我想知道如何仅根据信用卡的号码来判断信用卡的类型。有谁知道确定可靠的方法吗?


当前回答

下面是一些用Python编写的布尔函数的示例,如果根据函数名检测到卡片,则返回True。

def is_american_express(cc_number):
    """Checks if the card is an american express. If us billing address country code, & is_amex, use vpos
    https://en.wikipedia.org/wiki/Bank_card_number#cite_note-GenCardFeatures-3
    :param cc_number: unicode card number
    """
    return bool(re.match(r'^3[47][0-9]{13}$', cc_number))


def is_visa(cc_number):
    """Checks if the card is a visa, begins with 4 and 12 or 15 additional digits.
    :param cc_number: unicode card number
    """

    # Standard Visa is 13 or 16, debit can be 19
    if bool(re.match(r'^4', cc_number)) and len(cc_number) in [13, 16, 19]:
        return True

    return False


def is_mastercard(cc_number):
    """Checks if the card is a mastercard. Begins with 51-55 or 2221-2720 and 16 in length.
    :param cc_number: unicode card number
    """
    if len(cc_number) == 16 and cc_number.isdigit():  # Check digit, before cast to int
        return bool(re.match(r'^5[1-5]', cc_number)) or int(cc_number[:4]) in range(2221, 2721)
    return False


def is_discover(cc_number):
    """Checks if the card is discover, re would be too hard to maintain. Not a supported card.
    :param cc_number: unicode card number
    """
    if len(cc_number) == 16:
        try:
            # return bool(cc_number[:4] == '6011' or cc_number[:2] == '65' or cc_number[:6] in range(622126, 622926))
            return bool(cc_number[:4] == '6011' or cc_number[:2] == '65' or 622126 <= int(cc_number[:6]) <= 622925)
        except ValueError:
            return False
    return False


def is_jcb(cc_number):
    """Checks if the card is a jcb. Not a supported card.
    :param cc_number: unicode card number
    """
    # return bool(re.match(r'^(?:2131|1800|35\d{3})\d{11}$', cc_number))  # wikipedia
    return bool(re.match(r'^35(2[89]|[3-8][0-9])[0-9]{12}$', cc_number))  # PawelDecowski


def is_diners_club(cc_number):
    """Checks if the card is a diners club. Not a supported card.
    :param cc_number: unicode card number
    """
    return bool(re.match(r'^3(?:0[0-6]|[68][0-9])[0-9]{11}$', cc_number))  # 0-5 = carte blance, 6 = international


def is_laser(cc_number):
    """Checks if the card is laser. Not a supported card.
    :param cc_number: unicode card number
    """
    return bool(re.match(r'^(6304|670[69]|6771)', cc_number))


def is_maestro(cc_number):
    """Checks if the card is maestro. Not a supported card.
    :param cc_number: unicode card number
    """
    possible_lengths = [12, 13, 14, 15, 16, 17, 18, 19]
    return bool(re.match(r'^(50|5[6-9]|6[0-9])', cc_number)) and len(cc_number) in possible_lengths


# Child cards

def is_visa_electron(cc_number):
    """Child of visa. Checks if the card is a visa electron. Not a supported card.
    :param cc_number: unicode card number
    """
    return bool(re.match(r'^(4026|417500|4508|4844|491(3|7))', cc_number)) and len(cc_number) == 16


def is_total_rewards_visa(cc_number):
    """Child of visa. Checks if the card is a Total Rewards Visa. Not a supported card.
    :param cc_number: unicode card number
    """
    return bool(re.match(r'^41277777[0-9]{8}$', cc_number))


def is_diners_club_carte_blanche(cc_number):
    """Child card of diners. Checks if the card is a diners club carte blance. Not a supported card.
    :param cc_number: unicode card number
    """
    return bool(re.match(r'^30[0-5][0-9]{11}$', cc_number))  # github PawelDecowski, jquery-creditcardvalidator


def is_diners_club_carte_international(cc_number):
    """Child card of diners. Checks if the card is a diners club international. Not a supported card.
    :param cc_number: unicode card number
    """
    return bool(re.match(r'^36[0-9]{12}$', cc_number))  # jquery-creditcardvalidator

其他回答

public string GetCreditCardType(string CreditCardNumber)
{
    Regex regVisa = new Regex("^4[0-9]{12}(?:[0-9]{3})?$");
    Regex regMaster = new Regex("^5[1-5][0-9]{14}$");
    Regex regExpress = new Regex("^3[47][0-9]{13}$");
    Regex regDiners = new Regex("^3(?:0[0-5]|[68][0-9])[0-9]{11}$");
    Regex regDiscover = new Regex("^6(?:011|5[0-9]{2})[0-9]{12}$");
    Regex regJCB = new Regex("^(?:2131|1800|35\\d{3})\\d{11}$");


    if (regVisa.IsMatch(CreditCardNumber))
        return "VISA";
    else if (regMaster.IsMatch(CreditCardNumber))
        return "MASTER";
    else  if (regExpress.IsMatch(CreditCardNumber))
        return "AEXPRESS";
    else if (regDiners.IsMatch(CreditCardNumber))
        return "DINERS";
    else if (regDiscover.IsMatch(CreditCardNumber))
        return "DISCOVERS";
    else if (regJCB.IsMatch(CreditCardNumber))
        return "JCB";
    else
        return "invalid";
}

下面是使用Regex, c#检查信用卡类型的函数

卡号的前六位数字(包括初始信息信息) 数字)被称为发行者识别号码(IIN)。这些 识别向该卡发行该卡的发卡机构 持有人。其余的数字由发卡机构分配。的 卡号的长度是它的位数。许多发卡机构打印 他们卡上的整个IIN和账号。

基于以上事实,我想保留一段JAVA代码来识别卡片品牌。

样卡类型

public static final String AMERICAN_EXPRESS = "American Express";
public static final String DISCOVER = "Discover";
public static final String JCB = "JCB";
public static final String DINERS_CLUB = "Diners Club";
public static final String VISA = "Visa";
public static final String MASTERCARD = "MasterCard";
public static final String UNKNOWN = "Unknown";

卡前缀

// Based on http://en.wikipedia.org/wiki/Bank_card_number#Issuer_identification_number_.28IIN.29
public static final String[] PREFIXES_AMERICAN_EXPRESS = {"34", "37"};
public static final String[] PREFIXES_DISCOVER = {"60", "62", "64", "65"};
public static final String[] PREFIXES_JCB = {"35"};
public static final String[] PREFIXES_DINERS_CLUB = {"300", "301", "302", "303", "304", "305", "309", "36", "38", "39"};
public static final String[] PREFIXES_VISA = {"4"};
public static final String[] PREFIXES_MASTERCARD = {
        "2221", "2222", "2223", "2224", "2225", "2226", "2227", "2228", "2229",
        "223", "224", "225", "226", "227", "228", "229",
        "23", "24", "25", "26",
        "270", "271", "2720",
        "50", "51", "52", "53", "54", "55"
    };

检查输入的数字是否有任何给定的前缀。

public String getBrand(String number) {

String evaluatedType;
if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_AMERICAN_EXPRESS)) {
    evaluatedType = AMERICAN_EXPRESS;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_DISCOVER)) {
    evaluatedType = DISCOVER;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_JCB)) {
    evaluatedType = JCB;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_DINERS_CLUB)) {
    evaluatedType = DINERS_CLUB;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_VISA)) {
    evaluatedType = VISA;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_MASTERCARD)) {
    evaluatedType = MASTERCARD;
} else {
    evaluatedType = UNKNOWN;
}
    return evaluatedType;
}

最后,效用方法

/**
  * Check to see if the input number has any of the given prefixes.
  *
  * @param number the number to test
  * @param prefixes the prefixes to test against
  * @return {@code true} if number begins with any of the input prefixes
*/

public static boolean hasAnyPrefix(String number, String... prefixes) {
  if (number == null) {
       return false;
  }
   for (String prefix : prefixes) {
       if (number.startsWith(prefix)) {
       return true;
    }
  }
     return false;
}

参考

条纹卡生成器

follow Luhn’s algorithm

 private  boolean validateCreditCardNumber(String str) {

        int[] ints = new int[str.length()];
        for (int i = 0; i < str.length(); i++) {
            ints[i] = Integer.parseInt(str.substring(i, i + 1));
        }
        for (int i = ints.length - 2; i >= 0; i = i - 2) {
            int j = ints[i];
            j = j * 2;
            if (j > 9) {
                j = j % 10 + 1;
            }
            ints[i] = j;
        }
        int sum = 0;
        for (int i = 0; i < ints.length; i++) {
            sum += ints[i];
        }
        if (sum % 10 == 0) {
           return true;
        } else {
            return false;
        }


    }

then call this method

Edittext mCreditCardNumberEt;

 mCreditCardNumberEt.addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {

            }

            @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {

             int cardcount=   s.toString().length();
                 if(cardcount>=16) {
                    boolean cardnumbervalid=   validateCreditCardNumber(s.toString());
                    if(cardnumbervalid) {
                        cardvalidtesting.setText("Valid Card");
                        cardvalidtesting.setTextColor(ContextCompat.getColor(context,R.color.green));
                    }
                    else {
                        cardvalidtesting.setText("Invalid Card");
                        cardvalidtesting.setTextColor(ContextCompat.getColor(context,R.color.red));
                    }
                }
               else if(cardcount>0 &&cardcount<16) {
                     cardvalidtesting.setText("Invalid Card");
                     cardvalidtesting.setTextColor(ContextCompat.getColor(context,R.color.red));
                }

                else {
                    cardvalidtesting.setText("");

                }


                }

            @Override
            public void afterTextChanged(Editable s) {

            }
        });

更新日期:2016年6月15日(目前为最终解决方案)

请注意,我甚至放弃投票给一个被投票最多的,但为了明确这些是regexp实际上是有效的,我用数千个真实的BIN代码测试了它。最重要的是使用开始字符串(^),否则在现实世界中会给出错误的结果!

JCB ^(?:2131|1800|35)[0-9]{0,}$开始:2131,1800,35 (3528-3589)

美国运通^3[47][0-9]{0,}$以:34,37开头

大莱卡^ 3(?:0(0-59){1}|[689])[0 - 9]{0}$开头:300 - 305年,309年,36岁,38-39

Visa ^4[0-9]{0,}$以:4开头

万事达卡^(5[1 - 5]| 222(1 - 9)| 22(3 - 9)| 2(3 - 6)| 27[01]| 2720)[0 - 9]{0}$开头:2221 - 2720,51-55

Maestro ^(5[06789]|6)[0-9]{0,}$ Maestro总是在范围内增长:60-69,以/开始,但开始5必须编码为万事达卡。大师卡必须在代码的末尾被检测到,因为其他一些卡的范围在60-69之间。请看代码。

发现^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0,}$发现很难编码,从:6011,622126 - 622925,644 -649,65开始

在javascript中,我使用这个函数。当你把它分配给一个onkeyup事件并尽快给出结果时,这是很好的。

function cc_brand_id(cur_val) {
    // the regular expressions check for possible matches as you type, hence the OR operators based on the number of chars
    // regexp string length {0} provided for soonest detection of beginning of the card numbers this way it could be used for BIN CODE detection also

    //JCB
    jcb_regex = new RegExp('^(?:2131|1800|35)[0-9]{0,}$'); //2131, 1800, 35 (3528-3589)
    // American Express
    amex_regex = new RegExp('^3[47][0-9]{0,}$'); //34, 37
    // Diners Club
    diners_regex = new RegExp('^3(?:0[0-59]{1}|[689])[0-9]{0,}$'); //300-305, 309, 36, 38-39
    // Visa
    visa_regex = new RegExp('^4[0-9]{0,}$'); //4
    // MasterCard
    mastercard_regex = new RegExp('^(5[1-5]|222[1-9]|22[3-9]|2[3-6]|27[01]|2720)[0-9]{0,}$'); //2221-2720, 51-55
    maestro_regex = new RegExp('^(5[06789]|6)[0-9]{0,}$'); //always growing in the range: 60-69, started with / not something else, but starting 5 must be encoded as mastercard anyway
    //Discover
    discover_regex = new RegExp('^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0,}$');
    ////6011, 622126-622925, 644-649, 65


    // get rid of anything but numbers
    cur_val = cur_val.replace(/\D/g, '');

    // checks per each, as their could be multiple hits
    //fix: ordering matter in detection, otherwise can give false results in rare cases
    var sel_brand = "unknown";
    if (cur_val.match(jcb_regex)) {
        sel_brand = "jcb";
    } else if (cur_val.match(amex_regex)) {
        sel_brand = "amex";
    } else if (cur_val.match(diners_regex)) {
        sel_brand = "diners_club";
    } else if (cur_val.match(visa_regex)) {
        sel_brand = "visa";
    } else if (cur_val.match(mastercard_regex)) {
        sel_brand = "mastercard";
    } else if (cur_val.match(discover_regex)) {
        sel_brand = "discover";
    } else if (cur_val.match(maestro_regex)) {
        if (cur_val[0] == '5') { //started 5 must be mastercard
            sel_brand = "mastercard";
        } else {
            sel_brand = "maestro"; //maestro is all 60-69 which is not something else, thats why this condition in the end
        }
    }

    return sel_brand;
}

在这里你可以玩它:

http://jsfiddle.net/upN3L/69/

对于PHP使用这个函数,它也会检测一些子VISA/MC卡:

/**
  * Obtain a brand constant from a PAN
  *
  * @param string $pan               Credit card number
  * @param bool   $include_sub_types Include detection of sub visa brands
  * @return string
  */
public static function getCardBrand($pan, $include_sub_types = false)
{
    //maximum length is not fixed now, there are growing number of CCs has more numbers in length, limiting can give false negatives atm

    //these regexps accept not whole cc numbers too
    //visa
    $visa_regex = "/^4[0-9]{0,}$/";
    $vpreca_regex = "/^428485[0-9]{0,}$/";
    $postepay_regex = "/^(402360|402361|403035|417631|529948){0,}$/";
    $cartasi_regex = "/^(432917|432930|453998)[0-9]{0,}$/";
    $entropay_regex = "/^(406742|410162|431380|459061|533844|522093)[0-9]{0,}$/";
    $o2money_regex = "/^(422793|475743)[0-9]{0,}$/";

    // MasterCard
    $mastercard_regex = "/^(5[1-5]|222[1-9]|22[3-9]|2[3-6]|27[01]|2720)[0-9]{0,}$/";
    $maestro_regex = "/^(5[06789]|6)[0-9]{0,}$/";
    $kukuruza_regex = "/^525477[0-9]{0,}$/";
    $yunacard_regex = "/^541275[0-9]{0,}$/";

    // American Express
    $amex_regex = "/^3[47][0-9]{0,}$/";

    // Diners Club
    $diners_regex = "/^3(?:0[0-59]{1}|[689])[0-9]{0,}$/";

    //Discover
    $discover_regex = "/^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0,}$/";

    //JCB
    $jcb_regex = "/^(?:2131|1800|35)[0-9]{0,}$/";

    //ordering matter in detection, otherwise can give false results in rare cases
    if (preg_match($jcb_regex, $pan)) {
        return "jcb";
    }

    if (preg_match($amex_regex, $pan)) {
        return "amex";
    }

    if (preg_match($diners_regex, $pan)) {
        return "diners_club";
    }

    //sub visa/mastercard cards
    if ($include_sub_types) {
        if (preg_match($vpreca_regex, $pan)) {
            return "v-preca";
        }
        if (preg_match($postepay_regex, $pan)) {
            return "postepay";
        }
        if (preg_match($cartasi_regex, $pan)) {
            return "cartasi";
        }
        if (preg_match($entropay_regex, $pan)) {
            return "entropay";
        }
        if (preg_match($o2money_regex, $pan)) {
            return "o2money";
        }
        if (preg_match($kukuruza_regex, $pan)) {
            return "kukuruza";
        }
        if (preg_match($yunacard_regex, $pan)) {
            return "yunacard";
        }
    }

    if (preg_match($visa_regex, $pan)) {
        return "visa";
    }

    if (preg_match($mastercard_regex, $pan)) {
        return "mastercard";
    }

    if (preg_match($discover_regex, $pan)) {
        return "discover";
    }

    if (preg_match($maestro_regex, $pan)) {
        if ($pan[0] == '5') { //started 5 must be mastercard
            return "mastercard";
        }
        return "maestro"; //maestro is all 60-69 which is not something else, thats why this condition in the end

    }

    return "unknown"; //unknown for this system
}

anatoly用PHP回答:

 public static function detectCardType($num)
 {
    $re = array(
        "visa"       => "/^4[0-9]{12}(?:[0-9]{3})?$/",
        "mastercard" => "/^5[1-5][0-9]{14}$/",
        "amex"       => "/^3[47][0-9]{13}$/",
        "discover"   => "/^6(?:011|5[0-9]{2})[0-9]{12}$/",
    );

    if (preg_match($re['visa'],$num))
    {
        return 'visa';
    }
    else if (preg_match($re['mastercard'],$num))
    {
        return 'mastercard';
    }
    else if (preg_match($re['amex'],$num))
    {
        return 'amex';
    }
    else if (preg_match($re['discover'],$num))
    {
        return 'discover';
    }
    else
    {
        return false;
    }
 }