我从来都不记得我是怎么做到的,因为它很少出现在我身上。但是在C或c++中,从标准输入中读取字符而不等待换行符(按enter)的最佳方法是什么?
理想情况下,它也不会将输入字符回显到屏幕上。我只是想在不影响控制台屏幕的情况下捕捉击键。
我从来都不记得我是怎么做到的,因为它很少出现在我身上。但是在C或c++中,从标准输入中读取字符而不等待换行符(按enter)的最佳方法是什么?
理想情况下,它也不会将输入字符回显到屏幕上。我只是想在不影响控制台屏幕的情况下捕捉击键。
当前回答
这在纯c++中以可移植的方式是不可能的,因为它太依赖于可能与stdin连接的终端(它们通常是行缓冲的)。不过,你可以使用一个库来实现:
conio available with Windows compilers. Use the _getch() function to give you a character without waiting for the Enter key. I'm not a frequent Windows developer, but I've seen my classmates just include <conio.h> and use it. See conio.h at Wikipedia. It lists getch(), which is declared deprecated in Visual C++. curses available for Linux. Compatible curses implementations are available for Windows too. It has also a getch() function. (try man getch to view its manpage). See Curses at Wikipedia.
如果你的目标是跨平台兼容性,我建议你使用curses。也就是说,我相信有一些函数可以用来关闭行缓冲(我相信这被称为“原始模式”,而不是“熟模式”-看看man stty)。如果我没记错的话,诅咒可以方便地帮你解决这个问题。
其他回答
下面是一个不向系统提供外壳的版本(在macOS 10.14上编写和测试)
#include <unistd.h>
#include <termios.h>
#include <stdio.h>
#include <string.h>
char* getStr( char* buffer , int maxRead ) {
int numRead = 0;
char ch;
struct termios old = {0};
struct termios new = {0};
if( tcgetattr( 0 , &old ) < 0 ) perror( "tcgetattr() old settings" );
if( tcgetattr( 0 , &new ) < 0 ) perror( "tcgetaart() new settings" );
cfmakeraw( &new );
if( tcsetattr( 0 , TCSADRAIN , &new ) < 0 ) perror( "tcssetattr makeraw new" );
for( int i = 0 ; i < maxRead ; i++) {
ch = getchar();
switch( ch ) {
case EOF:
case '\n':
case '\r':
goto exit_getStr;
break;
default:
printf( "%1c" , ch );
buffer[ numRead++ ] = ch;
if( numRead >= maxRead ) {
goto exit_getStr;
}
break;
}
}
exit_getStr:
if( tcsetattr( 0 , TCSADRAIN , &old) < 0) perror ("tcsetattr reset to old" );
printf( "\n" );
return buffer;
}
int main( void )
{
const int maxChars = 20;
char stringBuffer[ maxChars+1 ];
memset( stringBuffer , 0 , maxChars+1 ); // initialize to 0
printf( "enter a string: ");
getStr( stringBuffer , maxChars );
printf( "you entered: [%s]\n" , stringBuffer );
}
CONIO.H
你需要的函数是:
int getch();
Prototype
int _getch(void);
Description
_getch obtains a character from stdin. Input is unbuffered, and this
routine will return as soon as a character is available without
waiting for a carriage return. The character is not echoed to stdout.
_getch bypasses the normal buffering done by getchar and getc. ungetc
cannot be used with _getch.
Synonym
Function: getch
int kbhit();
Description
Checks if a keyboard key has been pressed but not yet read.
Return Value
Returns a non-zero value if a key was pressed. Otherwise, returns 0.
libconio http://sourceforge.net/projects/libconio
or
conio.h的Linux c++实现 http://sourceforge.net/projects/linux-conioh
在WINDOWS上我这样做:
#include <Windows.h>
int main()
{
system("PAUSE>NUL");
if (GetKeyState(0x41/*(the 'A' key, choosen e.g.)*/) & (0xff80/*That stands for "Default state / Key Down"*/)) {
//whatever I want to do after 'A' is pressed
}
}
这里可以找到一个键的列表,每个键都有自己的十六进制值: https://learn.microsoft.com/en-us/windows/win32/inputdev/virtual-key-codes
我总是想要一个循环读取我的输入而不按返回键。 这对我很管用。
#include<stdio.h>
main()
{
char ch;
system("stty raw");//seting the terminal in raw mode
while(1)
{
ch=getchar();
if(ch=='~'){ //terminate or come out of raw mode on "~" pressed
system("stty cooked");
//while(1);//you may still run the code
exit(0); //or terminate
}
printf("you pressed %c\n ",ch); //write rest code here
}
}
我在另一个论坛上发现了这个,当时我想解决同样的问题。根据我的发现,我做了一些修改。效果很好。我运行的是OS X,所以如果你运行的是微软,你需要找到正确的system()命令来切换到raw和cooked模式。
#include <iostream>
#include <stdio.h>
using namespace std;
int main() {
// Output prompt
cout << "Press any key to continue..." << endl;
// Set terminal to raw mode
system("stty raw");
// Wait for single character
char input = getchar();
// Echo input:
cout << "--" << input << "--";
// Reset terminal to normal "cooked" mode
system("stty cooked");
// And we're out of here
return 0;
}