下面的位运算符在现实世界中有哪些用例?
和 XOR 不 或 左/右转
下面的位运算符在现实世界中有哪些用例?
和 XOR 不 或 左/右转
当前回答
当我有一堆布尔标记时,我喜欢将它们全部存储在一个整型中。
我用bitwise-AND取出它们。例如:
int flags;
if (flags & 0x10) {
// Turn this feature on.
}
if (flags & 0x08) {
// Turn a second feature on.
}
etc.
其他回答
在当今现代语言的抽象世界里,没有太多。File IO是一个容易想到的方法,尽管它是在已经实现的东西上执行按位操作,而不是实现使用按位操作的东西。尽管如此,作为一个简单的例子,这段代码演示了在c#中删除文件上的只读属性(这样它就可以与指定FileMode.Create的新FileStream一起使用):
//Hidden files posses some extra attibutes that make the FileStream throw an exception
//even with FileMode.Create (if exists -> overwrite) so delete it and don't worry about it!
if(File.Exists(targetName))
{
FileAttributes attributes = File.GetAttributes(targetName);
if ((attributes & FileAttributes.ReadOnly) == FileAttributes.ReadOnly)
File.SetAttributes(targetName, attributes & (~FileAttributes.ReadOnly));
File.Delete(targetName);
}
As far as custom implementations, here's a recent example: I created a "message center" for sending secure messages from one installation of our distributed application to another. Basically, it's analogous to email, complete with Inbox, Outbox, Sent, etc, but it also has guaranteed delivery with read receipts, so there are additional subfolders beyond "inbox" and "sent." What this amounted to was a requirement for me to define generically what's "in the inbox" or what's "in the sent folder". Of the sent folder, I need to know what's read and what's unread. Of what's unread, I need to know what's received and what's not received. I use this information to build a dynamic where clause which filters a local datasource and displays the appropriate information.
下面是枚举是如何组合在一起的:
public enum MemoView :int
{
InboundMemos = 1, // 0000 0001
InboundMemosForMyOrders = 3, // 0000 0011
SentMemosAll = 16, // 0001 0000
SentMemosNotReceived = 48, // 0011
SentMemosReceivedNotRead = 80, // 0101
SentMemosRead = 144, // 1001
Outbox = 272, //0001 0001 0000
OutBoxErrors = 784 //0011 0001 0000
}
你明白这是怎么回事了吗?通过与“收件箱”枚举值InboundMemos加上(&),我知道InboundMemosForMyOrders在收件箱中。
下面是该方法的简化版本,它构建并返回为当前选择的文件夹定义视图的过滤器:
private string GetFilterForView(MemoView view, DefaultableBoolean readOnly)
{
string filter = string.Empty;
if((view & MemoView.InboundMemos) == MemoView.InboundMemos)
{
filter = "<inbox filter conditions>";
if((view & MemoView.InboundMemosForMyOrders) == MemoView.InboundMemosForMyOrders)
{
filter += "<my memo filter conditions>";
}
}
else if((view & MemoView.SentMemosAll) == MemoView.SentMemosAll)
{
//all sent items have originating system = to local
filter = "<memos leaving current system>";
if((view & MemoView.Outbox) == MemoView.Outbox)
{
...
}
else
{
//sent sub folders
filter += "<all sent items>";
if((view & MemoView.SentMemosNotReceived) == MemoView.SentMemosNotReceived)
{
if((view & MemoView.SentMemosReceivedNotRead) == MemoView.SentMemosReceivedNotRead)
{
filter += "<not received and not read conditions>";
}
else
filter += "<received and not read conditions>";
}
}
}
return filter;
}
非常简单,但在抽象级别上是一个整洁的实现,通常不需要按位操作。
河内塔线性解采用位运算来解决问题。
public static void linear(char start, char temp, char end, int discs)
{
int from,to;
for (int i = 1; i < (1 << discs); i++) {
from = (i & i-1) % 3;
to = ((i | i-1) + 1) % 3;
System.out.println(from+" => "+to);
}
}
这个解决方案的解释可以在这里找到
似乎没有人提到定点数学。
(是的,我老了,好吗?)
我使用它们来实现快速BCD计算(会计师和审计员会对fp舍入感到不安)。
还没人提到过收藏。有时您有一个较小的可能值集合,比如只有10或20个可能值,您希望将其中一些值保存在一个集合中。当然,您可以使用常规的Set实现,它很可能使用支持哈希表。但由于可能值的集合是如此之小,这实际上只是浪费时间和空间。相反,您可以将集合存储在单个int或长值中,这正是java EnumSet所做的,如果我没记错的话。