使用正则表达式模式

    [ ]+    #only space

   var text = Regex.Replace(inputString, @"[ ]+", " ");

老派：

string oldText = "   1 2  3   4    5     ";
string newText = oldText
                    .Replace("  ", " " + (char)22 )
                    .Replace( (char)22 + " ", "" )
                    .Replace( (char)22 + "", "" );

Assert.That( newText, Is.EqualTo( " 1 2 3 4 5 " ) );

string xyz = "1   2   3   4   5";
xyz = string.Join( " ", xyz.Split( new char[] { ' ' }, StringSplitOptions.RemoveEmptyEntries ));

// Mysample string
string str ="hi you           are          a demo";

//Split the words based on white sapce
var demo= str .Split(' ').Where(s => !string.IsNullOrWhiteSpace(s));
        
//Join the values back and add a single space in between
str = string.Join(" ", demo);
// output: string str ="hi you are a demo";

混合StringBuilder和Enumerable.Aggregate()作为字符串的扩展方法:

using System;
using System.Linq;
using System.Text;

public static class StringExtension
{
    public static string CondenseSpaces(this string s)
    {
        return s.Aggregate(new StringBuilder(), (acc, c) =>
        {
            if (c != ' ' || acc.Length == 0 || acc[acc.Length - 1] != ' ')
                acc.Append(c);
            return acc;
        }).ToString();
    }

    public static void Main()
    {
        const string input = "     (five leading spaces)     (five internal spaces)     (five trailing spaces)     ";
        
        Console.WriteLine(" Input: \"{0}\"", input);
        Console.WriteLine("Output: \"{0}\"", StringExtension.CondenseSpaces(input));
    }
}

执行这个程序产生以下输出:

 Input: "     (five leading spaces)     (five internal spaces)     (five trailing spaces)     "
Output: " (five leading spaces) (five internal spaces) (five trailing spaces) "

我知道这很老了，但在尝试完成几乎相同的事情时偶然发现了它。在RegEx Buddy中找到了这个解决方案。该模式将用单个空格替换所有的双空格，并修剪开头和结尾空格。

pattern: (?m:^ +| +$|( ){2,})
replacement: $1

因为我们处理的是空格，所以读起来有点困难，所以这里还是用“_”代替了“空格”。

pattern: (?m:^_+|_+$|(_){2,})  <-- don't use this, just for illustration.

“(?M:" construct启用“多行”选项。我通常喜欢在模式本身中包含任何我可以包含的选项，这样它就更独立了。