceTime:number;
  public invoke:T = ((...args:any[])=>{
    this._timeout && window.clearTimeout(this._timeout);
    this._timeout = window.setTimeout(()=>{
      (this._method as any)(...args);
    },this._debounceTime);
  }) as any;
}

要使用

var foo = new debouncedMethod((name,age)=>{
 console.log(name,age);
},500);
foo.invoke("john",31);

避免使用event.persist()——你想让React回收合成事件。我认为无论你使用类还是钩子,最干净的方法是将回调函数分成两部分:

没有deboundation的回调 只使用您需要的事件片段调用已撤销的函数(这样合成的事件就可以循环使用)

handleMouseOver = throttle(target => {
  console.log(target);
}, 1000);

onMouseOver = e => {
  this.handleMouseOver(e.target);
};

<div onMouseOver={this.onMouseOver} />

功能

const handleMouseOver = useRef(throttle(target => {
  console.log(target);
}, 1000));

function onMouseOver(e) {
  handleMouseOver.current(e.target);
}

<div onMouseOver={this.onMouseOver} />

注意,如果你的handleMouseOver函数从组件中使用状态,你应该使用usemo而不是useRef,并将它们作为依赖项传递,否则你将使用过时的数据(当然不适用于类)。