我想知道如何仅根据信用卡的号码来判断信用卡的类型。有谁知道确定可靠的方法吗?
当前回答
更新日期:2016年6月15日(目前为最终解决方案)
请注意，我甚至放弃投票给一个被投票最多的，但为了明确这些是regexp实际上是有效的，我用数千个真实的BIN代码测试了它。最重要的是使用开始字符串(^)，否则在现实世界中会给出错误的结果!
JCB ^(?:2131|1800|35)[0-9]{0，}$开始:2131,1800,35 (3528-3589)
美国运通^3[47][0-9]{0，}$以:34,37开头
大莱卡^ 3(?:0(0-59){1}|[689])[0 - 9]{0}$开头:300 - 305年,309年,36岁,38-39
Visa ^4[0-9]{0，}$以:4开头
万事达卡^(5[1 - 5]| 222(1 - 9)| 22(3 - 9)| 2(3 - 6)| 27[01]| 2720)[0 - 9]{0}$开头:2221 - 2720,51-55
Maestro ^(5[06789]|6)[0-9]{0，}$ Maestro总是在范围内增长:60-69，以/开始，但开始5必须编码为万事达卡。大师卡必须在代码的末尾被检测到，因为其他一些卡的范围在60-69之间。请看代码。
发现^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0，}$发现很难编码，从:6011,622126 - 622925,644 -649,65开始
在javascript中，我使用这个函数。当你把它分配给一个onkeyup事件并尽快给出结果时，这是很好的。
function cc_brand_id(cur_val) {
// the regular expressions check for possible matches as you type, hence the OR operators based on the number of chars
// regexp string length {0} provided for soonest detection of beginning of the card numbers this way it could be used for BIN CODE detection also
//JCB
jcb_regex = new RegExp('^(?:2131|1800|35)[0-9]{0,}$'); //2131, 1800, 35 (3528-3589)
// American Express
amex_regex = new RegExp('^3[47][0-9]{0,}$'); //34, 37
// Diners Club
diners_regex = new RegExp('^3(?:0[0-59]{1}|[689])[0-9]{0,}$'); //300-305, 309, 36, 38-39
// Visa
visa_regex = new RegExp('^4[0-9]{0,}$'); //4
// MasterCard
mastercard_regex = new RegExp('^(5[1-5]|222[1-9]|22[3-9]|2[3-6]|27[01]|2720)[0-9]{0,}$'); //2221-2720, 51-55
maestro_regex = new RegExp('^(5[06789]|6)[0-9]{0,}$'); //always growing in the range: 60-69, started with / not something else, but starting 5 must be encoded as mastercard anyway
//Discover
discover_regex = new RegExp('^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0,}$');
////6011, 622126-622925, 644-649, 65
// get rid of anything but numbers
cur_val = cur_val.replace(/\D/g, '');
// checks per each, as their could be multiple hits
//fix: ordering matter in detection, otherwise can give false results in rare cases
var sel_brand = "unknown";
if (cur_val.match(jcb_regex)) {
sel_brand = "jcb";
} else if (cur_val.match(amex_regex)) {
sel_brand = "amex";
} else if (cur_val.match(diners_regex)) {
sel_brand = "diners_club";
} else if (cur_val.match(visa_regex)) {
sel_brand = "visa";
} else if (cur_val.match(mastercard_regex)) {
sel_brand = "mastercard";
} else if (cur_val.match(discover_regex)) {
sel_brand = "discover";
} else if (cur_val.match(maestro_regex)) {
if (cur_val[0] == '5') { //started 5 must be mastercard
sel_brand = "mastercard";
} else {
sel_brand = "maestro"; //maestro is all 60-69 which is not something else, thats why this condition in the end
}
}
return sel_brand;
}
在这里你可以玩它:
http://jsfiddle.net/upN3L/69/
对于PHP使用这个函数，它也会检测一些子VISA/MC卡:
/**
* Obtain a brand constant from a PAN
*
* @param string $pan Credit card number
* @param bool $include_sub_types Include detection of sub visa brands
* @return string
*/
public static function getCardBrand($pan, $include_sub_types = false)
{
//maximum length is not fixed now, there are growing number of CCs has more numbers in length, limiting can give false negatives atm
//these regexps accept not whole cc numbers too
//visa
$visa_regex = "/^4[0-9]{0,}$/";
$vpreca_regex = "/^428485[0-9]{0,}$/";
$postepay_regex = "/^(402360|402361|403035|417631|529948){0,}$/";
$cartasi_regex = "/^(432917|432930|453998)[0-9]{0,}$/";
$entropay_regex = "/^(406742|410162|431380|459061|533844|522093)[0-9]{0,}$/";
$o2money_regex = "/^(422793|475743)[0-9]{0,}$/";
// MasterCard
$mastercard_regex = "/^(5[1-5]|222[1-9]|22[3-9]|2[3-6]|27[01]|2720)[0-9]{0,}$/";
$maestro_regex = "/^(5[06789]|6)[0-9]{0,}$/";
$kukuruza_regex = "/^525477[0-9]{0,}$/";
$yunacard_regex = "/^541275[0-9]{0,}$/";
// American Express
$amex_regex = "/^3[47][0-9]{0,}$/";
// Diners Club
$diners_regex = "/^3(?:0[0-59]{1}|[689])[0-9]{0,}$/";
//Discover
$discover_regex = "/^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0,}$/";
//JCB
$jcb_regex = "/^(?:2131|1800|35)[0-9]{0,}$/";
//ordering matter in detection, otherwise can give false results in rare cases
if (preg_match($jcb_regex, $pan)) {
return "jcb";
}
if (preg_match($amex_regex, $pan)) {
return "amex";
}
if (preg_match($diners_regex, $pan)) {
return "diners_club";
}
//sub visa/mastercard cards
if ($include_sub_types) {
if (preg_match($vpreca_regex, $pan)) {
return "v-preca";
}
if (preg_match($postepay_regex, $pan)) {
return "postepay";
}
if (preg_match($cartasi_regex, $pan)) {
return "cartasi";
}
if (preg_match($entropay_regex, $pan)) {
return "entropay";
}
if (preg_match($o2money_regex, $pan)) {
return "o2money";
}
if (preg_match($kukuruza_regex, $pan)) {
return "kukuruza";
}
if (preg_match($yunacard_regex, $pan)) {
return "yunacard";
}
}
if (preg_match($visa_regex, $pan)) {
return "visa";
}
if (preg_match($mastercard_regex, $pan)) {
return "mastercard";
}
if (preg_match($discover_regex, $pan)) {
return "discover";
}
if (preg_match($maestro_regex, $pan)) {
if ($pan[0] == '5') { //started 5 must be mastercard
return "mastercard";
}
return "maestro"; //maestro is all 60-69 which is not something else, thats why this condition in the end
}
return "unknown"; //unknown for this system
}
其他回答
// abobjects.com, parvez ahmad ab bulk mailer
use below script
function isValidCreditCard2(type, ccnum) {
if (type == "Visa") {
// Visa: length 16, prefix 4, dashes optional.
var re = /^4\d{3}?\d{4}?\d{4}?\d{4}$/;
} else if (type == "MasterCard") {
// Mastercard: length 16, prefix 51-55, dashes optional.
var re = /^5[1-5]\d{2}?\d{4}?\d{4}?\d{4}$/;
} else if (type == "Discover") {
// Discover: length 16, prefix 6011, dashes optional.
var re = /^6011?\d{4}?\d{4}?\d{4}$/;
} else if (type == "AmEx") {
// American Express: length 15, prefix 34 or 37.
var re = /^3[4,7]\d{13}$/;
} else if (type == "Diners") {
// Diners: length 14, prefix 30, 36, or 38.
var re = /^3[0,6,8]\d{12}$/;
}
if (!re.test(ccnum)) return false;
return true;
/*
// Remove all dashes for the checksum checks to eliminate negative numbers
ccnum = ccnum.split("-").join("");
// Checksum ("Mod 10")
// Add even digits in even length strings or odd digits in odd length strings.
var checksum = 0;
for (var i=(2-(ccnum.length % 2)); i<=ccnum.length; i+=2) {
checksum += parseInt(ccnum.charAt(i-1));
}
// Analyze odd digits in even length strings or even digits in odd length strings.
for (var i=(ccnum.length % 2) + 1; i<ccnum.length; i+=2) {
var digit = parseInt(ccnum.charAt(i-1)) * 2;
if (digit < 10) { checksum += digit; } else { checksum += (digit-9); }
}
if ((checksum % 10) == 0) return true; else return false;
*/
}
jQuery.validator.addMethod("isValidCreditCard", function(postalcode, element) {
return isValidCreditCard2($("#cardType").val(), $("#cardNum").val());
}, "<br>credit card is invalid");
Type</td>
<td class="text"> <form:select path="cardType" cssclass="fields" style="border: 1px solid #D5D5D5;padding: 0px 0px 0px 0px;width: 130px;height: 22px;">
<option value="SELECT">SELECT</option>
<option value="MasterCard">Mastercard</option>
<option value="Visa">Visa</option>
<option value="AmEx">American Express</option>
<option value="Discover">Discover</option>
</form:select> <font color="#FF0000">*</font>
$("#signupForm").validate({
rules:{
companyName:{required: true},
address1:{required: true},
city:{required: true},
state:{required: true},
zip:{required: true},
country:{required: true},
chkAgree:{required: true},
confPassword:{required: true},
lastName:{required: true},
firstName:{required: true},
ccAddress1:{required: true},
ccZip:{
postalcode : true
},
phone:{required: true},
email:{
required: true,
email: true
},
userName:{
required: true,
minlength: 6
},
password:{
required: true,
minlength: 6
},
cardNum:{
isValidCreditCard : true
},
卡号的前六位数字(包括初始信息信息) 数字)被称为发行者识别号码(IIN)。这些 识别向该卡发行该卡的发卡机构 持有人。其余的数字由发卡机构分配。的 卡号的长度是它的位数。许多发卡机构打印 他们卡上的整个IIN和账号。
基于以上事实，我想保留一段JAVA代码来识别卡片品牌。
样卡类型
public static final String AMERICAN_EXPRESS = "American Express";
public static final String DISCOVER = "Discover";
public static final String JCB = "JCB";
public static final String DINERS_CLUB = "Diners Club";
public static final String VISA = "Visa";
public static final String MASTERCARD = "MasterCard";
public static final String UNKNOWN = "Unknown";
卡前缀
// Based on http://en.wikipedia.org/wiki/Bank_card_number#Issuer_identification_number_.28IIN.29
public static final String[] PREFIXES_AMERICAN_EXPRESS = {"34", "37"};
public static final String[] PREFIXES_DISCOVER = {"60", "62", "64", "65"};
public static final String[] PREFIXES_JCB = {"35"};
public static final String[] PREFIXES_DINERS_CLUB = {"300", "301", "302", "303", "304", "305", "309", "36", "38", "39"};
public static final String[] PREFIXES_VISA = {"4"};
public static final String[] PREFIXES_MASTERCARD = {
"2221", "2222", "2223", "2224", "2225", "2226", "2227", "2228", "2229",
"223", "224", "225", "226", "227", "228", "229",
"23", "24", "25", "26",
"270", "271", "2720",
"50", "51", "52", "53", "54", "55"
};
检查输入的数字是否有任何给定的前缀。
public String getBrand(String number) {
String evaluatedType;
if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_AMERICAN_EXPRESS)) {
evaluatedType = AMERICAN_EXPRESS;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_DISCOVER)) {
evaluatedType = DISCOVER;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_JCB)) {
evaluatedType = JCB;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_DINERS_CLUB)) {
evaluatedType = DINERS_CLUB;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_VISA)) {
evaluatedType = VISA;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_MASTERCARD)) {
evaluatedType = MASTERCARD;
} else {
evaluatedType = UNKNOWN;
}
return evaluatedType;
}
最后，效用方法
/**
* Check to see if the input number has any of the given prefixes.
*
* @param number the number to test
* @param prefixes the prefixes to test against
* @return {@code true} if number begins with any of the input prefixes
*/
public static boolean hasAnyPrefix(String number, String... prefixes) {
if (number == null) {
return false;
}
for (String prefix : prefixes) {
if (number.startsWith(prefix)) {
return true;
}
}
return false;
}
参考
条纹卡生成器
试试kotlin。添加Regex并添加到when语句中。
private fun getCardType(number: String): String {
val visa = Regex("^4[0-9]{12}(?:[0-9]{3})?$")
val mastercard = Regex("^5[1-5][0-9]{14}$")
val amx = Regex("^3[47][0-9]{13}$")
return when {
visa.matches(number) -> "Visa"
mastercard.matches(number) -> "Mastercard"
amx.matches(number) -> "American Express"
else -> "Unknown"
}
}
一个javascript改进的@Anatoliy答案
function getCardType (number) { const numberFormated = number.replace(/\D/g, '') var patterns = { VISA: /^4[0-9]{12}(?:[0-9]{3})?$/, MASTER: /^5[1-5][0-9]{14}$/, AMEX: /^3[47][0-9]{13}$/, ELO: /^((((636368)|(438935)|(504175)|(451416)|(636297))\d{0,10})|((5067)|(4576)|(4011))\d{0,12})$/, AURA: /^(5078\d{2})(\d{2})(\d{11})$/, JCB: /^(?:2131|1800|35\d{3})\d{11}$/, DINERS: /^3(?:0[0-5]|[68][0-9])[0-9]{11}$/, DISCOVERY: /^6(?:011|5[0-9]{2})[0-9]{12}$/, HIPERCARD: /^(606282\d{10}(\d{3})?)|(3841\d{15})$/, ELECTRON: /^(4026|417500|4405|4508|4844|4913|4917)\d+$/, MAESTRO: /^(5018|5020|5038|5612|5893|6304|6759|6761|6762|6763|0604|6390)\d+$/, DANKORT: /^(5019)\d+$/, INTERPAYMENT: /^(636)\d+$/, UNIONPAY: /^(62|88)\d+$/, } for (var key in patterns) { if (patterns[key].test(numberFormated)) { return key } } } console.log(getCardType("4539 5684 7526 2091"))
我用jQuery的解决方案:
function detectCreditCardType() {
var type = new Array;
type[1] = '^4[0-9]{12}(?:[0-9]{3})?$'; // visa
type[2] = '^5[1-5][0-9]{14}$'; // mastercard
type[3] = '^6(?:011|5[0-9]{2})[0-9]{12}$'; // discover
type[4] = '^3[47][0-9]{13}$'; // amex
var ccnum = $('.creditcard').val().replace(/[^\d.]/g, '');
var returntype = 0;
$.each(type, function(idx, re) {
var regex = new RegExp(re);
if(regex.test(ccnum) && idx>0) {
returntype = idx;
}
});
return returntype;
}
如果返回0，则未检测到信用卡类型。
“creditcard”类应该添加到creditcard输入字段中。
