我从来都不记得我是怎么做到的,因为它很少出现在我身上。但是在C或c++中,从标准输入中读取字符而不等待换行符(按enter)的最佳方法是什么?
理想情况下,它也不会将输入字符回显到屏幕上。我只是想在不影响控制台屏幕的情况下捕捉击键。
我从来都不记得我是怎么做到的,因为它很少出现在我身上。但是在C或c++中,从标准输入中读取字符而不等待换行符(按enter)的最佳方法是什么?
理想情况下,它也不会将输入字符回显到屏幕上。我只是想在不影响控制台屏幕的情况下捕捉击键。
当前回答
适用于我的windows:
#include <conio.h>
char c = _getch();
其他回答
下面是一个不向系统提供外壳的版本(在macOS 10.14上编写和测试)
#include <unistd.h>
#include <termios.h>
#include <stdio.h>
#include <string.h>
char* getStr( char* buffer , int maxRead ) {
int numRead = 0;
char ch;
struct termios old = {0};
struct termios new = {0};
if( tcgetattr( 0 , &old ) < 0 ) perror( "tcgetattr() old settings" );
if( tcgetattr( 0 , &new ) < 0 ) perror( "tcgetaart() new settings" );
cfmakeraw( &new );
if( tcsetattr( 0 , TCSADRAIN , &new ) < 0 ) perror( "tcssetattr makeraw new" );
for( int i = 0 ; i < maxRead ; i++) {
ch = getchar();
switch( ch ) {
case EOF:
case '\n':
case '\r':
goto exit_getStr;
break;
default:
printf( "%1c" , ch );
buffer[ numRead++ ] = ch;
if( numRead >= maxRead ) {
goto exit_getStr;
}
break;
}
}
exit_getStr:
if( tcsetattr( 0 , TCSADRAIN , &old) < 0) perror ("tcsetattr reset to old" );
printf( "\n" );
return buffer;
}
int main( void )
{
const int maxChars = 20;
char stringBuffer[ maxChars+1 ];
memset( stringBuffer , 0 , maxChars+1 ); // initialize to 0
printf( "enter a string: ");
getStr( stringBuffer , maxChars );
printf( "you entered: [%s]\n" , stringBuffer );
}
CONIO.H
你需要的函数是:
int getch();
Prototype
int _getch(void);
Description
_getch obtains a character from stdin. Input is unbuffered, and this
routine will return as soon as a character is available without
waiting for a carriage return. The character is not echoed to stdout.
_getch bypasses the normal buffering done by getchar and getc. ungetc
cannot be used with _getch.
Synonym
Function: getch
int kbhit();
Description
Checks if a keyboard key has been pressed but not yet read.
Return Value
Returns a non-zero value if a key was pressed. Otherwise, returns 0.
libconio http://sourceforge.net/projects/libconio
or
conio.h的Linux c++实现 http://sourceforge.net/projects/linux-conioh
我也遇到过同样的问题。这里是一个小的解决方案为windows控制台使用cygwing++与if(GetKeyState(keycode) & bitANDcompare){};
#include <windows.h>
#include <fstream>
#include <iostream>
using namespace std;
void clear() {
COORD topLeft = { 0, 0 };
HANDLE console = GetStdHandle(STD_OUTPUT_HANDLE);
CONSOLE_SCREEN_BUFFER_INFO screen;
DWORD written;
GetConsoleScreenBufferInfo(console, &screen);
FillConsoleOutputCharacterA(
console, ' ', screen.dwSize.X * screen.dwSize.Y, topLeft, &written
);
FillConsoleOutputAttribute(
console, FOREGROUND_GREEN | FOREGROUND_RED | FOREGROUND_BLUE,
screen.dwSize.X * screen.dwSize.Y, topLeft, &written
);
SetConsoleCursorPosition(console, topLeft);
}
class Keyclick{
private:
int key;
char id;
public:
bool keydown = false;
Keyclick(int key1, char id1){
key=key1;
id=id1;
};
void watch(){
if(keydown==false){
if(GetKeyState(key) & 0x8000 ){
cout << id;
cout << " pressed.\r\n";
keydown = true;
}
}
if(keydown == true){
if(!(GetKeyState(key) & 0x8000)) {
cout << "released!!!!!!!!!!\r\n";
keydown = false;
clear();
}
}
};
};
int main()
{
bool primaryloop =true;
Keyclick keysp(VK_SPACE,'S');
Keyclick keyw(0x57,'w');
Keyclick keya(0x41,'a');
Keyclick keys(0x53,'s');
Keyclick keyd(0x44,'d');
Keyclick keyesc(VK_ESCAPE,'E');
while(primaryloop){
keysp.watch();
keyw.watch();
keya.watch();
keys.watch();
keyd.watch();
keyesc.watch();
if(keyesc.keydown){
primaryloop=false;
};
}
return 0;
}
https://github.com/wark77/windows_console_keypoller/blob/main/getkeystate_SOLUTION01.cpp
假设是Windows,看一下ReadConsoleInput函数。
适用于我的windows:
#include <conio.h>
char c = _getch();