有没有办法用JavaScript生成指定范围内的随机数?

例如:指定范围从1到6,随机数可以是1、2、3、4、5或6。


当前回答

重要的

The following code works only if the minimum value is `1`. It does not work for minimum values other than `1`.

如果你想得到一个介于1(且只有1)和6之间的随机整数,你可以计算:

const rndInt=数学地板(Math.random()*6)+1控制台日志(rndInt)

哪里:

1是起始编号6是可能结果的数量(1+start(6)-end(1))

其他回答

ES6/Arrow函数版本基于Francis的代码(即顶级答案):

const randomIntFromInterval = (min, max) => Math.floor(Math.random() * (max - min + 1) + min);

对于大数字。

var min_num = 900;
var max_num = 1000;
while(true){
    
    let num_random = Math.random()* max_num;
    console.log('input : '+num_random);
    if(num_random >= min_num){
        console.log(Math.floor(num_random));
       break; 
    } else {
        console.log(':::'+Math.floor(num_random));
    }
}

重要的

The following code works only if the minimum value is `1`. It does not work for minimum values other than `1`.

如果你想得到一个介于1(且只有1)和6之间的随机整数,你可以计算:

const rndInt=数学地板(Math.random()*6)+1控制台日志(rndInt)

哪里:

1是起始编号6是可能结果的数量(1+start(6)-end(1))

尽管有许多答案,但结果几乎相同。我想补充一下我的答案并解释一下它的作用。因为理解它的工作方式比复制粘贴单行代码更重要。生成随机数只是简单的数学。

代码:

function getR(lower, upper) {

  var percent = (Math.random() * 100);
  // this will return number between 0-99 because Math.random returns decimal number from 0-0.9929292 something like that
  //now you have a percentage, use it find out the number between your INTERVAL :upper-lower 
  var num = ((percent * (upper - lower) / 100));
  //num will now have a number that falls in your INTERVAL simple maths
  num += lower;
  //add lower to make it fall in your INTERVAL
  //but num is still in decimal
  //use Math.floor>downward to its nearest integer you won't get upper value ever
  //use Math.ceil>upward to its nearest integer upper value is possible
  //Math.round>to its nearest integer 2.4>2 2.5>3   both lower and upper value possible
  console.log(Math.floor(num), Math.ceil(num), Math.round(num));
}
var x = 6; // can be any number
var rand = Math.floor(Math.random()*x) + 1;