最好使用这个:

fn print_type_of<T>(_: &T) -> String {
    format!("{}", std::any::type_name::<T>())
}

fn main() {
    let s = &"hello world".to_string();
    let cloned_s = s.clone();
    println!("{:?}", print_type_of(&s));
    println!("{:?}", print_type_of(&cloned_s));
}

来自https://stackoverflow.com/a/29168659/6774636的推论

你可以使用std::any::type_name函数。这并不需要一个夜间编译器或外部板条箱，结果是非常正确的:

fn print_type_of<T>(_: &T) {
    println!("{}", std::any::type_name::<T>())
}

fn main() {
    let s = "Hello";
    let i = 42;

    print_type_of(&s); // &str
    print_type_of(&i); // i32
    print_type_of(&main); // playground::main
    print_type_of(&print_type_of::<i32>); // playground::print_type_of<i32>
    print_type_of(&{ || "Hi!" }); // playground::main::{{closure}}
}

注意:如文档中所述，此信息只能用于调试目的:

这是用于诊断用途。字符串的确切内容和格式没有指定，只是尽力描述该类型。

如果你想让你的类型表示在不同的编译器版本中保持相同，你应该使用一个trait，就像phicr的答案一样。

最好使用这个:

fn print_type_of<T>(_: &T) -> String {
    format!("{}", std::any::type_name::<T>())
}

fn main() {
    let s = &"hello world".to_string();
    let cloned_s = s.clone();
    println!("{:?}", print_type_of(&s));
    println!("{:?}", print_type_of(&cloned_s));
}

来自https://stackoverflow.com/a/29168659/6774636的推论

更新，原始答案如下

trait函数type_name如何，它对于快速获取类型名称非常有用。

pub trait AnyExt {
    fn type_name(&self) -> &'static str;
}

impl<T> AnyExt for T {
    fn type_name(&self) -> &'static str {
        std::any::type_name::<T>()
    }
}

fn main(){
    let my_number = 32.90;
    println!("{}",my_number.type_name());
}

输出:

f64

原来的答案

我写了一个宏type_of!()来调试，它来自std dbg!()。

pub fn type_of2<T>(v: T) -> (&'static str, T) {
    (std::any::type_name::<T>(), v)
}

#[macro_export]
macro_rules! type_of {
    // NOTE: We cannot use `concat!` to make a static string as a format argument
    // of `eprintln!` because `file!` could contain a `{` or
    // `$val` expression could be a block (`{ .. }`), in which case the `eprintln!`
    // will be malformed.
    () => {
        eprintln!("[{}:{}]", file!(), line!());
    };
    ($val:expr $(,)?) => {
        // Use of `match` here is intentional because it affects the lifetimes
        // of temporaries - https://stackoverflow.com/a/48732525/1063961
        match $val {
            tmp => {
                let (type_,tmp) = $crate::type_of2(tmp);
                eprintln!("[{}:{}] {}: {}",
                    file!(), line!(), stringify!($val), type_);
                tmp
            }
        }
    };
    ($($val:expr),+ $(,)?) => {
        ($($crate::type_of!($val)),+,)
    };
}

fn main(){
    let my_number = type_of!(32.90);
    type_of!(my_number);
}

输出:

[src/main.rs:32] 32.90: f64
[src/main.rs:33] my_number: f64

短篇小说;

fn tyof<T>(_: &T) -> String {
    std::any::type_name::<T>().into()
}

很长的故事;

trait Type {
    fn type_of(&self) -> String;
}

macro_rules! Type {
    ($($ty:ty),*) => {
        $(
            impl Type for $ty {
                fn type_of(&self) -> String {
                    stringify!($ty).into()
                }
            }
        )*
    }
}

#[rustfmt::skip]
Type!(
    u8, i8, u16, i16, u32, i32, i64, u64, i128, String, [()], (), Vec<()>, &u8, &i8, &u16, &i16, &u32, &i32, &i64, &u64, &i128, &str, &[()], &Vec<()>, &() 
    // add any struct, enum or type you want
);

macro_rules! tyof {
    ($var: expr) => {{
        $var.type_of()
    }};
}

fn main() {
    let x = "Hello world!";
    println!("{}", tyof!(x));
    // or
    println!("{}", x.type_of());

    let x = 5;
    println!("{}", tyof!(x));
    // or
    println!("{}", x.type_of());
}

这是@Boiethios回答的简化版。我已经从原始解决方案中删除了一些“&”符号。

fn print_type_of<T>(_: T) {
    println!("{}", std::any::type_name::<T>())
}

fn main() {
    let s = "Hello";
    let i = 42;

    print_type_of(s); // &str
    print_type_of(i); // i32
    print_type_of(main); // playground::main
    print_type_of(print_type_of::<i32>); // playground::print_type_of<i32>
    print_type_of(|| "Hi!" ); // playground::main::{{closure}}
}

Rust游乐场的景观