在WINDOWS上我这样做:

#include <Windows.h>
int main()
{
    system("PAUSE>NUL");
    if (GetKeyState(0x41/*(the 'A' key, choosen e.g.)*/) & (0xff80/*That stands for "Default state / Key Down"*/)) {
        //whatever I want to do after 'A' is pressed
    }
}

这里可以找到一个键的列表，每个键都有自己的十六进制值: https://learn.microsoft.com/en-us/windows/win32/inputdev/virtual-key-codes

最接近可移植的方法是使用ncurses库将终端置于“cbreak模式”。API是巨大的;你最想要的是

Initscr和endwin 黄昏时分和黄昏时分 getch

好运！

C和c++对I/O有一个非常抽象的看法，没有标准的方法来做你想做的事情。有从标准输入流中获取字符的标准方法(如果有的话)，这两种语言都没有定义其他任何方法。因此，任何答案都必须是特定于平台的，可能不仅取决于操作系统，还取决于软件框架。

这里有一些合理的猜测，但如果不知道目标环境是什么，就无法回答您的问题。

管道演示:如何从C语言的系统调用管道读取键盘按键

理想情况下，它也不会将输入字符回显到屏幕上。我只是想在不影响控制台屏幕的情况下捕捉击键。

要在Linux上做到这一点，您可以使用以下bash命令:

read -sn1 c && printf "You Pressed: %s\n" "$c"

请看我在这里的回答关于这个的详细信息:shell脚本响应按键。

因此，要在Linux上的C或c++中做到这一点，您只需要通过使用popen()和fgets()的管道通过系统调用调用上面的bash命令，这样您就可以从bash命令读取输出。

下面是一个完整的例子，在Linux上运行良好的C和c++:

read_system_call_via_pipe__keypress.c:

#include <stdbool.h> // For `true` (`1`) and `false` (`0`) macros in C
#include <stdint.h>  // For `uint8_t`, `int8_t`, etc.
#include <stdio.h>   // For `printf()`
#include <stdlib.h>

#define BUFSIZE 32

// Read a keyboard key press and return the character pressed, or a negative
// number in the event of an error.
// NB: for help reading output from system calls, see here:
//  1. https://stackoverflow.com/a/28971647/4561887
//  2. https://stackoverflow.com/a/18297075/4561887
char getKeypress()
{
    // This bash cmd is from my answer here:
    // https://stackoverflow.com/a/70979348/4561887
    const char* cmd = "bash -c 'read -s -n1 c && printf \"%s\" \"$c\"'";
    FILE *fp = popen(cmd, "r");
    if (fp == NULL)
    {
        printf("\nError opening pipe!\n");
        return -1;
    }

    char buf[BUFSIZE] = {0};
    char* retval1 = fgets(buf, BUFSIZE, fp);
    if (retval1 == NULL)
    {
        printf("\nFailed to read cmd response.\n");
        return -2;
    }

    // See meaning of this return value here:
    // https://stackoverflow.com/questions/43116/how-can-i-run-an-external-program-from-c-and-parse-its-output/28971647#comment60311936_28971647
    int retval2 = pclose(fp);
    if (retval2 == -1)
    {
        printf("\nError obtaining the cmd's exit status code.\n");
        return -3;
    }
    else if (retval2 != 0)
    {
        printf("\nCommand exited with exit status code %i.\n", retval2);
        return -4;
    }

    char keyPressed = buf[0];
    return keyPressed;
}

// int main(int argc, char *argv[])  // alternative prototype
int main()
{
    printf("Press any key to continue: ");
    fflush(stdout);
    char keyPressed = getKeypress();
    if (keyPressed > 0)
    {
        printf("\nKey pressed = %c\n", keyPressed);
    }

    return 0;
}

C和c++编译和运行命令是下面输出的一部分。下面是一些演示:

在C:

eRCaGuy_hello_world/c$ gcc -Wall -Wextra -Werror -O3 -std=gnu17 read_keypress_system_call.c -o bin/a && bin/a
Press any key to continue:
Key pressed = P

或，在c++中:

eRCaGuy_hello_world/c$ g++ -Wall -Wextra -Werror -O3 -std=c++17 read_keypress_system_call.c -o bin/a && bin/a
Press any key to continue:
Key pressed = u

参见:

要更进一步，请参阅我在这里的另一个回答，我一次检测并解析3个字符，以便检测方向键的向上、向下、向左或向右:在C语言中读取键按下。方向键，Enter键

引用:

How I learned to read from a pipe to get system call output: How can I run an external program from C and parse its output? Is there a way to obtain the output of a linux command(like ifconfig) on a .txt file using a C program? [duplicate] How to compile and use popen() in C: use -std=gnu17 instead of -std=c17: popen implicitly declared even though #include <stdio.h> is added [my answer] How to read without blocking, via bash: shell script respond to keypress [my answer] How do I read in the Enter key as an input in C?

关于这个话题的3个问题

从标准输入中捕获字符，而不需要等待按enter键 C非阻塞键盘输入 如何避免按Enter与getchar()只为读取单个字符?

Ncurses提供了一个很好的方法来做到这一点! 这也是我的第一篇文章(我记得)，所以欢迎任何评论。我会欣赏有用的，但都是受欢迎的!

编译： g++ -std=c++11 -pthread -lncurses .cpp -o

#include <iostream>
#include <ncurses.h>
#include <future>

char get_keyboard_input();

int main(int argc, char *argv[])
{
    initscr();
    raw();
    noecho();
    keypad(stdscr,true);

    auto f = std::async(std::launch::async, get_keyboard_input);
    while (f.wait_for(std::chrono::milliseconds(20)) != std::future_status::ready)
    {
        // do some work
    }

    endwin();
    std::cout << "returned: " << f.get() << std::endl;
    return 0;
}

char get_keyboard_input()
{
    char input = '0';
    while(input != 'q')
    {
        input = getch();
    }
    return input;
}

下面是一个不向系统提供外壳的版本(在macOS 10.14上编写和测试)

#include <unistd.h>
#include <termios.h>
#include <stdio.h>
#include <string.h>

char* getStr( char* buffer , int maxRead ) {
  int  numRead  = 0;
  char ch;

  struct termios old = {0};
  struct termios new = {0};
  if( tcgetattr( 0 , &old ) < 0 )        perror( "tcgetattr() old settings" );
  if( tcgetattr( 0 , &new ) < 0 )        perror( "tcgetaart() new settings" );
  cfmakeraw( &new );
  if( tcsetattr( 0 , TCSADRAIN , &new ) < 0 ) perror( "tcssetattr makeraw new" );

  for( int i = 0 ; i < maxRead ; i++)  {
    ch = getchar();
    switch( ch )  {
      case EOF: 
      case '\n':
      case '\r':
        goto exit_getStr;
        break;

      default:
        printf( "%1c" , ch );
        buffer[ numRead++ ] = ch;
        if( numRead >= maxRead )  {
          goto exit_getStr;
        }
        break;
    }
  }

exit_getStr:
  if( tcsetattr( 0 , TCSADRAIN , &old) < 0)   perror ("tcsetattr reset to old" );
  printf( "\n" );   
  return buffer;
}


int main( void ) 
{
  const int maxChars = 20;
  char      stringBuffer[ maxChars+1 ];
  memset(   stringBuffer , 0 , maxChars+1 ); // initialize to 0

  printf( "enter a string: ");
  getStr( stringBuffer , maxChars );
  printf( "you entered: [%s]\n" , stringBuffer );
}