下面的位运算符在现实世界中有哪些用例?
和 XOR 不 或 左/右转
下面的位运算符在现实世界中有哪些用例?
和 XOR 不 或 左/右转
当前回答
一个数x是2的幂吗?(例如,在计数器递增的算法中很有用,并且一个操作只执行对数次)
(x & (x - 1)) == 0
整数x的最高位是哪位?(例如,这可以用来找出比x大的2的最小次幂)
x |= (x >> 1);
x |= (x >> 2);
x |= (x >> 4);
x |= (x >> 8);
x |= (x >> 16);
return x - (x >>> 1); // ">>>" is unsigned right shift
整数x的最小1位是哪一位?(帮助找出能被2整除的次数。)
x & -x
其他回答
我很惊讶,没有人为互联网时代选择一个显而易见的答案。计算子网的有效网络地址。
http://www.topwebhosts.org/tools/netmask.php
当我有一堆布尔标记时,我喜欢将它们全部存储在一个整型中。
我用bitwise-AND取出它们。例如:
int flags;
if (flags & 0x10) {
// Turn this feature on.
}
if (flags & 0x08) {
// Turn a second feature on.
}
etc.
Bit fields (flags) They're the most efficient way of representing something whose state is defined by several "yes or no" properties. ACLs are a good example; if you have let's say 4 discrete permissions (read, write, execute, change policy), it's better to store this in 1 byte rather than waste 4. These can be mapped to enumeration types in many languages for added convenience. Communication over ports/sockets Always involves checksums, parity, stop bits, flow control algorithms, and so on, which usually depend on the logic values of individual bytes as opposed to numeric values, since the medium may only be capable of transmitting one bit at a time. Compression, Encryption Both of these are heavily dependent on bitwise algorithms. Look at the deflate algorithm for an example - everything is in bits, not bytes. Finite State Machines I'm speaking primarily of the kind embedded in some piece of hardware, although they can be found in software too. These are combinatorial in nature - they might literally be getting "compiled" down to a bunch of logic gates, so they have to be expressed as AND, OR, NOT, etc. Graphics There's hardly enough space here to get into every area where these operators are used in graphics programming. XOR (or ^) is particularly interesting here because applying the same input a second time will undo the first. Older GUIs used to rely on this for selection highlighting and other overlays, in order to eliminate the need for costly redraws. They're still useful in slow graphics protocols (i.e. remote desktop).
这些只是我最先想到的几个例子——这不是一个详尽的清单。
河内塔线性解采用位运算来解决问题。
public static void linear(char start, char temp, char end, int discs)
{
int from,to;
for (int i = 1; i < (1 << discs); i++) {
from = (i & i-1) % 3;
to = ((i | i-1) + 1) % 3;
System.out.println(from+" => "+to);
}
}
这个解决方案的解释可以在这里找到
不久前,我在维基上写了一篇小文章,展示了一个二进制的作者/读者。它在位级上工作,并展示了如何使用位操作符来打包数据。这可能是一个“现实世界”的例子,因为它在游戏中也有应用。