我想知道如何仅根据信用卡的号码来判断信用卡的类型。有谁知道确定可靠的方法吗?


当前回答

另一个api解决方案在rapidapi银行卡位数检查有250K+发行卡类型。

只有一个GET rest api请求,并获得发卡机构信息,如:

{ "bin_number": 535177, "bank": "Finansbank A.S.", "scheme": "MASTERCARD", "type": "Debit", "country": "Turkey" }

其他回答

我用jQuery的解决方案:

function detectCreditCardType() {
    var type = new Array;
    type[1] = '^4[0-9]{12}(?:[0-9]{3})?$';      // visa
    type[2] = '^5[1-5][0-9]{14}$';              // mastercard
    type[3] = '^6(?:011|5[0-9]{2})[0-9]{12}$';  // discover
    type[4] = '^3[47][0-9]{13}$';               // amex

    var ccnum = $('.creditcard').val().replace(/[^\d.]/g, '');
    var returntype = 0;

    $.each(type, function(idx, re) {
        var regex = new RegExp(re);
        if(regex.test(ccnum) && idx>0) {
            returntype = idx;
        }
    });

    return returntype;
}

如果返回0,则未检测到信用卡类型。

“creditcard”类应该添加到creditcard输入字段中。

斯威夫特 5+

extension String {
    
    func isMatch(_ Regex: String) -> Bool {
        
        do {
            let regex = try NSRegularExpression(pattern: Regex)
            let results = regex.matches(in: self, range: NSRange(self.startIndex..., in: self))
            return results.map {
                String(self[Range($0.range, in: self)!])
            }.count > 0
        } catch {
            return false
        }
        
    }
    
    func getCreditCardType() -> String? {
        
        let VISA_Regex = "^4[0-9]{6,}$"
        let MasterCard_Regex = "^5[1-5][0-9]{5,}|222[1-9][0-9]{3,}|22[3-9][0-9]{4,}|2[3-6][0-9]{5,}|27[01][0-9]{4,}|2720[0-9]{3,}$"
        let AmericanExpress_Regex = "^3[47][0-9]{5,}$"
        let DinersClub_Regex = "^3(?:0[0-5]|[68][0-9])[0-9]{4,}$"
        let Discover_Regex = "^6(?:011|5[0-9]{2})[0-9]{3,}$"
        let JCB_Regex = "^(?:2131|1800|35[0-9]{3})[0-9]{3,}$"
        
        if self.isMatch(VISA_Regex) {
            return "VISA"
        } else if self.isMatch(MasterCard_Regex) {
            return "MasterCard"
        } else if self.isMatch(AmericanExpress_Regex) {
            return "AmericanExpress"
        } else if self.isMatch(DinersClub_Regex) {
            return "DinersClub"
        } else if self.isMatch(Discover_Regex) {
            return "Discover"
        } else if self.isMatch(JCB_Regex) {
            return "JCB"
        } else {
            return nil
        }
        
    }
    
}

使用。

"1234123412341234".getCreditCardType()

压缩javascript版本

    var getCardType = function (number) {
        var cards = {
            visa: /^4[0-9]{12}(?:[0-9]{3})?$/,
            mastercard: /^5[1-5][0-9]{14}$/,
            amex: /^3[47][0-9]{13}$/,
            diners: /^3(?:0[0-5]|[68][0-9])[0-9]{11}$/,
            discover: /^6(?:011|5[0-9]{2})[0-9]{12}$/,
            jcb: /^(?:2131|1800|35\d{3})\d{11}$/
        };
        for (var card in cards) {
            if (cards[card].test(number)) {
                return card;
            }
        }
    };

这是一个php类函数,通过CCnumber返回CCtype。 此代码不验证卡或不运行Luhn算法仅尝试查找基于本页表的信用卡类型。基本上使用CCnumber长度和CCcard前缀来确定CCcard类型。

<?php
class CreditcardType
{
    public static $creditcardTypes = [
        [
            'Name' => 'American Express',
            'cardLength' => [15],
            'cardPrefix' => ['34', '37'],
        ], [
            'Name' => 'Maestro',
            'cardLength' => [12, 13, 14, 15, 16, 17, 18, 19],
            'cardPrefix' => ['5018', '5020', '5038', '6304', '6759', '6761', '6763'],
        ], [
            'Name' => 'Mastercard',
            'cardLength' => [16],
            'cardPrefix' => ['51', '52', '53', '54', '55'],
        ], [
            'Name' => 'Visa',
            'cardLength' => [13, 16],
            'cardPrefix' => ['4'],
        ], [
            'Name' => 'JCB',
            'cardLength' => [16],
            'cardPrefix' => ['3528', '3529', '353', '354', '355', '356', '357', '358'],
        ], [
            'Name' => 'Discover',
            'cardLength' => [16],
            'cardPrefix' => ['6011', '622126', '622127', '622128', '622129', '62213','62214', '62215', '62216', '62217', '62218', '62219','6222', '6223', '6224', '6225', '6226', '6227', '6228','62290', '62291', '622920', '622921', '622922', '622923','622924', '622925', '644', '645', '646', '647', '648','649', '65'],
        ], [
            'Name' => 'Solo',
            'cardLength' => [16, 18, 19],
            'cardPrefix' => ['6334', '6767'],
        ], [
            'Name' => 'Unionpay',
            'cardLength' => [16, 17, 18, 19],
            'cardPrefix' => ['622126', '622127', '622128', '622129', '62213', '62214','62215', '62216', '62217', '62218', '62219', '6222', '6223','6224', '6225', '6226', '6227', '6228', '62290', '62291','622920', '622921', '622922', '622923', '622924', '622925'],
        ], [
            'Name' => 'Diners Club',
            'cardLength' => [14],
            'cardPrefix' => ['300', '301', '302', '303', '304', '305', '36'],
        ], [
            'Name' => 'Diners Club US',
            'cardLength' => [16],
            'cardPrefix' => ['54', '55'],
        ], [
            'Name' => 'Diners Club Carte Blanche',
            'cardLength' => [14],
            'cardPrefix' => ['300', '305'],
        ], [
            'Name' => 'Laser',
            'cardLength' => [16, 17, 18, 19],
            'cardPrefix' => ['6304', '6706', '6771', '6709'],
        ],
    ];

    public static function getType($CCNumber)
    {
        $CCNumber = trim($CCNumber);
        $type = 'Unknown';
        foreach (CreditcardType::$creditcardTypes as $card) {
            if (! in_array(strlen($CCNumber), $card['cardLength'])) {
                continue;
            }
            $prefixes = '/^(' . implode('|', $card['cardPrefix']) . ')/';
            if (preg_match($prefixes, $CCNumber) == 1) {
                $type = $card['Name'];
                break;
            }
        }
        return $type;
    }
}

更新日期:2016年6月15日(目前为最终解决方案)

请注意,我甚至放弃投票给一个被投票最多的,但为了明确这些是regexp实际上是有效的,我用数千个真实的BIN代码测试了它。最重要的是使用开始字符串(^),否则在现实世界中会给出错误的结果!

JCB ^(?:2131|1800|35)[0-9]{0,}$开始:2131,1800,35 (3528-3589)

美国运通^3[47][0-9]{0,}$以:34,37开头

大莱卡^ 3(?:0(0-59){1}|[689])[0 - 9]{0}$开头:300 - 305年,309年,36岁,38-39

Visa ^4[0-9]{0,}$以:4开头

万事达卡^(5[1 - 5]| 222(1 - 9)| 22(3 - 9)| 2(3 - 6)| 27[01]| 2720)[0 - 9]{0}$开头:2221 - 2720,51-55

Maestro ^(5[06789]|6)[0-9]{0,}$ Maestro总是在范围内增长:60-69,以/开始,但开始5必须编码为万事达卡。大师卡必须在代码的末尾被检测到,因为其他一些卡的范围在60-69之间。请看代码。

发现^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0,}$发现很难编码,从:6011,622126 - 622925,644 -649,65开始

在javascript中,我使用这个函数。当你把它分配给一个onkeyup事件并尽快给出结果时,这是很好的。

function cc_brand_id(cur_val) {
    // the regular expressions check for possible matches as you type, hence the OR operators based on the number of chars
    // regexp string length {0} provided for soonest detection of beginning of the card numbers this way it could be used for BIN CODE detection also

    //JCB
    jcb_regex = new RegExp('^(?:2131|1800|35)[0-9]{0,}$'); //2131, 1800, 35 (3528-3589)
    // American Express
    amex_regex = new RegExp('^3[47][0-9]{0,}$'); //34, 37
    // Diners Club
    diners_regex = new RegExp('^3(?:0[0-59]{1}|[689])[0-9]{0,}$'); //300-305, 309, 36, 38-39
    // Visa
    visa_regex = new RegExp('^4[0-9]{0,}$'); //4
    // MasterCard
    mastercard_regex = new RegExp('^(5[1-5]|222[1-9]|22[3-9]|2[3-6]|27[01]|2720)[0-9]{0,}$'); //2221-2720, 51-55
    maestro_regex = new RegExp('^(5[06789]|6)[0-9]{0,}$'); //always growing in the range: 60-69, started with / not something else, but starting 5 must be encoded as mastercard anyway
    //Discover
    discover_regex = new RegExp('^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0,}$');
    ////6011, 622126-622925, 644-649, 65


    // get rid of anything but numbers
    cur_val = cur_val.replace(/\D/g, '');

    // checks per each, as their could be multiple hits
    //fix: ordering matter in detection, otherwise can give false results in rare cases
    var sel_brand = "unknown";
    if (cur_val.match(jcb_regex)) {
        sel_brand = "jcb";
    } else if (cur_val.match(amex_regex)) {
        sel_brand = "amex";
    } else if (cur_val.match(diners_regex)) {
        sel_brand = "diners_club";
    } else if (cur_val.match(visa_regex)) {
        sel_brand = "visa";
    } else if (cur_val.match(mastercard_regex)) {
        sel_brand = "mastercard";
    } else if (cur_val.match(discover_regex)) {
        sel_brand = "discover";
    } else if (cur_val.match(maestro_regex)) {
        if (cur_val[0] == '5') { //started 5 must be mastercard
            sel_brand = "mastercard";
        } else {
            sel_brand = "maestro"; //maestro is all 60-69 which is not something else, thats why this condition in the end
        }
    }

    return sel_brand;
}

在这里你可以玩它:

http://jsfiddle.net/upN3L/69/

对于PHP使用这个函数,它也会检测一些子VISA/MC卡:

/**
  * Obtain a brand constant from a PAN
  *
  * @param string $pan               Credit card number
  * @param bool   $include_sub_types Include detection of sub visa brands
  * @return string
  */
public static function getCardBrand($pan, $include_sub_types = false)
{
    //maximum length is not fixed now, there are growing number of CCs has more numbers in length, limiting can give false negatives atm

    //these regexps accept not whole cc numbers too
    //visa
    $visa_regex = "/^4[0-9]{0,}$/";
    $vpreca_regex = "/^428485[0-9]{0,}$/";
    $postepay_regex = "/^(402360|402361|403035|417631|529948){0,}$/";
    $cartasi_regex = "/^(432917|432930|453998)[0-9]{0,}$/";
    $entropay_regex = "/^(406742|410162|431380|459061|533844|522093)[0-9]{0,}$/";
    $o2money_regex = "/^(422793|475743)[0-9]{0,}$/";

    // MasterCard
    $mastercard_regex = "/^(5[1-5]|222[1-9]|22[3-9]|2[3-6]|27[01]|2720)[0-9]{0,}$/";
    $maestro_regex = "/^(5[06789]|6)[0-9]{0,}$/";
    $kukuruza_regex = "/^525477[0-9]{0,}$/";
    $yunacard_regex = "/^541275[0-9]{0,}$/";

    // American Express
    $amex_regex = "/^3[47][0-9]{0,}$/";

    // Diners Club
    $diners_regex = "/^3(?:0[0-59]{1}|[689])[0-9]{0,}$/";

    //Discover
    $discover_regex = "/^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0,}$/";

    //JCB
    $jcb_regex = "/^(?:2131|1800|35)[0-9]{0,}$/";

    //ordering matter in detection, otherwise can give false results in rare cases
    if (preg_match($jcb_regex, $pan)) {
        return "jcb";
    }

    if (preg_match($amex_regex, $pan)) {
        return "amex";
    }

    if (preg_match($diners_regex, $pan)) {
        return "diners_club";
    }

    //sub visa/mastercard cards
    if ($include_sub_types) {
        if (preg_match($vpreca_regex, $pan)) {
            return "v-preca";
        }
        if (preg_match($postepay_regex, $pan)) {
            return "postepay";
        }
        if (preg_match($cartasi_regex, $pan)) {
            return "cartasi";
        }
        if (preg_match($entropay_regex, $pan)) {
            return "entropay";
        }
        if (preg_match($o2money_regex, $pan)) {
            return "o2money";
        }
        if (preg_match($kukuruza_regex, $pan)) {
            return "kukuruza";
        }
        if (preg_match($yunacard_regex, $pan)) {
            return "yunacard";
        }
    }

    if (preg_match($visa_regex, $pan)) {
        return "visa";
    }

    if (preg_match($mastercard_regex, $pan)) {
        return "mastercard";
    }

    if (preg_match($discover_regex, $pan)) {
        return "discover";
    }

    if (preg_match($maestro_regex, $pan)) {
        if ($pan[0] == '5') { //started 5 must be mastercard
            return "mastercard";
        }
        return "maestro"; //maestro is all 60-69 which is not something else, thats why this condition in the end

    }

    return "unknown"; //unknown for this system
}