我在另一个论坛上发现了这个，当时我想解决同样的问题。根据我的发现，我做了一些修改。效果很好。我运行的是OS X，所以如果你运行的是微软，你需要找到正确的system()命令来切换到raw和cooked模式。

#include <iostream> 
#include <stdio.h>  
using namespace std;  

int main() { 
  // Output prompt 
  cout << "Press any key to continue..." << endl; 

  // Set terminal to raw mode 
  system("stty raw"); 

  // Wait for single character 
  char input = getchar(); 

  // Echo input:
  cout << "--" << input << "--";

  // Reset terminal to normal "cooked" mode 
  system("stty cooked"); 

  // And we're out of here 
  return 0; 
}

以下是一个从Expert C Programming: Deep Secrets中提取的解决方案，它应该可以在SVr4上工作。它使用stty和ioctl。

#include <sys/filio.h>
int kbhit()
{
 int i;
 ioctl(0, FIONREAD, &i);
 return i; /* return a count of chars available to read */
}
main()
{
 int i = 0;
 intc='';
 system("stty raw -echo");
 printf("enter 'q' to quit \n");
 for (;c!='q';i++) {
    if (kbhit()) {
        c=getchar();
       printf("\n got %c, on iteration %d",c, i);
    }
}
 system("stty cooked echo");
}

CONIO.H

你需要的函数是:

int getch();
Prototype
    int _getch(void); 
Description
    _getch obtains a character  from stdin. Input is unbuffered, and this
    routine  will  return as  soon as  a character is  available  without 
    waiting for a carriage return. The character is not echoed to stdout.
    _getch bypasses the normal buffering done by getchar and getc. ungetc 
    cannot be used with _getch. 
Synonym
    Function: getch 


int kbhit();
Description
    Checks if a keyboard key has been pressed but not yet read. 
Return Value
    Returns a non-zero value if a key was pressed. Otherwise, returns 0.

libconio http://sourceforge.net/projects/libconio

or

conio.h的Linux c++实现 http://sourceforge.net/projects/linux-conioh

这在纯c++中以可移植的方式是不可能的，因为它太依赖于可能与stdin连接的终端(它们通常是行缓冲的)。不过，你可以使用一个库来实现:

conio available with Windows compilers. Use the _getch() function to give you a character without waiting for the Enter key. I'm not a frequent Windows developer, but I've seen my classmates just include <conio.h> and use it. See conio.h at Wikipedia. It lists getch(), which is declared deprecated in Visual C++. curses available for Linux. Compatible curses implementations are available for Windows too. It has also a getch() function. (try man getch to view its manpage). See Curses at Wikipedia.

如果你的目标是跨平台兼容性，我建议你使用curses。也就是说，我相信有一些函数可以用来关闭行缓冲(我相信这被称为“原始模式”，而不是“熟模式”-看看man stty)。如果我没记错的话，诅咒可以方便地帮你解决这个问题。

在WINDOWS上我这样做:

#include <Windows.h>
int main()
{
    system("PAUSE>NUL");
    if (GetKeyState(0x41/*(the 'A' key, choosen e.g.)*/) & (0xff80/*That stands for "Default state / Key Down"*/)) {
        //whatever I want to do after 'A' is pressed
    }
}

这里可以找到一个键的列表，每个键都有自己的十六进制值: https://learn.microsoft.com/en-us/windows/win32/inputdev/virtual-key-codes

在Linux(和其他类unix系统)上，这可以通过以下方式完成:

#include <unistd.h>
#include <termios.h>

char getch() {
        char buf = 0;
        struct termios old = {0};
        if (tcgetattr(0, &old) < 0)
                perror("tcsetattr()");
        old.c_lflag &= ~ICANON;
        old.c_lflag &= ~ECHO;
        old.c_cc[VMIN] = 1;
        old.c_cc[VTIME] = 0;
        if (tcsetattr(0, TCSANOW, &old) < 0)
                perror("tcsetattr ICANON");
        if (read(0, &buf, 1) < 0)
                perror ("read()");
        old.c_lflag |= ICANON;
        old.c_lflag |= ECHO;
        if (tcsetattr(0, TCSADRAIN, &old) < 0)
                perror ("tcsetattr ~ICANON");
        return (buf);
}

基本上你必须关闭规范模式(和回声模式来抑制回声)。