更新，原始答案如下

trait函数type_name如何，它对于快速获取类型名称非常有用。

pub trait AnyExt {
    fn type_name(&self) -> &'static str;
}

impl<T> AnyExt for T {
    fn type_name(&self) -> &'static str {
        std::any::type_name::<T>()
    }
}

fn main(){
    let my_number = 32.90;
    println!("{}",my_number.type_name());
}

输出:

f64

原来的答案

我写了一个宏type_of!()来调试，它来自std dbg!()。

pub fn type_of2<T>(v: T) -> (&'static str, T) {
    (std::any::type_name::<T>(), v)
}

#[macro_export]
macro_rules! type_of {
    // NOTE: We cannot use `concat!` to make a static string as a format argument
    // of `eprintln!` because `file!` could contain a `{` or
    // `$val` expression could be a block (`{ .. }`), in which case the `eprintln!`
    // will be malformed.
    () => {
        eprintln!("[{}:{}]", file!(), line!());
    };
    ($val:expr $(,)?) => {
        // Use of `match` here is intentional because it affects the lifetimes
        // of temporaries - https://stackoverflow.com/a/48732525/1063961
        match $val {
            tmp => {
                let (type_,tmp) = $crate::type_of2(tmp);
                eprintln!("[{}:{}] {}: {}",
                    file!(), line!(), stringify!($val), type_);
                tmp
            }
        }
    };
    ($($val:expr),+ $(,)?) => {
        ($($crate::type_of!($val)),+,)
    };
}

fn main(){
    let my_number = type_of!(32.90);
    type_of!(my_number);
}

输出:

[src/main.rs:32] 32.90: f64
[src/main.rs:33] my_number: f64

我非常喜欢@Coautose之前的回答，但如果有人只想要没有名称空间的类型名称，例如C而不是a::b::C，这里是一个修改后的宏版本，看起来像预期的那样工作:

macro_rules! ty {
    ($type:ty) => {{
        let result = std::any::type_name::<$type>();
        match result.rsplit_once(':') {
            Some((_, s)) => s,
            None => result,
        }
    }};
}

用法:

debug!("Testing type name: {}", ty!(A));

如果你只是想找出一个变量的类型，并愿意在编译时执行，你可能会导致一个错误，并让编译器拾取它。

例如，将变量设置为一个无效的类型:

let mut my_number: () = 32.90;
// let () = x; would work too

error[E0308]: mismatched types
 --> src/main.rs:2:29
  |
2 |     let mut my_number: () = 32.90;
  |                             ^^^^^ expected (), found floating-point number
  |
  = note: expected type `()`
             found type `{float}`

或者调用无效的方法:

let mut my_number = 32.90;
my_number.what_is_this();

error[E0599]: no method named `what_is_this` found for type `{float}` in the current scope
 --> src/main.rs:3:15
  |
3 |     my_number.what_is_this();
  |               ^^^^^^^^^^^^

或访问无效字段:

let mut my_number = 32.90;
my_number.what_is_this

error[E0610]: `{float}` is a primitive type and therefore doesn't have fields
 --> src/main.rs:3:15
  |
3 |     my_number.what_is_this
  |               ^^^^^^^^^^^^

These reveal the type, which in this case is actually not fully resolved. It’s called “floating-point variable” in the first example, and “{float}” in all three examples; this is a partially resolved type which could end up f32 or f64, depending on how you use it. “{float}” is not a legal type name, it’s a placeholder meaning “I’m not completely sure what this is”, but it is a floating-point number. In the case of floating-point variables, if you don't constrain it, it will default to f64¹. (An unqualified integer literal will default to i32.)

参见:

编译器错误消息中的{integer}或{float}是什么?

¹可能仍然有一些让编译器困惑的方法，使它无法在f32和f64之间做出决定;我不确定。它曾经像32.90.eq(&32.90)一样简单，但现在两者都被视为f64，并且可以愉快地进行，所以我不知道。

短篇小说;

fn tyof<T>(_: &T) -> String {
    std::any::type_name::<T>().into()
}

很长的故事;

trait Type {
    fn type_of(&self) -> String;
}

macro_rules! Type {
    ($($ty:ty),*) => {
        $(
            impl Type for $ty {
                fn type_of(&self) -> String {
                    stringify!($ty).into()
                }
            }
        )*
    }
}

#[rustfmt::skip]
Type!(
    u8, i8, u16, i16, u32, i32, i64, u64, i128, String, [()], (), Vec<()>, &u8, &i8, &u16, &i16, &u32, &i32, &i64, &u64, &i128, &str, &[()], &Vec<()>, &() 
    // add any struct, enum or type you want
);

macro_rules! tyof {
    ($var: expr) => {{
        $var.type_of()
    }};
}

fn main() {
    let x = "Hello world!";
    println!("{}", tyof!(x));
    // or
    println!("{}", x.type_of());

    let x = 5;
    println!("{}", tyof!(x));
    // or
    println!("{}", x.type_of());
}

这是@Boiethios回答的简化版。我已经从原始解决方案中删除了一些“&”符号。

fn print_type_of<T>(_: T) {
    println!("{}", std::any::type_name::<T>())
}

fn main() {
    let s = "Hello";
    let i = 42;

    print_type_of(s); // &str
    print_type_of(i); // i32
    print_type_of(main); // playground::main
    print_type_of(print_type_of::<i32>); // playground::print_type_of<i32>
    print_type_of(|| "Hi!" ); // playground::main::{{closure}}
}

Rust游乐场的景观

在稳定rust中有一个@ChrisMorgan答案可以获得近似类型(“float”)，在夜间rust中有一个@ShubhamJain答案可以通过不稳定函数获得精确类型(“f64”)。

现在有一种方法可以得到精确的类型(即在f32和f64之间决定)在稳定的rust:

fn main() {
    let a = 5.;
    let _: () = unsafe { std::mem::transmute(a) };
}

结果

error[E0512]: cannot transmute between types of different sizes, or dependently-sized types
 --> main.rs:3:27
  |
3 |     let _: () = unsafe { std::mem::transmute(a) };
  |                           ^^^^^^^^^^^^^^^^^^^
  |
  = note: source type: `f64` (64 bits)
  = note: target type: `()` (0 bits)

更新

涡轮鱼的变异

fn main() {
    let a = 5.;
    unsafe { std::mem::transmute::<_, ()>(a) }
}

略短，但可读性稍差。