我想知道如何仅根据信用卡的号码来判断信用卡的类型。有谁知道确定可靠的方法吗?
当前回答
卡号的前六位数字(包括初始信息信息) 数字)被称为发行者识别号码(IIN)。这些 识别向该卡发行该卡的发卡机构 持有人。其余的数字由发卡机构分配。的 卡号的长度是它的位数。许多发卡机构打印 他们卡上的整个IIN和账号。
基于以上事实，我想保留一段JAVA代码来识别卡片品牌。
样卡类型
public static final String AMERICAN_EXPRESS = "American Express";
public static final String DISCOVER = "Discover";
public static final String JCB = "JCB";
public static final String DINERS_CLUB = "Diners Club";
public static final String VISA = "Visa";
public static final String MASTERCARD = "MasterCard";
public static final String UNKNOWN = "Unknown";
卡前缀
// Based on http://en.wikipedia.org/wiki/Bank_card_number#Issuer_identification_number_.28IIN.29
public static final String[] PREFIXES_AMERICAN_EXPRESS = {"34", "37"};
public static final String[] PREFIXES_DISCOVER = {"60", "62", "64", "65"};
public static final String[] PREFIXES_JCB = {"35"};
public static final String[] PREFIXES_DINERS_CLUB = {"300", "301", "302", "303", "304", "305", "309", "36", "38", "39"};
public static final String[] PREFIXES_VISA = {"4"};
public static final String[] PREFIXES_MASTERCARD = {
"2221", "2222", "2223", "2224", "2225", "2226", "2227", "2228", "2229",
"223", "224", "225", "226", "227", "228", "229",
"23", "24", "25", "26",
"270", "271", "2720",
"50", "51", "52", "53", "54", "55"
};
检查输入的数字是否有任何给定的前缀。
public String getBrand(String number) {
String evaluatedType;
if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_AMERICAN_EXPRESS)) {
evaluatedType = AMERICAN_EXPRESS;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_DISCOVER)) {
evaluatedType = DISCOVER;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_JCB)) {
evaluatedType = JCB;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_DINERS_CLUB)) {
evaluatedType = DINERS_CLUB;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_VISA)) {
evaluatedType = VISA;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_MASTERCARD)) {
evaluatedType = MASTERCARD;
} else {
evaluatedType = UNKNOWN;
}
return evaluatedType;
}
最后，效用方法
/**
* Check to see if the input number has any of the given prefixes.
*
* @param number the number to test
* @param prefixes the prefixes to test against
* @return {@code true} if number begins with any of the input prefixes
*/
public static boolean hasAnyPrefix(String number, String... prefixes) {
if (number == null) {
return false;
}
for (String prefix : prefixes) {
if (number.startsWith(prefix)) {
return true;
}
}
return false;
}
参考
条纹卡生成器
其他回答
// abobjects.com, parvez ahmad ab bulk mailer
use below script
function isValidCreditCard2(type, ccnum) {
if (type == "Visa") {
// Visa: length 16, prefix 4, dashes optional.
var re = /^4\d{3}?\d{4}?\d{4}?\d{4}$/;
} else if (type == "MasterCard") {
// Mastercard: length 16, prefix 51-55, dashes optional.
var re = /^5[1-5]\d{2}?\d{4}?\d{4}?\d{4}$/;
} else if (type == "Discover") {
// Discover: length 16, prefix 6011, dashes optional.
var re = /^6011?\d{4}?\d{4}?\d{4}$/;
} else if (type == "AmEx") {
// American Express: length 15, prefix 34 or 37.
var re = /^3[4,7]\d{13}$/;
} else if (type == "Diners") {
// Diners: length 14, prefix 30, 36, or 38.
var re = /^3[0,6,8]\d{12}$/;
}
if (!re.test(ccnum)) return false;
return true;
/*
// Remove all dashes for the checksum checks to eliminate negative numbers
ccnum = ccnum.split("-").join("");
// Checksum ("Mod 10")
// Add even digits in even length strings or odd digits in odd length strings.
var checksum = 0;
for (var i=(2-(ccnum.length % 2)); i<=ccnum.length; i+=2) {
checksum += parseInt(ccnum.charAt(i-1));
}
// Analyze odd digits in even length strings or even digits in odd length strings.
for (var i=(ccnum.length % 2) + 1; i<ccnum.length; i+=2) {
var digit = parseInt(ccnum.charAt(i-1)) * 2;
if (digit < 10) { checksum += digit; } else { checksum += (digit-9); }
}
if ((checksum % 10) == 0) return true; else return false;
*/
}
jQuery.validator.addMethod("isValidCreditCard", function(postalcode, element) {
return isValidCreditCard2($("#cardType").val(), $("#cardNum").val());
}, "<br>credit card is invalid");
Type</td>
<td class="text"> <form:select path="cardType" cssclass="fields" style="border: 1px solid #D5D5D5;padding: 0px 0px 0px 0px;width: 130px;height: 22px;">
<option value="SELECT">SELECT</option>
<option value="MasterCard">Mastercard</option>
<option value="Visa">Visa</option>
<option value="AmEx">American Express</option>
<option value="Discover">Discover</option>
</form:select> <font color="#FF0000">*</font>
$("#signupForm").validate({
rules:{
companyName:{required: true},
address1:{required: true},
city:{required: true},
state:{required: true},
zip:{required: true},
country:{required: true},
chkAgree:{required: true},
confPassword:{required: true},
lastName:{required: true},
firstName:{required: true},
ccAddress1:{required: true},
ccZip:{
postalcode : true
},
phone:{required: true},
email:{
required: true,
email: true
},
userName:{
required: true,
minlength: 6
},
password:{
required: true,
minlength: 6
},
cardNum:{
isValidCreditCard : true
},
看看这个:
http://www.breakingpar.com/bkp/home.nsf/0/87256B280015193F87256CC70060A01B
function isValidCreditCard(type, ccnum) {
/* Visa: length 16, prefix 4, dashes optional.
Mastercard: length 16, prefix 51-55, dashes optional.
Discover: length 16, prefix 6011, dashes optional.
American Express: length 15, prefix 34 or 37.
Diners: length 14, prefix 30, 36, or 38. */
var re = new Regex({
"visa": "/^4\d{3}-?\d{4}-?\d{4}-?\d",
"mc": "/^5[1-5]\d{2}-?\d{4}-?\d{4}-?\d{4}$/",
"disc": "/^6011-?\d{4}-?\d{4}-?\d{4}$/",
"amex": "/^3[47]\d{13}$/",
"diners": "/^3[068]\d{12}$/"
}[type.toLowerCase()])
if (!re.test(ccnum)) return false;
// Remove all dashes for the checksum checks to eliminate negative numbers
ccnum = ccnum.split("-").join("");
// Checksum ("Mod 10")
// Add even digits in even length strings or odd digits in odd length strings.
var checksum = 0;
for (var i = (2 - (ccnum.length % 2)); i <= ccnum.length; i += 2) {
checksum += parseInt(ccnum.charAt(i - 1));
}
// Analyze odd digits in even length strings or even digits in odd length strings.
for (var i = (ccnum.length % 2) + 1; i < ccnum.length; i += 2) {
var digit = parseInt(ccnum.charAt(i - 1)) * 2;
if (digit < 10) { checksum += digit; } else { checksum += (digit - 9); }
}
if ((checksum % 10) == 0) return true;
else return false;
}
Usman Y回答的Swift 2.1版本。 使用print语句来验证，因此调用某个字符串值
print(self.validateCardType(self.creditCardField.text!))
func validateCardType(testCard: String) -> String {
let regVisa = "^4[0-9]{12}(?:[0-9]{3})?$"
let regMaster = "^5[1-5][0-9]{14}$"
let regExpress = "^3[47][0-9]{13}$"
let regDiners = "^3(?:0[0-5]|[68][0-9])[0-9]{11}$"
let regDiscover = "^6(?:011|5[0-9]{2})[0-9]{12}$"
let regJCB = "^(?:2131|1800|35\\d{3})\\d{11}$"
let regVisaTest = NSPredicate(format: "SELF MATCHES %@", regVisa)
let regMasterTest = NSPredicate(format: "SELF MATCHES %@", regMaster)
let regExpressTest = NSPredicate(format: "SELF MATCHES %@", regExpress)
let regDinersTest = NSPredicate(format: "SELF MATCHES %@", regDiners)
let regDiscoverTest = NSPredicate(format: "SELF MATCHES %@", regDiscover)
let regJCBTest = NSPredicate(format: "SELF MATCHES %@", regJCB)
if regVisaTest.evaluateWithObject(testCard){
return "Visa"
}
else if regMasterTest.evaluateWithObject(testCard){
return "MasterCard"
}
else if regExpressTest.evaluateWithObject(testCard){
return "American Express"
}
else if regDinersTest.evaluateWithObject(testCard){
return "Diners Club"
}
else if regDiscoverTest.evaluateWithObject(testCard){
return "Discover"
}
else if regJCBTest.evaluateWithObject(testCard){
return "JCB"
}
return ""
}
在swift中，您可以创建一个枚举来检测信用卡类型。
enum CreditCardType: Int { // Enum which encapsulates different card types and method to find the type of card.
case Visa
case Master
case Amex
case Discover
func validationRegex() -> String {
var regex = ""
switch self {
case .Visa:
regex = "^4[0-9]{6,}$"
case .Master:
regex = "^5[1-5][0-9]{5,}$"
case .Amex:
regex = "^3[47][0-9]{13}$"
case .Discover:
regex = "^6(?:011|5[0-9]{2})[0-9]{12}$"
}
return regex
}
func validate(cardNumber: String) -> Bool {
let predicate = NSPredicate(format: "SELF MATCHES %@", validationRegex())
return predicate.evaluateWithObject(cardNumber)
}
// Method returns the credit card type for given card number
static func cardTypeForCreditCardNumber(cardNumber: String) -> CreditCardType? {
var creditCardType: CreditCardType?
var index = 0
while let cardType = CreditCardType(rawValue: index) {
if cardType.validate(cardNumber) {
creditCardType = cardType
break
} else {
index++
}
}
return creditCardType
}
}
调用方法CreditCardType。cardTypeForCreditCardNumber(“#卡号”)返回CreditCardType enum值。
在卡牌范围识别(CRR)中，使用一系列正则表达式或其他硬编码范围的算法的一个缺点是，根据我的经验，bin / iin会随着时间的推移而变化。信用卡的联合品牌是一个持续的复杂问题。不同的购卡商/商家可能会要求你不同地对待同一张卡，这取决于例如地理位置。
Additionally, in the last few years with e.g. UnionPay cards in wider circulation, existing models do not cope with new ranges that sometimes interleave with broader ranges that they supersede. Knowing the geography your system needs to cover may help, as some ranges are restricted to use in particular countries. For example, ranges 62 include some AAA sub-ranges in the US, but if your merchant base is outside the US, you may be able to treat all 62 as UnionPay. You may be also asked to treat a card differently based on merchant location. E.g. to treat certain UK cards as debit domestically, but as credit internationally.
There are very useful set of rules maintained by one major Acquiring Bank. E.g. https://www.barclaycard.co.uk/business/files/BIN-Rules-EIRE.pdf and https://www.barclaycard.co.uk/business/files/BIN-Rules-UK.pdf. (Valid links as of June 2017, thanks to the user who provided a link to updated reference.) But be aware of the caveat that, while these CRR rules may represent the Card Issuing universe as it applies to the merchants acquired by that entity, it does not include e.g. ranges identified as CUP/UPI.
这些注释适用于磁条(MagStripe)或PKE (Pan Key Entry)场景。在ICC/EMV领域，情况又有所不同。
更新:本页上的其他答案(以及链接的维基百科页面)的JCB始终是16长。然而，在我的公司，我们有一个专门的工程师团队，他们在多个银行和地区认证我们的POS设备和软件。这个团队从JCB获得的最新认证卡包，有一个19长PAN的合格案例。
