有很多MD5 JavaScript实现。 有人知道哪一个是最先进的，修复最多的，最快的吗?
我需要它来做这个工具。
我听说Joseph的Myers实现非常快。此外，他还有一篇关于Javascript优化的长篇文章，描述了他在编写实现时学到的东西。对于任何对性能javascript感兴趣的人来说，这是一本很好的读物。
http://www.webreference.com/programming/javascript/jkm3/
他的MD5实现可以在这里找到
我找到了许多关于这个主题的文章。 他们都建议约瑟夫·迈耶斯实施。
在某些测试中，请参阅:http://jsperf.com/md5-shootout
在我对终极速度的追求中，我看了这段代码，我看到它可以改进。所以我基于Joseph Meyers代码创建了一个新的JS脚本。
参见改进的约瑟夫迈耶斯代码
在这种情况下，我建议您使用CryptoJS。
基本上，CryptoJS是一个使用最佳实践和模式在JavaScript中实现的标准和安全加密算法的不断增长的集合。它们速度快，界面一致且简单。
因此，如果你想计算密码字符串的MD5哈希值，那么按照以下步骤进行:
<script src="https://cdnjs.cloudflare.com/ajax/libs/crypto-js/3.1.9-1/core.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/crypto-js/3.1.9-1/md5.js"></script>
<script>
var passhash = CryptoJS.MD5(password).toString();
$.post(
'includes/login.php',
{ user: username, pass: passhash },
onLogin,
'json' );
</script>
因此，这个脚本将把密码字符串的散列发布到服务器。
有关其他哈希计算算法的进一步信息和支持，您可以访问:
http://code.google.com/p/crypto-js/
我只需要支持支持类型化数组(DataView, ArrayBuffer等)的HTML5浏览器。 我认为我采取了约瑟夫迈尔斯代码，并修改它，以支持传递在Uint8Array。我没有捕捉到所有的改进，仍然可能有一些char()数组构件可以改进。我需要它来添加到PouchDB项目。
var PouchUtils = {};
PouchUtils.Crypto = {};
(function () {
PouchUtils.Crypto.MD5 = function (uint8Array) {
function md5cycle(x, k) {
var a = x[0], b = x[1], c = x[2], d = x[3];
a = ff(a, b, c, d, k[0], 7, -680876936);
d = ff(d, a, b, c, k[1], 12, -389564586);
c = ff(c, d, a, b, k[2], 17, 606105819);
b = ff(b, c, d, a, k[3], 22, -1044525330);
a = ff(a, b, c, d, k[4], 7, -176418897);
d = ff(d, a, b, c, k[5], 12, 1200080426);
c = ff(c, d, a, b, k[6], 17, -1473231341);
b = ff(b, c, d, a, k[7], 22, -45705983);
a = ff(a, b, c, d, k[8], 7, 1770035416);
d = ff(d, a, b, c, k[9], 12, -1958414417);
c = ff(c, d, a, b, k[10], 17, -42063);
b = ff(b, c, d, a, k[11], 22, -1990404162);
a = ff(a, b, c, d, k[12], 7, 1804603682);
d = ff(d, a, b, c, k[13], 12, -40341101);
c = ff(c, d, a, b, k[14], 17, -1502002290);
b = ff(b, c, d, a, k[15], 22, 1236535329);
a = gg(a, b, c, d, k[1], 5, -165796510);
d = gg(d, a, b, c, k[6], 9, -1069501632);
c = gg(c, d, a, b, k[11], 14, 643717713);
b = gg(b, c, d, a, k[0], 20, -373897302);
a = gg(a, b, c, d, k[5], 5, -701558691);
d = gg(d, a, b, c, k[10], 9, 38016083);
c = gg(c, d, a, b, k[15], 14, -660478335);
b = gg(b, c, d, a, k[4], 20, -405537848);
a = gg(a, b, c, d, k[9], 5, 568446438);
d = gg(d, a, b, c, k[14], 9, -1019803690);
c = gg(c, d, a, b, k[3], 14, -187363961);
b = gg(b, c, d, a, k[8], 20, 1163531501);
a = gg(a, b, c, d, k[13], 5, -1444681467);
d = gg(d, a, b, c, k[2], 9, -51403784);
c = gg(c, d, a, b, k[7], 14, 1735328473);
b = gg(b, c, d, a, k[12], 20, -1926607734);
a = hh(a, b, c, d, k[5], 4, -378558);
d = hh(d, a, b, c, k[8], 11, -2022574463);
c = hh(c, d, a, b, k[11], 16, 1839030562);
b = hh(b, c, d, a, k[14], 23, -35309556);
a = hh(a, b, c, d, k[1], 4, -1530992060);
d = hh(d, a, b, c, k[4], 11, 1272893353);
c = hh(c, d, a, b, k[7], 16, -155497632);
b = hh(b, c, d, a, k[10], 23, -1094730640);
a = hh(a, b, c, d, k[13], 4, 681279174);
d = hh(d, a, b, c, k[0], 11, -358537222);
c = hh(c, d, a, b, k[3], 16, -722521979);
b = hh(b, c, d, a, k[6], 23, 76029189);
a = hh(a, b, c, d, k[9], 4, -640364487);
d = hh(d, a, b, c, k[12], 11, -421815835);
c = hh(c, d, a, b, k[15], 16, 530742520);
b = hh(b, c, d, a, k[2], 23, -995338651);
a = ii(a, b, c, d, k[0], 6, -198630844);
d = ii(d, a, b, c, k[7], 10, 1126891415);
c = ii(c, d, a, b, k[14], 15, -1416354905);
b = ii(b, c, d, a, k[5], 21, -57434055);
a = ii(a, b, c, d, k[12], 6, 1700485571);
d = ii(d, a, b, c, k[3], 10, -1894986606);
c = ii(c, d, a, b, k[10], 15, -1051523);
b = ii(b, c, d, a, k[1], 21, -2054922799);
a = ii(a, b, c, d, k[8], 6, 1873313359);
d = ii(d, a, b, c, k[15], 10, -30611744);
c = ii(c, d, a, b, k[6], 15, -1560198380);
b = ii(b, c, d, a, k[13], 21, 1309151649);
a = ii(a, b, c, d, k[4], 6, -145523070);
d = ii(d, a, b, c, k[11], 10, -1120210379);
c = ii(c, d, a, b, k[2], 15, 718787259);
b = ii(b, c, d, a, k[9], 21, -343485551);
x[0] = add32(a, x[0]);
x[1] = add32(b, x[1]);
x[2] = add32(c, x[2]);
x[3] = add32(d, x[3]);
}
function cmn(q, a, b, x, s, t) {
a = add32(add32(a, q), add32(x, t));
return add32((a << s) | (a >>> (32 - s)), b);
}
function ff(a, b, c, d, x, s, t) {
return cmn((b & c) | ((~b) & d), a, b, x, s, t);
}
function gg(a, b, c, d, x, s, t) {
return cmn((b & d) | (c & (~d)), a, b, x, s, t);
}
function hh(a, b, c, d, x, s, t) {
return cmn(b ^ c ^ d, a, b, x, s, t);
}
function ii(a, b, c, d, x, s, t) {
return cmn(c ^ (b | (~d)), a, b, x, s, t);
}
function md51(s) {
txt = '';
var n = s.length,
state = [1732584193, -271733879, -1732584194, 271733878], i;
for (i = 64; i <= s.length; i += 64) {
md5cycle(state, md5blk(s.subarray(i - 64, i)));
}
s = s.subarray(i - 64);
var tail = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0];
for (i = 0; i < s.length; i++)
tail[i >> 2] |= s[i] << ((i % 4) << 3);
tail[i >> 2] |= 0x80 << ((i % 4) << 3);
if (i > 55) {
md5cycle(state, tail);
for (i = 0; i < 16; i++) tail[i] = 0;
}
tail[14] = n * 8;
md5cycle(state, tail);
return state;
}
/* there needs to be support for Unicode here,
* unless we pretend that we can redefine the MD-5
* algorithm for multi-byte characters (perhaps
* by adding every four 16-bit characters and
* shortening the sum to 32 bits). Otherwise
* I suggest performing MD-5 as if every character
* was two bytes--e.g., 0040 0025 = @%--but then
* how will an ordinary MD-5 sum be matched?
* There is no way to standardize text to something
* like UTF-8 before transformation; speed cost is
* utterly prohibitive. The JavaScript standard
* itself needs to look at this: it should start
* providing access to strings as preformed UTF-8
* 8-bit unsigned value arrays.
*/
function md5blk(s) { /* I figured global was faster. */
var md5blks = [], i; /* Andy King said do it this way. */
for (i = 0; i < 64; i += 4) {
md5blks[i >> 2] = s[i]
+ (s[i + 1] << 8)
+ (s[i + 2] << 16)
+ (s[i + 3] << 24);
}
return md5blks;
}
var hex_chr = '0123456789abcdef'.split('');
function rhex(n) {
var s = '', j = 0;
for (; j < 4; j++)
s += hex_chr[(n >> (j * 8 + 4)) & 0x0F]
+ hex_chr[(n >> (j * 8)) & 0x0F];
return s;
}
function hex(x) {
for (var i = 0; i < x.length; i++)
x[i] = rhex(x[i]);
return x.join('');
}
function md5(s) {
return hex(md51(s));
}
function add32(a, b) {
return (a + b) & 0xFFFFFFFF;
}
return md5(uint8Array);
};
})();
在选择库时，也要看它是否支持现代框架(如Bower)，是否通过jslint，是否支持JQuery插件模型或模块系统(如AMD/RequireJS)，以及是否正在积极开发中，是否有超过1个贡献者。有几个选项可以满足这些附加条件的一部分或全部:
CryptoJS: This is perhaps the most expansive library where each algorithm can be used separately without adding fat in to your JS code. Plus it as encoder/decoders for UTF8, UTF16 and Base64. I maintain github repository that is registered as Bower package plus instructions on how to use it with RequireJS. Spark MD5: This is based on JKM code that other answer mentions which is also the faster implementation. However in addition, Spark implementation adds AMD support, passes jslint plus has incremental mode. It doesn't have Base64 o/p but it does have raw o/p (i.e. array of 32-bit int insead of string). JQuery MD5 plugin: Very simple down to earth but doesn't seem to have raw mode. JavaScript-MD5: Not as fancy or fast as Spark but simpler.
来自CryptoJS的例子:
//just include md5.js from the CryptoJS rollups folder
var hash = CryptoJS.MD5("Message");
console.log(hash.toString());
在http://jsperf.com/md5-shootout/7上有上述库之间的性能比较。在我的机器上，当前的测试(不可否认是旧的)表明，如果您正在寻找速度，Spark MD5是您的最佳选择(普通JKM代码也是如此)。然而，如果你正在寻找更全面的库，那么CryptoJS是你最好的选择，尽管它比Spark MD5慢79%。然而，我想CryptoJS最终会达到同样的速度，因为它是一个更活跃的项目。
令我烦恼的是，我找不到一个既快速又支持Unicode字符串的实现。
所以我做了一个支持Unicode字符串的实现，并且仍然比目前最快的ascii-only-strings实现更快(在编写时):
https://github.com/gorhill/yamd5.js
基于Joseph Myers的代码，但使用了TypedArrays，并进行了其他改进。
为什么不试试http://phpjs.org/functions/md5/?
不幸的是，任何模拟脚本的性能都是有限的，但是这可以呈现真正的md5散列。尽管我建议不要使用md5作为密码，因为它是一个快速呈现的散列。
目前最快的md5实现(基于Joseph Myers的代码):
https://github.com/iReal/FastMD5
jsPerf比较:http://jsperf.com/md5-shootout/63
更快的哈希应该可以通过在显卡上计算(在WebGL中实现哈希算法)，正如关于SHA256的讨论:是否有可能在浏览器中使用用户的视频卡来计算SHA256哈希值?使用WebGL还是Flash?
我编写了测试来比较几种JavaScript哈希实现，包括这里提到的大多数MD5实现。 要运行测试，请访问http://brillout.github.io/test-javascript-hash-implementations/并稍等片刻。
似乎R. Hill的答案的YaMD5实现是最快的。
我真的不记得我从哪里得到这个。我在网上到处找，唯一能找到的参考文献就是这篇文章。奇怪。 如果任何人有关于这个实现起源的信息，请告诉我。
或者你可以试试这个新的，速度快25%:https://stackoverflow.com/a/74186696/236062:D
MD5 = function(e) { function h(a, b) { var c, d, e, f, g; e = a & 2147483648; f = b & 2147483648; c = a & 1073741824; d = b & 1073741824; g = (a & 1073741823) + (b & 1073741823); return c & d ? g ^ 2147483648 ^ e ^ f : c | d ? g & 1073741824 ? g ^ 3221225472 ^ e ^ f : g ^ 1073741824 ^ e ^ f : g ^ e ^ f } function k(a, b, c, d, e, f, g) { a = h(a, h(h(b & c | ~b & d, e), g)); return h(a << f | a >>> 32 - f, b) } function l(a, b, c, d, e, f, g) { a = h(a, h(h(b & d | c & ~d, e), g)); return h(a << f | a >>> 32 - f, b) } function m(a, b, d, c, e, f, g) { a = h(a, h(h(b ^ d ^ c, e), g)); return h(a << f | a >>> 32 - f, b) } function n(a, b, d, c, e, f, g) { a = h(a, h(h(d ^ (b | ~c), e), g)); return h(a << f | a >>> 32 - f, b) } function p(a) { var b = "", d = "", c; for (c = 0; 3 >= c; c++) d = a >>> 8 * c & 255, d = "0" + d.toString(16), b += d.substr(d.length - 2, 2); return b } var f = [], q, r, s, t, a, b, c, d; e = function(a) { a = a.replace(/\r\n/g, "\n"); for (var b = "", d = 0; d < a.length; d++) { var c = a.charCodeAt(d); 128 > c ? b += String.fromCharCode(c) : (127 < c && 2048 > c ? b += String.fromCharCode(c >> 6 | 192) : (b += String.fromCharCode(c >> 12 | 224), b += String.fromCharCode(c >> 6 & 63 | 128)), b += String.fromCharCode(c & 63 | 128)) } return b }(e); f = function(b) { var a, c = b.length; a = c + 8; for (var d = 16 * ((a - a % 64) / 64 + 1), e = Array(d - 1), f = 0, g = 0; g < c;) a = (g - g % 4) / 4, f = g % 4 * 8, e[a] |= b.charCodeAt(g) << f, g++; a = (g - g % 4) / 4; e[a] |= 128 << g % 4 * 8; e[d - 2] = c << 3; e[d - 1] = c >>> 29; return e }(e); a = 1732584193; b = 4023233417; c = 2562383102; d = 271733878; for (e = 0; e < f.length; e += 16) q = a, r = b, s = c, t = d, a = k(a, b, c, d, f[e + 0], 7, 3614090360), d = k(d, a, b, c, f[e + 1], 12, 3905402710), c = k(c, d, a, b, f[e + 2], 17, 606105819), b = k(b, c, d, a, f[e + 3], 22, 3250441966), a = k(a, b, c, d, f[e + 4], 7, 4118548399), d = k(d, a, b, c, f[e + 5], 12, 1200080426), c = k(c, d, a, b, f[e + 6], 17, 2821735955), b = k(b, c, d, a, f[e + 7], 22, 4249261313), a = k(a, b, c, d, f[e + 8], 7, 1770035416), d = k(d, a, b, c, f[e + 9], 12, 2336552879), c = k(c, d, a, b, f[e + 10], 17, 4294925233), b = k(b, c, d, a, f[e + 11], 22, 2304563134), a = k(a, b, c, d, f[e + 12], 7, 1804603682), d = k(d, a, b, c, f[e + 13], 12, 4254626195), c = k(c, d, a, b, f[e + 14], 17, 2792965006), b = k(b, c, d, a, f[e + 15], 22, 1236535329), a = l(a, b, c, d, f[e + 1], 5, 4129170786), d = l(d, a, b, c, f[e + 6], 9, 3225465664), c = l(c, d, a, b, f[e + 11], 14, 643717713), b = l(b, c, d, a, f[e + 0], 20, 3921069994), a = l(a, b, c, d, f[e + 5], 5, 3593408605), d = l(d, a, b, c, f[e + 10], 9, 38016083), c = l(c, d, a, b, f[e + 15], 14, 3634488961), b = l(b, c, d, a, f[e + 4], 20, 3889429448), a = l(a, b, c, d, f[e + 9], 5, 568446438), d = l(d, a, b, c, f[e + 14], 9, 3275163606), c = l(c, d, a, b, f[e + 3], 14, 4107603335), b = l(b, c, d, a, f[e + 8], 20, 1163531501), a = l(a, b, c, d, f[e + 13], 5, 2850285829), d = l(d, a, b, c, f[e + 2], 9, 4243563512), c = l(c, d, a, b, f[e + 7], 14, 1735328473), b = l(b, c, d, a, f[e + 12], 20, 2368359562), a = m(a, b, c, d, f[e + 5], 4, 4294588738), d = m(d, a, b, c, f[e + 8], 11, 2272392833), c = m(c, d, a, b, f[e + 11], 16, 1839030562), b = m(b, c, d, a, f[e + 14], 23, 4259657740), a = m(a, b, c, d, f[e + 1], 4, 2763975236), d = m(d, a, b, c, f[e + 4], 11, 1272893353), c = m(c, d, a, b, f[e + 7], 16, 4139469664), b = m(b, c, d, a, f[e + 10], 23, 3200236656), a = m(a, b, c, d, f[e + 13], 4, 681279174), d = m(d, a, b, c, f[e + 0], 11, 3936430074), c = m(c, d, a, b, f[e + 3], 16, 3572445317), b = m(b, c, d, a, f[e + 6], 23, 76029189), a = m(a, b, c, d, f[e + 9], 4, 3654602809), d = m(d, a, b, c, f[e + 12], 11, 3873151461), c = m(c, d, a, b, f[e + 15], 16, 530742520), b = m(b, c, d, a, f[e + 2], 23, 3299628645), a = n(a, b, c, d, f[e + 0], 6, 4096336452), d = n(d, a, b, c, f[e + 7], 10, 1126891415), c = n(c, d, a, b, f[e + 14], 15, 2878612391), b = n(b, c, d, a, f[e + 5], 21, 4237533241), a = n(a, b, c, d, f[e + 12], 6, 1700485571), d = n(d, a, b, c, f[e + 3], 10, 2399980690), c = n(c, d, a, b, f[e + 10], 15, 4293915773), b = n(b, c, d, a, f[e + 1], 21, 2240044497), a = n(a, b, c, d, f[e + 8], 6, 1873313359), d = n(d, a, b, c, f[e + 15], 10, 4264355552), c = n(c, d, a, b, f[e + 6], 15, 2734768916), b = n(b, c, d, a, f[e + 13], 21, 1309151649), a = n(a, b, c, d, f[e + 4], 6, 4149444226), d = n(d, a, b, c, f[e + 11], 10, 3174756917), c = n(c, d, a, b, f[e + 2], 15, 718787259), b = n(b, c, d, a, f[e + 9], 21, 3951481745), a = h(a, q), b = h(b, r), c = h(c, s), d = h(d, t); return (p(a) + p(b) + p(c) + p(d)).toLowerCase() }; <!DOCTYPE html> <html> <body onload="md5.value=MD5(a.value);"> <form oninput="md5.value=MD5(a.value)">Enter String: <input type="string" id="a" name="a" value="https://www.zibri.org"></br></br>MD5:<output id="md5" name="md5" for="a"></output> </form> </body> </html>
也许这个包是有用的 https://www.npmjs.com/package/pure-md5
console.time（'latin'）; 常量拉丁语 = MD5（'你好'）; console.timeEnd（'latin'）; console.log（'Привет： '， md5（'Привет'））; console.log（'嘿： '， md5（'嘿'））; <script src=“https://unpkg.com/pure-md5@latest/lib/index.js”></script>
Node.js有内置的支持
const crypto = require('crypto')
crypto.createHash('md5').update('hello world').digest('hex')
上面的代码段为字符串hello world计算MD5十六进制字符串
这种解决方案的优点是不需要安装额外的库。
我认为内置解决方案应该是最快的。如果不是，我们应该为Node.js项目创建issue/PR。
我最喜欢的md5
这篇文章有42行长，横向可容纳120个字符，看起来不错。它快吗?好吧，它足够快了，它和所有其他JS实现差不多。但看着这些排列整齐的列，会有一种奇怪的满足感。不否认。
// A formatted version of a popular md5 implementation.
// Original copyright (c) Paul Johnston & Greg Holt.
// The function itself is now 42 lines long.
function md5(inputString) {
var hc="0123456789abcdef";
function rh(n) {var j,s="";for(j=0;j<=3;j++) s+=hc.charAt((n>>(j*8+4))&0x0F)+hc.charAt((n>>(j*8))&0x0F);return s;}
function ad(x,y) {var l=(x&0xFFFF)+(y&0xFFFF);var m=(x>>16)+(y>>16)+(l>>16);return (m<<16)|(l&0xFFFF);}
function rl(n,c) {return (n<<c)|(n>>>(32-c));}
function cm(q,a,b,x,s,t) {return ad(rl(ad(ad(a,q),ad(x,t)),s),b);}
function ff(a,b,c,d,x,s,t) {return cm((b&c)|((~b)&d),a,b,x,s,t);}
function gg(a,b,c,d,x,s,t) {return cm((b&d)|(c&(~d)),a,b,x,s,t);}
function hh(a,b,c,d,x,s,t) {return cm(b^c^d,a,b,x,s,t);}
function ii(a,b,c,d,x,s,t) {return cm(c^(b|(~d)),a,b,x,s,t);}
function sb(x) {
var i;var nblk=((x.length+8)>>6)+1;var blks=new Array(nblk*16);for(i=0;i<nblk*16;i++) blks[i]=0;
for(i=0;i<x.length;i++) blks[i>>2]|=x.charCodeAt(i)<<((i%4)*8);
blks[i>>2]|=0x80<<((i%4)*8);blks[nblk*16-2]=x.length*8;return blks;
}
var i,x=sb(inputString),a=1732584193,b=-271733879,c=-1732584194,d=271733878,olda,oldb,oldc,oldd;
for(i=0;i<x.length;i+=16) {olda=a;oldb=b;oldc=c;oldd=d;
a=ff(a,b,c,d,x[i+ 0], 7, -680876936);d=ff(d,a,b,c,x[i+ 1],12, -389564586);c=ff(c,d,a,b,x[i+ 2],17, 606105819);
b=ff(b,c,d,a,x[i+ 3],22,-1044525330);a=ff(a,b,c,d,x[i+ 4], 7, -176418897);d=ff(d,a,b,c,x[i+ 5],12, 1200080426);
c=ff(c,d,a,b,x[i+ 6],17,-1473231341);b=ff(b,c,d,a,x[i+ 7],22, -45705983);a=ff(a,b,c,d,x[i+ 8], 7, 1770035416);
d=ff(d,a,b,c,x[i+ 9],12,-1958414417);c=ff(c,d,a,b,x[i+10],17, -42063);b=ff(b,c,d,a,x[i+11],22,-1990404162);
a=ff(a,b,c,d,x[i+12], 7, 1804603682);d=ff(d,a,b,c,x[i+13],12, -40341101);c=ff(c,d,a,b,x[i+14],17,-1502002290);
b=ff(b,c,d,a,x[i+15],22, 1236535329);a=gg(a,b,c,d,x[i+ 1], 5, -165796510);d=gg(d,a,b,c,x[i+ 6], 9,-1069501632);
c=gg(c,d,a,b,x[i+11],14, 643717713);b=gg(b,c,d,a,x[i+ 0],20, -373897302);a=gg(a,b,c,d,x[i+ 5], 5, -701558691);
d=gg(d,a,b,c,x[i+10], 9, 38016083);c=gg(c,d,a,b,x[i+15],14, -660478335);b=gg(b,c,d,a,x[i+ 4],20, -405537848);
a=gg(a,b,c,d,x[i+ 9], 5, 568446438);d=gg(d,a,b,c,x[i+14], 9,-1019803690);c=gg(c,d,a,b,x[i+ 3],14, -187363961);
b=gg(b,c,d,a,x[i+ 8],20, 1163531501);a=gg(a,b,c,d,x[i+13], 5,-1444681467);d=gg(d,a,b,c,x[i+ 2], 9, -51403784);
c=gg(c,d,a,b,x[i+ 7],14, 1735328473);b=gg(b,c,d,a,x[i+12],20,-1926607734);a=hh(a,b,c,d,x[i+ 5], 4, -378558);
d=hh(d,a,b,c,x[i+ 8],11,-2022574463);c=hh(c,d,a,b,x[i+11],16, 1839030562);b=hh(b,c,d,a,x[i+14],23, -35309556);
a=hh(a,b,c,d,x[i+ 1], 4,-1530992060);d=hh(d,a,b,c,x[i+ 4],11, 1272893353);c=hh(c,d,a,b,x[i+ 7],16, -155497632);
b=hh(b,c,d,a,x[i+10],23,-1094730640);a=hh(a,b,c,d,x[i+13], 4, 681279174);d=hh(d,a,b,c,x[i+ 0],11, -358537222);
c=hh(c,d,a,b,x[i+ 3],16, -722521979);b=hh(b,c,d,a,x[i+ 6],23, 76029189);a=hh(a,b,c,d,x[i+ 9], 4, -640364487);
d=hh(d,a,b,c,x[i+12],11, -421815835);c=hh(c,d,a,b,x[i+15],16, 530742520);b=hh(b,c,d,a,x[i+ 2],23, -995338651);
a=ii(a,b,c,d,x[i+ 0], 6, -198630844);d=ii(d,a,b,c,x[i+ 7],10, 1126891415);c=ii(c,d,a,b,x[i+14],15,-1416354905);
b=ii(b,c,d,a,x[i+ 5],21, -57434055);a=ii(a,b,c,d,x[i+12], 6, 1700485571);d=ii(d,a,b,c,x[i+ 3],10,-1894986606);
c=ii(c,d,a,b,x[i+10],15, -1051523);b=ii(b,c,d,a,x[i+ 1],21,-2054922799);a=ii(a,b,c,d,x[i+ 8], 6, 1873313359);
d=ii(d,a,b,c,x[i+15],10, -30611744);c=ii(c,d,a,b,x[i+ 6],15,-1560198380);b=ii(b,c,d,a,x[i+13],21, 1309151649);
a=ii(a,b,c,d,x[i+ 4], 6, -145523070);d=ii(d,a,b,c,x[i+11],10,-1120210379);c=ii(c,d,a,b,x[i+ 2],15, 718787259);
b=ii(b,c,d,a,x[i+ 9],21, -343485551);a=ad(a,olda);b=ad(b,oldb);c=ad(c,oldc);d=ad(d,oldd);
}
return rh(a)+rh(b)+rh(c)+rh(d);
}
另一个完全无关的事实是:它有4000字节长。这似乎毫无意义，但知道就感觉很好。你看着它，你知道。你是秘密俱乐部的一员。生活将从此不同。相信我。
同时，感谢保罗·约翰斯顿和格雷格·霍尔特。 还有道格拉斯·亚当斯，所有的鱼。
Stackblitz试样
到2020年，最快的MD5实现可能是用WASM (Web Assembly)编写的。
hash- WASM是一个在WASM中实现MD5哈希的库。
您可以在这里找到基准测试。
你可以用npm安装它:
npm i hash-wasm
或者只是添加一个脚本标记
<script src="https://cdn.jsdelivr.net/npm/hash-wasm"></script>
然后使用hashwasm全局变量。
例子:
async function run() {
console.log('MD5:', await hashwasm.md5('The quick brown fox jumps over the lazy dog'));
}
run();
输出
MD5: 9e107d9d372bb6826bd81d3542a419d6
下面是@dkellner和@Eonasdan的md5实现的ES6版本:
const md5 = inputString => {
const hc = '0123456789abcdef';
const rh = n => {let j,s='';for(j=0;j<=3;j++) s+=hc.charAt((n>>(j*8+4))&0x0F)+hc.charAt((n>>(j*8))&0x0F);return s;}
const ad = (x,y) => {let l=(x&0xFFFF)+(y&0xFFFF);let m=(x>>16)+(y>>16)+(l>>16);return (m<<16)|(l&0xFFFF);}
const rl = (n,c) => (n<<c)|(n>>>(32-c));
const cm = (q,a,b,x,s,t) => ad(rl(ad(ad(a,q),ad(x,t)),s),b);
const ff = (a,b,c,d,x,s,t) => cm((b&c)|((~b)&d),a,b,x,s,t);
const gg = (a,b,c,d,x,s,t) => cm((b&d)|(c&(~d)),a,b,x,s,t);
const hh = (a,b,c,d,x,s,t) => cm(b^c^d,a,b,x,s,t);
const ii = (a,b,c,d,x,s,t) => cm(c^(b|(~d)),a,b,x,s,t);
const sb = x => {
let i;const nblk=((x.length+8)>>6)+1;const blks=[];for(i=0;i<nblk*16;i++) { blks[i]=0 };
for(i=0;i<x.length;i++) {blks[i>>2]|=x.charCodeAt(i)<<((i%4)*8);}
blks[i>>2]|=0x80<<((i%4)*8);blks[nblk*16-2]=x.length*8;return blks;
}
let i,x=sb(inputString),a=1732584193,b=-271733879,c=-1732584194,d=271733878,olda,oldb,oldc,oldd;
for(i=0;i<x.length;i+=16) {olda=a;oldb=b;oldc=c;oldd=d;
a=ff(a,b,c,d,x[i+ 0], 7, -680876936);d=ff(d,a,b,c,x[i+ 1],12, -389564586);c=ff(c,d,a,b,x[i+ 2],17, 606105819);
b=ff(b,c,d,a,x[i+ 3],22,-1044525330);a=ff(a,b,c,d,x[i+ 4], 7, -176418897);d=ff(d,a,b,c,x[i+ 5],12, 1200080426);
c=ff(c,d,a,b,x[i+ 6],17,-1473231341);b=ff(b,c,d,a,x[i+ 7],22, -45705983);a=ff(a,b,c,d,x[i+ 8], 7, 1770035416);
d=ff(d,a,b,c,x[i+ 9],12,-1958414417);c=ff(c,d,a,b,x[i+10],17, -42063);b=ff(b,c,d,a,x[i+11],22,-1990404162);
a=ff(a,b,c,d,x[i+12], 7, 1804603682);d=ff(d,a,b,c,x[i+13],12, -40341101);c=ff(c,d,a,b,x[i+14],17,-1502002290);
b=ff(b,c,d,a,x[i+15],22, 1236535329);a=gg(a,b,c,d,x[i+ 1], 5, -165796510);d=gg(d,a,b,c,x[i+ 6], 9,-1069501632);
c=gg(c,d,a,b,x[i+11],14, 643717713);b=gg(b,c,d,a,x[i+ 0],20, -373897302);a=gg(a,b,c,d,x[i+ 5], 5, -701558691);
d=gg(d,a,b,c,x[i+10], 9, 38016083);c=gg(c,d,a,b,x[i+15],14, -660478335);b=gg(b,c,d,a,x[i+ 4],20, -405537848);
a=gg(a,b,c,d,x[i+ 9], 5, 568446438);d=gg(d,a,b,c,x[i+14], 9,-1019803690);c=gg(c,d,a,b,x[i+ 3],14, -187363961);
b=gg(b,c,d,a,x[i+ 8],20, 1163531501);a=gg(a,b,c,d,x[i+13], 5,-1444681467);d=gg(d,a,b,c,x[i+ 2], 9, -51403784);
c=gg(c,d,a,b,x[i+ 7],14, 1735328473);b=gg(b,c,d,a,x[i+12],20,-1926607734);a=hh(a,b,c,d,x[i+ 5], 4, -378558);
d=hh(d,a,b,c,x[i+ 8],11,-2022574463);c=hh(c,d,a,b,x[i+11],16, 1839030562);b=hh(b,c,d,a,x[i+14],23, -35309556);
a=hh(a,b,c,d,x[i+ 1], 4,-1530992060);d=hh(d,a,b,c,x[i+ 4],11, 1272893353);c=hh(c,d,a,b,x[i+ 7],16, -155497632);
b=hh(b,c,d,a,x[i+10],23,-1094730640);a=hh(a,b,c,d,x[i+13], 4, 681279174);d=hh(d,a,b,c,x[i+ 0],11, -358537222);
c=hh(c,d,a,b,x[i+ 3],16, -722521979);b=hh(b,c,d,a,x[i+ 6],23, 76029189);a=hh(a,b,c,d,x[i+ 9], 4, -640364487);
d=hh(d,a,b,c,x[i+12],11, -421815835);c=hh(c,d,a,b,x[i+15],16, 530742520);b=hh(b,c,d,a,x[i+ 2],23, -995338651);
a=ii(a,b,c,d,x[i+ 0], 6, -198630844);d=ii(d,a,b,c,x[i+ 7],10, 1126891415);c=ii(c,d,a,b,x[i+14],15,-1416354905);
b=ii(b,c,d,a,x[i+ 5],21, -57434055);a=ii(a,b,c,d,x[i+12], 6, 1700485571);d=ii(d,a,b,c,x[i+ 3],10,-1894986606);
c=ii(c,d,a,b,x[i+10],15, -1051523);b=ii(b,c,d,a,x[i+ 1],21,-2054922799);a=ii(a,b,c,d,x[i+ 8], 6, 1873313359);
d=ii(d,a,b,c,x[i+15],10, -30611744);c=ii(c,d,a,b,x[i+ 6],15,-1560198380);b=ii(b,c,d,a,x[i+13],21, 1309151649);
a=ii(a,b,c,d,x[i+ 4], 6, -145523070);d=ii(d,a,b,c,x[i+11],10,-1120210379);c=ii(c,d,a,b,x[i+ 2],15, 718787259);
b=ii(b,c,d,a,x[i+ 9],21, -343485551);a=ad(a,olda);b=ad(b,oldb);c=ad(c,oldc);d=ad(d,oldd);
}
return rh(a)+rh(b)+rh(c)+rh(d);
}
这是另一个比我的快25%的 前一个 : D
function MD5(r) { var o, e, n, f = [ -680876936, -389564586, 606105819, -1044525330, -176418897, 1200080426, -1473231341, -45705983, 1770035416, -1958414417, -42063, -1990404162, 1804603682, -40341101, -1502002290, 1236535329, -165796510, -1069501632, 643717713, -373897302, -701558691, 38016083, -660478335, -405537848, 568446438, -1019803690, -187363961, 1163531501, -1444681467, -51403784, 1735328473, -1926607734, -378558, -2022574463, 1839030562, -35309556, -1530992060, 1272893353, -155497632, -1094730640, 681279174, -358537222, -722521979, 76029189, -640364487, -421815835, 530742520, -995338651, -198630844, 1126891415, -1416354905, -57434055, 1700485571, -1894986606, -1051523, -2054922799, 1873313359, -30611744, -1560198380, 1309151649, -145523070, -1120210379, 718787259, -343485551 ], t = [ o = 1732584193, e = 4023233417, ~o, ~e ], c = [], a = unescape(encodeURI(r)) + "\u0080", d = a.length; for (r = --d / 4 + 2 | 15, c[--r] = 8 * d; ~d; ) c[d >> 2] |= a.charCodeAt(d) << 8 * d--; for (i = a = 0; i < r; i += 16) { for (d = t; 64 > a; d = [ n = d[3], o + ((n = d[0] + [ o & e | ~o & n, n & o | ~n & e, o ^ e ^ n, e ^ (o | ~n) ][d = a >> 4] + f[a] + ~~c[i | 15 & [ a, 5 * a + 1, 3 * a + 5, 7 * a ][d]]) << (d = [ 7, 12, 17, 22, 5, 9, 14, 20, 4, 11, 16, 23, 6, 10, 15, 21 ][4 * d + a++ % 4]) | n >>> -d), o, e ]) o = 0 | d[1], e = d[2]; for (a = 4; a; ) t[--a] += d[a]; } for (r = ""; 32 > a; ) r += (t[a >> 3] >> 4 * (1 ^ a++) & 15).toString(16); return r; } <!DOCTYPE html> <html> <body onload="md5.value=MD5(a.value);"> <form oninput="md5.value=MD5(a.value)">Enter String: <input type="string" id="a" name="a" value="https://www.zibri.org"></br></br>MD5:<output id="md5" name="md5" for="a"></output> </form> </body> </html>
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