final EditText edittext = (EditText) findViewById(R.id.edittext);
    edittext.setOnKeyListener(new OnKeyListener() {
        public boolean onKey(View v, int keyCode, KeyEvent event) {
            // If the event is a key-down event on the "enter" button
            if ((event.getAction() == KeyEvent.ACTION_DOWN) &&
                    (keyCode == KeyEvent.KEYCODE_ENTER)) {
                // Perform action on key press
                Toast.makeText(HelloFormStuff.this, edittext.getText(), Toast.LENGTH_SHORT).show();
                return true;
            }
            return false;
        }
    });

这个问题还没有被Butterknife回答

布局的XML

<android.support.design.widget.TextInputLayout
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:hint="@string/some_input_hint">

        <android.support.design.widget.TextInputEditText
            android:id="@+id/textinput"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:imeOptions="actionSend"
            android:inputType="text|textCapSentences|textAutoComplete|textAutoCorrect"/>
    </android.support.design.widget.TextInputLayout>

JAVA应用程序

@OnEditorAction(R.id.textinput)
boolean onEditorAction(int actionId, KeyEvent key){
    boolean handled = false;
    if (actionId == EditorInfo.IME_ACTION_SEND || (key.getKeyCode() == KeyEvent.KEYCODE_ENTER)) {
        //do whatever you want
        handled = true;
    }
    return handled;
}

将“txtid”替换为您的EditText ID。

EditText txtinput;
txtinput=findViewById(R.id.txtid)    
txtinput.setOnEditorActionListener(new TextView.OnEditorActionListener() {
        @Override
        public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
            if ((event != null && (event.getKeyCode() == KeyEvent.KEYCODE_ENTER))     || (actionId == EditorInfo.IME_ACTION_DONE)) {
                
                //Code for the action you want to proceed with.

                InputMethodManager inputManager = (InputMethodManager)
                        getSystemService(Context.INPUT_METHOD_SERVICE);

                 inputManager.hideSoftInputFromWindow(getCurrentFocus().getWindowToken(),
                        InputMethodManager.HIDE_NOT_ALWAYS);
            }
            return false;
        }
    });

作为Chad响应的补充(对我来说几乎完美)，我发现我需要在KeyEvent操作类型上添加一个检查，以防止代码执行两次(一次在key-up事件上执行，一次在key-down事件上执行)。

if (actionId == EditorInfo.IME_NULL && event.getAction() == KeyEvent.ACTION_DOWN)
{
    // your code here
}

有关重复动作事件(按住enter键)的信息，请参见http://developer.android.com/reference/android/view/KeyEvent.html。

I had a similar purpose. I wanted to resolve pressing the "Enter" key on the keyboard (which I wanted to customize) in an AutoCompleteTextView which extends TextView. I tried different solutions from above and they seemed to work. BUT I experienced some problems when I switched the input type on my device (Nexus 4 with AOKP ROM) from SwiftKey 3 (where it worked perfectly) to the standard Android keyboard (where instead of handling my code from the listener, a new line was entered after pressing the "Enter" key. It took me a while to handle this problem, but I don't know if it will work under all circumstances no matter which input type you use.

这是我的解决方案:

在xml中设置TextView的输入类型属性为"text":

android:inputType="text"

自定义键盘上“Enter”键的标签:

myTextView.setImeActionLabel("Custom text", KeyEvent.KEYCODE_ENTER);

将OnEditorActionListener设置为TextView:

myTextView.setOnEditorActionListener(new OnEditorActionListener()
{
    @Override
    public boolean onEditorAction(TextView v, int actionId,
        KeyEvent event)
    {
    boolean handled = false;
    if (event.getAction() == KeyEvent.KEYCODE_ENTER)
    {
        // Handle pressing "Enter" key here

        handled = true;
    }
    return handled;
    }
});

我希望这能帮助其他人避免我遇到的问题，因为它们几乎把我逼疯了。

我知道这已经有一年了，但我刚刚发现这非常适合EditText。

EditText textin = (EditText) findViewById(R.id.editText1);
textin.setInputType(InputType.TYPE_CLASS_TEXT);

除了文本和空格，它可以阻止任何东西。我不能制表，“返回”(“\n”)，或任何东西。