我想知道如何仅根据信用卡的号码来判断信用卡的类型。有谁知道确定可靠的方法吗?
当前回答
我搜索了很多信用卡格式和电话号码格式。找到了很多好的提示,但没有一个真正符合我的需求,所以我创建了这段代码。你可以这样使用它:
var sf = smartForm.formatCC(myInputString);
var cardType = sf.cardType;
其他回答
信用卡的第一个数字可以用来大致了解供应商:
签证:49、44或47 Visa电子:42、45、48、49 万事达卡:51 美国运通:34 就餐者:30、36、38 JCB: 35
看看这个:
http://www.breakingpar.com/bkp/home.nsf/0/87256B280015193F87256CC70060A01B
function isValidCreditCard(type, ccnum) {
/* Visa: length 16, prefix 4, dashes optional.
Mastercard: length 16, prefix 51-55, dashes optional.
Discover: length 16, prefix 6011, dashes optional.
American Express: length 15, prefix 34 or 37.
Diners: length 14, prefix 30, 36, or 38. */
var re = new Regex({
"visa": "/^4\d{3}-?\d{4}-?\d{4}-?\d",
"mc": "/^5[1-5]\d{2}-?\d{4}-?\d{4}-?\d{4}$/",
"disc": "/^6011-?\d{4}-?\d{4}-?\d{4}$/",
"amex": "/^3[47]\d{13}$/",
"diners": "/^3[068]\d{12}$/"
}[type.toLowerCase()])
if (!re.test(ccnum)) return false;
// Remove all dashes for the checksum checks to eliminate negative numbers
ccnum = ccnum.split("-").join("");
// Checksum ("Mod 10")
// Add even digits in even length strings or odd digits in odd length strings.
var checksum = 0;
for (var i = (2 - (ccnum.length % 2)); i <= ccnum.length; i += 2) {
checksum += parseInt(ccnum.charAt(i - 1));
}
// Analyze odd digits in even length strings or even digits in odd length strings.
for (var i = (ccnum.length % 2) + 1; i < ccnum.length; i += 2) {
var digit = parseInt(ccnum.charAt(i - 1)) * 2;
if (digit < 10) { checksum += digit; } else { checksum += (digit - 9); }
}
if ((checksum % 10) == 0) return true;
else return false;
}
anatoly用PHP回答:
public static function detectCardType($num)
{
$re = array(
"visa" => "/^4[0-9]{12}(?:[0-9]{3})?$/",
"mastercard" => "/^5[1-5][0-9]{14}$/",
"amex" => "/^3[47][0-9]{13}$/",
"discover" => "/^6(?:011|5[0-9]{2})[0-9]{12}$/",
);
if (preg_match($re['visa'],$num))
{
return 'visa';
}
else if (preg_match($re['mastercard'],$num))
{
return 'mastercard';
}
else if (preg_match($re['amex'],$num))
{
return 'amex';
}
else if (preg_match($re['discover'],$num))
{
return 'discover';
}
else
{
return false;
}
}
斯威夫特 5+
extension String {
func isMatch(_ Regex: String) -> Bool {
do {
let regex = try NSRegularExpression(pattern: Regex)
let results = regex.matches(in: self, range: NSRange(self.startIndex..., in: self))
return results.map {
String(self[Range($0.range, in: self)!])
}.count > 0
} catch {
return false
}
}
func getCreditCardType() -> String? {
let VISA_Regex = "^4[0-9]{6,}$"
let MasterCard_Regex = "^5[1-5][0-9]{5,}|222[1-9][0-9]{3,}|22[3-9][0-9]{4,}|2[3-6][0-9]{5,}|27[01][0-9]{4,}|2720[0-9]{3,}$"
let AmericanExpress_Regex = "^3[47][0-9]{5,}$"
let DinersClub_Regex = "^3(?:0[0-5]|[68][0-9])[0-9]{4,}$"
let Discover_Regex = "^6(?:011|5[0-9]{2})[0-9]{3,}$"
let JCB_Regex = "^(?:2131|1800|35[0-9]{3})[0-9]{3,}$"
if self.isMatch(VISA_Regex) {
return "VISA"
} else if self.isMatch(MasterCard_Regex) {
return "MasterCard"
} else if self.isMatch(AmericanExpress_Regex) {
return "AmericanExpress"
} else if self.isMatch(DinersClub_Regex) {
return "DinersClub"
} else if self.isMatch(Discover_Regex) {
return "Discover"
} else if self.isMatch(JCB_Regex) {
return "JCB"
} else {
return nil
}
}
}
使用。
"1234123412341234".getCreditCardType()
压缩javascript版本
var getCardType = function (number) {
var cards = {
visa: /^4[0-9]{12}(?:[0-9]{3})?$/,
mastercard: /^5[1-5][0-9]{14}$/,
amex: /^3[47][0-9]{13}$/,
diners: /^3(?:0[0-5]|[68][0-9])[0-9]{11}$/,
discover: /^6(?:011|5[0-9]{2})[0-9]{12}$/,
jcb: /^(?:2131|1800|35\d{3})\d{11}$/
};
for (var card in cards) {
if (cards[card].test(number)) {
return card;
}
}
};