试试这个:

def rm_char(original_str, need2rm):
    ''' Remove charecters in "need2rm" from "original_str" '''
    return original_str.translate(str.maketrans('','',need2rm))

这个方法在python3中很有效

对于只允许字符串中某些字符的相反要求，可以使用带有集补操作符[^ABCabc]的正则表达式。例如，要删除除ascii字母、数字和连字符以外的所有字符:

>>> import string
>>> import re
>>>
>>> phrase = '  There were "nine" (9) chick-peas in my pocket!!!      '
>>> allow = string.letters + string.digits + '-'
>>> re.sub('[^%s]' % allow, '', phrase)

'Therewerenine9chick-peasinmypocket'

来自python正则表达式文档:

不在范围内的字符可以通过互补来匹配 一组。如果集合的第一个字符是'^'，则所有字符 不在集合中的将被匹配。例如，[^5]将匹配 除'5'以外的任何字符，[^^]将匹配除 “^”。的第一个字符没有特殊意义 集。

#!/usr/bin/python
import re

strs = "how^ much for{} the maple syrup? $20.99? That's[] ricidulous!!!"
print strs
nstr = re.sub(r'[?|$|.|!|a|b]',r' ',strs)#i have taken special character to remove but any #character can be added here
print nstr
nestr = re.sub(r'[^a-zA-Z0-9 ]',r'',nstr)#for removing special character
print nestr

试试这个:

def rm_char(original_str, need2rm):
    ''' Remove charecters in "need2rm" from "original_str" '''
    return original_str.translate(str.maketrans('','',need2rm))

这个方法在python3中很有效

这是我的Python 2/3兼容版本。因为翻译api已经改变了。

def remove(str_, chars):
    """Removes each char in `chars` from `str_`.

    Args:
        str_: String to remove characters from
        chars: String of to-be removed characters

    Returns:
        A copy of str_ with `chars` removed

    Example:
            remove("What?!?: darn;", " ?.!:;") => 'Whatdarn'
    """
    try:
        # Python2.x
        return str_.translate(None, chars)
    except TypeError:
        # Python 3.x
        table = {ord(char): None for char in chars}
        return str_.translate(table)

你可以使用re模块的正则表达式替换。使用^表达式可以准确地从字符串中选择想要的内容。

    import re
    text = "This is absurd!"
    text = re.sub("[^a-zA-Z]","",text) # Keeps only Alphabets
    print(text)

输出结果将是“这是荒谬的”。只有在^符号之后指定的内容才会出现。