我想知道如何仅根据信用卡的号码来判断信用卡的类型。有谁知道确定可靠的方法吗?
当前回答
Usman Y回答的Swift 2.1版本。 使用print语句来验证，因此调用某个字符串值
print(self.validateCardType(self.creditCardField.text!))
func validateCardType(testCard: String) -> String {
let regVisa = "^4[0-9]{12}(?:[0-9]{3})?$"
let regMaster = "^5[1-5][0-9]{14}$"
let regExpress = "^3[47][0-9]{13}$"
let regDiners = "^3(?:0[0-5]|[68][0-9])[0-9]{11}$"
let regDiscover = "^6(?:011|5[0-9]{2})[0-9]{12}$"
let regJCB = "^(?:2131|1800|35\\d{3})\\d{11}$"
let regVisaTest = NSPredicate(format: "SELF MATCHES %@", regVisa)
let regMasterTest = NSPredicate(format: "SELF MATCHES %@", regMaster)
let regExpressTest = NSPredicate(format: "SELF MATCHES %@", regExpress)
let regDinersTest = NSPredicate(format: "SELF MATCHES %@", regDiners)
let regDiscoverTest = NSPredicate(format: "SELF MATCHES %@", regDiscover)
let regJCBTest = NSPredicate(format: "SELF MATCHES %@", regJCB)
if regVisaTest.evaluateWithObject(testCard){
return "Visa"
}
else if regMasterTest.evaluateWithObject(testCard){
return "MasterCard"
}
else if regExpressTest.evaluateWithObject(testCard){
return "American Express"
}
else if regDinersTest.evaluateWithObject(testCard){
return "Diners Club"
}
else if regDiscoverTest.evaluateWithObject(testCard){
return "Discover"
}
else if regJCBTest.evaluateWithObject(testCard){
return "JCB"
}
return ""
}
其他回答
最近我需要这样的功能，我将Zend框架信用卡验证器移植到ruby。 红宝石宝石:https://github.com/Fivell/credit_card_validations zend框架:https://github.com/zendframework/zf2/blob/master/library/Zend/Validator/CreditCard.php
它们都使用INN范围来检测类型。在这里你可以读到关于INN的信息
根据这一点，您可以选择检测信用卡(没有regexp，但声明一些关于前缀和可能长度的规则)
所以我们有关于最常用卡片的下一个规则
######## most used brands #########
visa: [
{length: [13, 16], prefixes: ['4']}
],
mastercard: [
{length: [16], prefixes: ['51', '52', '53', '54', '55']}
],
amex: [
{length: [15], prefixes: ['34', '37']}
],
######## other brands ########
diners: [
{length: [14], prefixes: ['300', '301', '302', '303', '304', '305', '36', '38']},
],
#There are Diners Club (North America) cards that begin with 5. These are a joint venture between Diners Club and MasterCard, and are processed like a MasterCard
# will be removed in next major version
diners_us: [
{length: [16], prefixes: ['54', '55']}
],
discover: [
{length: [16], prefixes: ['6011', '644', '645', '646', '647', '648',
'649', '65']}
],
jcb: [
{length: [16], prefixes: ['3528', '3529', '353', '354', '355', '356', '357', '358', '1800', '2131']}
],
laser: [
{length: [16, 17, 18, 19], prefixes: ['6304', '6706', '6771']}
],
solo: [
{length: [16, 18, 19], prefixes: ['6334', '6767']}
],
switch: [
{length: [16, 18, 19], prefixes: ['633110', '633312', '633304', '633303', '633301', '633300']}
],
maestro: [
{length: [12, 13, 14, 15, 16, 17, 18, 19], prefixes: ['5010', '5011', '5012', '5013', '5014', '5015', '5016', '5017', '5018',
'502', '503', '504', '505', '506', '507', '508',
'6012', '6013', '6014', '6015', '6016', '6017', '6018', '6019',
'602', '603', '604', '605', '6060',
'677', '675', '674', '673', '672', '671', '670',
'6760', '6761', '6762', '6763', '6764', '6765', '6766', '6768', '6769']}
],
# Luhn validation are skipped for union pay cards because they have unknown generation algoritm
unionpay: [
{length: [16, 17, 18, 19], prefixes: ['622', '624', '625', '626', '628'], skip_luhn: true}
],
dankrot: [
{length: [16], prefixes: ['5019']}
],
rupay: [
{length: [16], prefixes: ['6061', '6062', '6063', '6064', '6065', '6066', '6067', '6068', '6069', '607', '608'], skip_luhn: true}
]
}
然后通过搜索前缀和比较长度来检测信用卡品牌。也不要忘记luhn算法(在http://en.wikipedia.org/wiki/Luhn有描述)。
更新
更新的规则列表可以在这里找到https://raw.githubusercontent.com/Fivell/credit_card_validations/master/lib/data/brands.yaml
Usman Y回答的Swift 2.1版本。 使用print语句来验证，因此调用某个字符串值
print(self.validateCardType(self.creditCardField.text!))
func validateCardType(testCard: String) -> String {
let regVisa = "^4[0-9]{12}(?:[0-9]{3})?$"
let regMaster = "^5[1-5][0-9]{14}$"
let regExpress = "^3[47][0-9]{13}$"
let regDiners = "^3(?:0[0-5]|[68][0-9])[0-9]{11}$"
let regDiscover = "^6(?:011|5[0-9]{2})[0-9]{12}$"
let regJCB = "^(?:2131|1800|35\\d{3})\\d{11}$"
let regVisaTest = NSPredicate(format: "SELF MATCHES %@", regVisa)
let regMasterTest = NSPredicate(format: "SELF MATCHES %@", regMaster)
let regExpressTest = NSPredicate(format: "SELF MATCHES %@", regExpress)
let regDinersTest = NSPredicate(format: "SELF MATCHES %@", regDiners)
let regDiscoverTest = NSPredicate(format: "SELF MATCHES %@", regDiscover)
let regJCBTest = NSPredicate(format: "SELF MATCHES %@", regJCB)
if regVisaTest.evaluateWithObject(testCard){
return "Visa"
}
else if regMasterTest.evaluateWithObject(testCard){
return "MasterCard"
}
else if regExpressTest.evaluateWithObject(testCard){
return "American Express"
}
else if regDinersTest.evaluateWithObject(testCard){
return "Diners Club"
}
else if regDiscoverTest.evaluateWithObject(testCard){
return "Discover"
}
else if regJCBTest.evaluateWithObject(testCard){
return "JCB"
}
return ""
}
试试kotlin。添加Regex并添加到when语句中。
private fun getCardType(number: String): String {
val visa = Regex("^4[0-9]{12}(?:[0-9]{3})?$")
val mastercard = Regex("^5[1-5][0-9]{14}$")
val amx = Regex("^3[47][0-9]{13}$")
return when {
visa.matches(number) -> "Visa"
mastercard.matches(number) -> "Mastercard"
amx.matches(number) -> "American Express"
else -> "Unknown"
}
}
一个javascript改进的@Anatoliy答案
function getCardType (number) { const numberFormated = number.replace(/\D/g, '') var patterns = { VISA: /^4[0-9]{12}(?:[0-9]{3})?$/, MASTER: /^5[1-5][0-9]{14}$/, AMEX: /^3[47][0-9]{13}$/, ELO: /^((((636368)|(438935)|(504175)|(451416)|(636297))\d{0,10})|((5067)|(4576)|(4011))\d{0,12})$/, AURA: /^(5078\d{2})(\d{2})(\d{11})$/, JCB: /^(?:2131|1800|35\d{3})\d{11}$/, DINERS: /^3(?:0[0-5]|[68][0-9])[0-9]{11}$/, DISCOVERY: /^6(?:011|5[0-9]{2})[0-9]{12}$/, HIPERCARD: /^(606282\d{10}(\d{3})?)|(3841\d{15})$/, ELECTRON: /^(4026|417500|4405|4508|4844|4913|4917)\d+$/, MAESTRO: /^(5018|5020|5038|5612|5893|6304|6759|6761|6762|6763|0604|6390)\d+$/, DANKORT: /^(5019)\d+$/, INTERPAYMENT: /^(636)\d+$/, UNIONPAY: /^(62|88)\d+$/, } for (var key in patterns) { if (patterns[key].test(numberFormated)) { return key } } } console.log(getCardType("4539 5684 7526 2091"))
匹配对应卡供应商的正则表达式规则:
(4\d{12}(?:\d{3})?) (5[1-5]\d{14}) (3[47]\d{13})为美国运通。 ((?: 5020 | 5038 | 6304 | 6579 | 6761) \ d {12} (?: \ \ d) ?)大师。 (3(?:0[0-5]|[68][0-9])[0-9]{11}) (6(?:011|5[0-9]{2})[0-9]{12})用于发现。 (35[2-8][89]\d\d\d{10})
