有很多MD5 JavaScript实现。 有人知道哪一个是最先进的,修复最多的,最快的吗?

我需要它来做这个工具。


当前回答

我真的不记得我从哪里得到这个。我在网上到处找,唯一能找到的参考文献就是这篇文章。奇怪。 如果任何人有关于这个实现起源的信息,请告诉我。

或者你可以试试这个新的,速度快25%:https://stackoverflow.com/a/74186696/236062:D

MD5 = function(e) { function h(a, b) { var c, d, e, f, g; e = a & 2147483648; f = b & 2147483648; c = a & 1073741824; d = b & 1073741824; g = (a & 1073741823) + (b & 1073741823); return c & d ? g ^ 2147483648 ^ e ^ f : c | d ? g & 1073741824 ? g ^ 3221225472 ^ e ^ f : g ^ 1073741824 ^ e ^ f : g ^ e ^ f } function k(a, b, c, d, e, f, g) { a = h(a, h(h(b & c | ~b & d, e), g)); return h(a << f | a >>> 32 - f, b) } function l(a, b, c, d, e, f, g) { a = h(a, h(h(b & d | c & ~d, e), g)); return h(a << f | a >>> 32 - f, b) } function m(a, b, d, c, e, f, g) { a = h(a, h(h(b ^ d ^ c, e), g)); return h(a << f | a >>> 32 - f, b) } function n(a, b, d, c, e, f, g) { a = h(a, h(h(d ^ (b | ~c), e), g)); return h(a << f | a >>> 32 - f, b) } function p(a) { var b = "", d = "", c; for (c = 0; 3 >= c; c++) d = a >>> 8 * c & 255, d = "0" + d.toString(16), b += d.substr(d.length - 2, 2); return b } var f = [], q, r, s, t, a, b, c, d; e = function(a) { a = a.replace(/\r\n/g, "\n"); for (var b = "", d = 0; d < a.length; d++) { var c = a.charCodeAt(d); 128 > c ? b += String.fromCharCode(c) : (127 < c && 2048 > c ? b += String.fromCharCode(c >> 6 | 192) : (b += String.fromCharCode(c >> 12 | 224), b += String.fromCharCode(c >> 6 & 63 | 128)), b += String.fromCharCode(c & 63 | 128)) } return b }(e); f = function(b) { var a, c = b.length; a = c + 8; for (var d = 16 * ((a - a % 64) / 64 + 1), e = Array(d - 1), f = 0, g = 0; g < c;) a = (g - g % 4) / 4, f = g % 4 * 8, e[a] |= b.charCodeAt(g) << f, g++; a = (g - g % 4) / 4; e[a] |= 128 << g % 4 * 8; e[d - 2] = c << 3; e[d - 1] = c >>> 29; return e }(e); a = 1732584193; b = 4023233417; c = 2562383102; d = 271733878; for (e = 0; e < f.length; e += 16) q = a, r = b, s = c, t = d, a = k(a, b, c, d, f[e + 0], 7, 3614090360), d = k(d, a, b, c, f[e + 1], 12, 3905402710), c = k(c, d, a, b, f[e + 2], 17, 606105819), b = k(b, c, d, a, f[e + 3], 22, 3250441966), a = k(a, b, c, d, f[e + 4], 7, 4118548399), d = k(d, a, b, c, f[e + 5], 12, 1200080426), c = k(c, d, a, b, f[e + 6], 17, 2821735955), b = k(b, c, d, a, f[e + 7], 22, 4249261313), a = k(a, b, c, d, f[e + 8], 7, 1770035416), d = k(d, a, b, c, f[e + 9], 12, 2336552879), c = k(c, d, a, b, f[e + 10], 17, 4294925233), b = k(b, c, d, a, f[e + 11], 22, 2304563134), a = k(a, b, c, d, f[e + 12], 7, 1804603682), d = k(d, a, b, c, f[e + 13], 12, 4254626195), c = k(c, d, a, b, f[e + 14], 17, 2792965006), b = k(b, c, d, a, f[e + 15], 22, 1236535329), a = l(a, b, c, d, f[e + 1], 5, 4129170786), d = l(d, a, b, c, f[e + 6], 9, 3225465664), c = l(c, d, a, b, f[e + 11], 14, 643717713), b = l(b, c, d, a, f[e + 0], 20, 3921069994), a = l(a, b, c, d, f[e + 5], 5, 3593408605), d = l(d, a, b, c, f[e + 10], 9, 38016083), c = l(c, d, a, b, f[e + 15], 14, 3634488961), b = l(b, c, d, a, f[e + 4], 20, 3889429448), a = l(a, b, c, d, f[e + 9], 5, 568446438), d = l(d, a, b, c, f[e + 14], 9, 3275163606), c = l(c, d, a, b, f[e + 3], 14, 4107603335), b = l(b, c, d, a, f[e + 8], 20, 1163531501), a = l(a, b, c, d, f[e + 13], 5, 2850285829), d = l(d, a, b, c, f[e + 2], 9, 4243563512), c = l(c, d, a, b, f[e + 7], 14, 1735328473), b = l(b, c, d, a, f[e + 12], 20, 2368359562), a = m(a, b, c, d, f[e + 5], 4, 4294588738), d = m(d, a, b, c, f[e + 8], 11, 2272392833), c = m(c, d, a, b, f[e + 11], 16, 1839030562), b = m(b, c, d, a, f[e + 14], 23, 4259657740), a = m(a, b, c, d, f[e + 1], 4, 2763975236), d = m(d, a, b, c, f[e + 4], 11, 1272893353), c = m(c, d, a, b, f[e + 7], 16, 4139469664), b = m(b, c, d, a, f[e + 10], 23, 3200236656), a = m(a, b, c, d, f[e + 13], 4, 681279174), d = m(d, a, b, c, f[e + 0], 11, 3936430074), c = m(c, d, a, b, f[e + 3], 16, 3572445317), b = m(b, c, d, a, f[e + 6], 23, 76029189), a = m(a, b, c, d, f[e + 9], 4, 3654602809), d = m(d, a, b, c, f[e + 12], 11, 3873151461), c = m(c, d, a, b, f[e + 15], 16, 530742520), b = m(b, c, d, a, f[e + 2], 23, 3299628645), a = n(a, b, c, d, f[e + 0], 6, 4096336452), d = n(d, a, b, c, f[e + 7], 10, 1126891415), c = n(c, d, a, b, f[e + 14], 15, 2878612391), b = n(b, c, d, a, f[e + 5], 21, 4237533241), a = n(a, b, c, d, f[e + 12], 6, 1700485571), d = n(d, a, b, c, f[e + 3], 10, 2399980690), c = n(c, d, a, b, f[e + 10], 15, 4293915773), b = n(b, c, d, a, f[e + 1], 21, 2240044497), a = n(a, b, c, d, f[e + 8], 6, 1873313359), d = n(d, a, b, c, f[e + 15], 10, 4264355552), c = n(c, d, a, b, f[e + 6], 15, 2734768916), b = n(b, c, d, a, f[e + 13], 21, 1309151649), a = n(a, b, c, d, f[e + 4], 6, 4149444226), d = n(d, a, b, c, f[e + 11], 10, 3174756917), c = n(c, d, a, b, f[e + 2], 15, 718787259), b = n(b, c, d, a, f[e + 9], 21, 3951481745), a = h(a, q), b = h(b, r), c = h(c, s), d = h(d, t); return (p(a) + p(b) + p(c) + p(d)).toLowerCase() }; <!DOCTYPE html> <html> <body onload="md5.value=MD5(a.value);"> <form oninput="md5.value=MD5(a.value)">Enter String: <input type="string" id="a" name="a" value="https://www.zibri.org"></br></br>MD5:<output id="md5" name="md5" for="a"></output> </form> </body> </html>

其他回答

下面是@dkellner和@Eonasdan的md5实现的ES6版本:

const md5 = inputString => {
   const hc = '0123456789abcdef';
   const rh = n => {let j,s='';for(j=0;j<=3;j++) s+=hc.charAt((n>>(j*8+4))&0x0F)+hc.charAt((n>>(j*8))&0x0F);return s;}
   const ad = (x,y) => {let l=(x&0xFFFF)+(y&0xFFFF);let m=(x>>16)+(y>>16)+(l>>16);return (m<<16)|(l&0xFFFF);}
   const rl = (n,c) => (n<<c)|(n>>>(32-c));
   const cm = (q,a,b,x,s,t) => ad(rl(ad(ad(a,q),ad(x,t)),s),b);
   const ff = (a,b,c,d,x,s,t) => cm((b&c)|((~b)&d),a,b,x,s,t);
   const gg = (a,b,c,d,x,s,t) => cm((b&d)|(c&(~d)),a,b,x,s,t);
   const hh = (a,b,c,d,x,s,t) => cm(b^c^d,a,b,x,s,t);
   const ii = (a,b,c,d,x,s,t) => cm(c^(b|(~d)),a,b,x,s,t);
   const sb = x => {
      let i;const nblk=((x.length+8)>>6)+1;const blks=[];for(i=0;i<nblk*16;i++) { blks[i]=0 };
      for(i=0;i<x.length;i++) {blks[i>>2]|=x.charCodeAt(i)<<((i%4)*8);}
      blks[i>>2]|=0x80<<((i%4)*8);blks[nblk*16-2]=x.length*8;return blks;
   }
   let i,x=sb(inputString),a=1732584193,b=-271733879,c=-1732584194,d=271733878,olda,oldb,oldc,oldd;
   for(i=0;i<x.length;i+=16) {olda=a;oldb=b;oldc=c;oldd=d;
      a=ff(a,b,c,d,x[i+ 0], 7, -680876936);d=ff(d,a,b,c,x[i+ 1],12, -389564586);c=ff(c,d,a,b,x[i+ 2],17,  606105819);
      b=ff(b,c,d,a,x[i+ 3],22,-1044525330);a=ff(a,b,c,d,x[i+ 4], 7, -176418897);d=ff(d,a,b,c,x[i+ 5],12, 1200080426);
      c=ff(c,d,a,b,x[i+ 6],17,-1473231341);b=ff(b,c,d,a,x[i+ 7],22,  -45705983);a=ff(a,b,c,d,x[i+ 8], 7, 1770035416);
      d=ff(d,a,b,c,x[i+ 9],12,-1958414417);c=ff(c,d,a,b,x[i+10],17,     -42063);b=ff(b,c,d,a,x[i+11],22,-1990404162);
      a=ff(a,b,c,d,x[i+12], 7, 1804603682);d=ff(d,a,b,c,x[i+13],12,  -40341101);c=ff(c,d,a,b,x[i+14],17,-1502002290);
      b=ff(b,c,d,a,x[i+15],22, 1236535329);a=gg(a,b,c,d,x[i+ 1], 5, -165796510);d=gg(d,a,b,c,x[i+ 6], 9,-1069501632);
      c=gg(c,d,a,b,x[i+11],14,  643717713);b=gg(b,c,d,a,x[i+ 0],20, -373897302);a=gg(a,b,c,d,x[i+ 5], 5, -701558691);
      d=gg(d,a,b,c,x[i+10], 9,   38016083);c=gg(c,d,a,b,x[i+15],14, -660478335);b=gg(b,c,d,a,x[i+ 4],20, -405537848);
      a=gg(a,b,c,d,x[i+ 9], 5,  568446438);d=gg(d,a,b,c,x[i+14], 9,-1019803690);c=gg(c,d,a,b,x[i+ 3],14, -187363961);
      b=gg(b,c,d,a,x[i+ 8],20, 1163531501);a=gg(a,b,c,d,x[i+13], 5,-1444681467);d=gg(d,a,b,c,x[i+ 2], 9,  -51403784);
      c=gg(c,d,a,b,x[i+ 7],14, 1735328473);b=gg(b,c,d,a,x[i+12],20,-1926607734);a=hh(a,b,c,d,x[i+ 5], 4,    -378558);
      d=hh(d,a,b,c,x[i+ 8],11,-2022574463);c=hh(c,d,a,b,x[i+11],16, 1839030562);b=hh(b,c,d,a,x[i+14],23,  -35309556);
      a=hh(a,b,c,d,x[i+ 1], 4,-1530992060);d=hh(d,a,b,c,x[i+ 4],11, 1272893353);c=hh(c,d,a,b,x[i+ 7],16, -155497632);
      b=hh(b,c,d,a,x[i+10],23,-1094730640);a=hh(a,b,c,d,x[i+13], 4,  681279174);d=hh(d,a,b,c,x[i+ 0],11, -358537222);
      c=hh(c,d,a,b,x[i+ 3],16, -722521979);b=hh(b,c,d,a,x[i+ 6],23,   76029189);a=hh(a,b,c,d,x[i+ 9], 4, -640364487);
      d=hh(d,a,b,c,x[i+12],11, -421815835);c=hh(c,d,a,b,x[i+15],16,  530742520);b=hh(b,c,d,a,x[i+ 2],23, -995338651);
      a=ii(a,b,c,d,x[i+ 0], 6, -198630844);d=ii(d,a,b,c,x[i+ 7],10, 1126891415);c=ii(c,d,a,b,x[i+14],15,-1416354905);
      b=ii(b,c,d,a,x[i+ 5],21,  -57434055);a=ii(a,b,c,d,x[i+12], 6, 1700485571);d=ii(d,a,b,c,x[i+ 3],10,-1894986606);
      c=ii(c,d,a,b,x[i+10],15,   -1051523);b=ii(b,c,d,a,x[i+ 1],21,-2054922799);a=ii(a,b,c,d,x[i+ 8], 6, 1873313359);
      d=ii(d,a,b,c,x[i+15],10,  -30611744);c=ii(c,d,a,b,x[i+ 6],15,-1560198380);b=ii(b,c,d,a,x[i+13],21, 1309151649);
      a=ii(a,b,c,d,x[i+ 4], 6, -145523070);d=ii(d,a,b,c,x[i+11],10,-1120210379);c=ii(c,d,a,b,x[i+ 2],15,  718787259);
      b=ii(b,c,d,a,x[i+ 9],21, -343485551);a=ad(a,olda);b=ad(b,oldb);c=ad(c,oldc);d=ad(d,oldd);
   }
   return rh(a)+rh(b)+rh(c)+rh(d);
}

js-md5支持UTF-8字符串,数组,ArrayBuffer, AMD....

和快速。jsperf

我听说Joseph的Myers实现非常快。此外,他还有一篇关于Javascript优化的长篇文章,描述了他在编写实现时学到的东西。对于任何对性能javascript感兴趣的人来说,这是一本很好的读物。

http://www.webreference.com/programming/javascript/jkm3/

他的MD5实现可以在这里找到

我找到了许多关于这个主题的文章。 他们都建议约瑟夫·迈耶斯实施。

在某些测试中,请参阅:http://jsperf.com/md5-shootout

在我对终极速度的追求中,我看了这段代码,我看到它可以改进。所以我基于Joseph Meyers代码创建了一个新的JS脚本。

参见改进的约瑟夫迈耶斯代码

我编写了测试来比较几种JavaScript哈希实现,包括这里提到的大多数MD5实现。 要运行测试,请访问http://brillout.github.io/test-javascript-hash-implementations/并稍等片刻。

似乎R. Hill的答案的YaMD5实现是最快的。