bash中有没有将字符串转换为小写字符串的方法?
例如,如果我有:
a="Hi all"
我想将其转换为:
"hi all"
bash中有没有将字符串转换为小写字符串的方法?
例如,如果我有:
a="Hi all"
我想将其转换为:
"hi all"
当前回答
你可以试试这个
s="Hello World!"
echo $s # Hello World!
a=${s,,}
echo $a # hello world!
b=${s^^}
echo $b # HELLO WORLD!
裁判:http://wiki.workassis.com/shell-script-convert-text-to-lowercase-and-uppercase/
其他回答
预冲击4.0
Bash降低字符串的大小写并赋值给变量
VARIABLE=$(echo "$VARIABLE" | tr '[:upper:]' '[:lower:]')
echo "$VARIABLE"
在Bash 4中:
小写
$ string="A FEW WORDS"
$ echo "${string,}"
a FEW WORDS
$ echo "${string,,}"
a few words
$ echo "${string,,[AEIUO]}"
a FeW WoRDS
$ string="A Few Words"
$ declare -l string
$ string=$string; echo "$string"
a few words
大写
$ string="a few words"
$ echo "${string^}"
A few words
$ echo "${string^^}"
A FEW WORDS
$ echo "${string^^[aeiou]}"
A fEw wOrds
$ string="A Few Words"
$ declare -u string
$ string=$string; echo "$string"
A FEW WORDS
切换(未记录,但可在编译时配置)
$ string="A Few Words"
$ echo "${string~~}"
a fEW wORDS
$ string="A FEW WORDS"
$ echo "${string~}"
a FEW WORDS
$ string="a few words"
$ echo "${string~}"
A few words
大写(未记录,但可在编译时配置)
$ string="a few words"
$ declare -c string
$ string=$string
$ echo "$string"
A few words
标题大小写:
$ string="a few words"
$ string=($string)
$ string="${string[@]^}"
$ echo "$string"
A Few Words
$ declare -c string
$ string=(a few words)
$ echo "${string[@]}"
A Few Words
$ string="a FeW WOrdS"
$ string=${string,,}
$ string=${string~}
$ echo "$string"
A few words
要关闭声明属性,请使用+。例如,声明+c字符串。这会影响后续赋值,而不是当前值。
declare选项更改变量的属性,但不更改内容。示例中的重新分配会更新内容以显示更改。
编辑:
按照ghostdog74的建议,添加了“按单词切换第一个字符”(${var~})。
编辑:更正波浪号行为以匹配Bash 4.3。
对于Bash命令行,根据语言环境和国际字母,这可能会起作用(根据其他人的答案组合而成):
$ echo "ABCÆØÅ" | python -c "print(open(0).read().lower())"
abcæøå
$ echo "ABCÆØÅ" | sed 's/./\L&/g'
abcæøå
$ export a="ABCÆØÅ" | echo "${a,,}"
abcæøå
尽管这些变化可能不起作用:
$ echo "ABCÆØÅ" | tr "[:upper:]" "[:lower:]"
abcÆØÅ
$ echo "ABCÆØÅ" | awk '{print tolower($1)}'
abcÆØÅ
$ echo "ABCÆØÅ" | perl -ne 'print lc'
abcÆØÅ
$ echo 'ABCÆØÅ' | dd conv=lcase 2> /dev/null
abcÆØÅ
使用GNU sed:
sed 's/.*/\L&/'
例子:
$ foo="Some STRIng";
$ foo=$(echo "$foo" | sed 's/.*/\L&/')
$ echo "$foo"
some string
对于早于4.0的Bash版本,该版本应该是最快的(因为它不会fork/exec任何命令):
function string.monolithic.tolower
{
local __word=$1
local __len=${#__word}
local __char
local __octal
local __decimal
local __result
for (( i=0; i<__len; i++ ))
do
__char=${__word:$i:1}
case "$__char" in
[A-Z] )
printf -v __decimal '%d' "'$__char"
printf -v __octal '%03o' $(( $__decimal ^ 0x20 ))
printf -v __char \\$__octal
;;
esac
__result+="$__char"
done
REPLY="$__result"
}
技术龙的回答也很有潜力,尽管它确实适合mee。