根据Joel的说法，巩固其他答案，并希望随着我的前进略有改善:

你可以用Regex.Replace()来实现:

string s = Regex.Replace (
    "   1  2    4 5", 
    @"[ ]{2,}", 
    " "
    );

或者使用String.Split():

static class StringExtensions
{
    public static string Join(this IList<string> value, string separator)
    {
        return string.Join(separator, value.ToArray());
    }
}

//...

string s = "     1  2    4 5".Split (
    " ".ToCharArray(), 
    StringSplitOptions.RemoveEmptyEntries
    ).Join (" ");

myString = Regex.Replace(myString, " {2,}", " ");

老派：

string oldText = "   1 2  3   4    5     ";
string newText = oldText
                    .Replace("  ", " " + (char)22 )
                    .Replace( (char)22 + " ", "" )
                    .Replace( (char)22 + "", "" );

Assert.That( newText, Is.EqualTo( " 1 2 3 4 5 " ) );

我刚刚写了一个我喜欢的新Join，所以我想我应该重新回答，用它:

public static string Join<T>(this IEnumerable<T> source, string separator)
{
    return string.Join(separator, source.Select(e => e.ToString()).ToArray());
}

关于它的一个很酷的事情是，它通过在元素上调用ToString()来处理不是字符串的集合。用法还是一样的:

//...

string s = "     1  2    4 5".Split (
    " ".ToCharArray(), 
    StringSplitOptions.RemoveEmptyEntries
    ).Join (" ");

试试这个方法

private string removeNestedWhitespaces(char[] st)
{
    StringBuilder sb = new StringBuilder();
    int indx = 0, length = st.Length;
    while (indx < length)
    {
        sb.Append(st[indx]);
        indx++;
        while (indx < length && st[indx] == ' ')
            indx++;
        if(sb.Length > 1  && sb[0] != ' ')
            sb.Append(' ');
    }
    return sb.ToString();
}

像这样使用它:

string test = removeNestedWhitespaces("1 2 3  4    5".toCharArray());

string xyz = "1   2   3   4   5";
xyz = string.Join( " ", xyz.Split( new char[] { ' ' }, StringSplitOptions.RemoveEmptyEntries ));