一些方便的字符串助手:

用法:

我讨厌不需要的空格尾随或引导字符串，因为字符串可以采取空值，这可能是棘手的，所以我使用这个:

public bool IsGroup { get { return !this.GroupName.IsNullOrTrimEmpty(); } }

这是另一个扩展方法，我使用一个新的验证框架，我正在试验。你可以看到regex扩展，帮助清理凌乱的regex:

public static bool IsRequiredWithLengthLessThanOrEqualNoSpecial(this String str, int length)
{
    return !str.IsNullOrTrimEmpty() &&
        str.RegexMatch(
            @"^[- \r\n\\\.!:*,@$%&""?\(\)\w']{1,{0}}$".RegexReplace(@"\{0\}", length.ToString()),
            RegexOptions.Multiline) == str;
}

来源:

public static class StringHelpers
{
    /// <summary>
    /// Same as String.IsNullOrEmpty except that
    /// it captures the Empty state for whitespace
    /// strings by Trimming first.
    /// </summary>
    public static bool IsNullOrTrimEmpty(this String helper)
    {
        if (helper == null)
            return true;
        else
            return String.Empty == helper.Trim();
    }

    public static int TrimLength(this String helper)
    {
        return helper.Trim().Length;
    }

    /// <summary>
    /// Returns the matched string from the regex pattern. The
    /// groupName is for named group match values in the form (?<name>group).
    /// </summary>
    public static string RegexMatch(this String helper, string pattern, RegexOptions options, string groupName)
    {
        if (groupName.IsNullOrTrimEmpty())
            return Regex.Match(helper, pattern, options).Value;
        else
            return Regex.Match(helper, pattern, options).Groups[groupName].Value;
    }

    public static string RegexMatch(this String helper, string pattern)
    {
        return RegexMatch(helper, pattern, RegexOptions.None, null);
    }

    public static string RegexMatch(this String helper, string pattern, RegexOptions options)
    {
        return RegexMatch(helper, pattern, options, null);
    }

    public static string RegexMatch(this String helper, string pattern, string groupName)
    {
        return RegexMatch(helper, pattern, RegexOptions.None, groupName);
    }

    /// <summary>
    /// Returns true if there is a match from the regex pattern
    /// </summary>
    public static bool IsRegexMatch(this String helper, string pattern, RegexOptions options)
    {
        return helper.RegexMatch(pattern, options).Length > 0;
    }

    public static bool IsRegexMatch(this String helper, string pattern)
    {
        return helper.IsRegexMatch(pattern, RegexOptions.None);
    }

    /// <summary>
    /// Returns a string where matching patterns are replaced by the replacement string.
    /// </summary>
    /// <param name="pattern">The regex pattern for matching the items to be replaced</param>
    /// <param name="replacement">The string to replace matching items</param>
    /// <returns></returns>
    public static string RegexReplace(this String helper, string pattern, string replacement, RegexOptions options)
    {
        return Regex.Replace(helper, pattern, replacement, options);
    }

    public static string RegexReplace(this String helper, string pattern, string replacement)
    {
        return Regex.Replace(helper, pattern, replacement, RegexOptions.None);
    }
}

我喜欢做很多正则表达式，所以我认为这些比添加using语句和额外的代码来处理命名组更容易。

讨厌这种代码?

CloneableClass cc1 = new CloneableClass ();
CloneableClass cc2 = null;
CloneableClass cc3 = null;

cc3 = (CloneableClass) cc1.Clone (); // this is ok
cc3 = cc2.Clone (); // this throws null ref exception
// code to handle both cases
cc3 = cc1 != null ? (CloneableClass) cc1.Clone () : null;

它有点笨拙，所以我用这个扩展替换它，我称之为CloneOrNull -

public static T CloneOrNull<T> (this T self) where T : class, ICloneable
{
    if (self == null) return null;
    return (T) self.Clone ();
}

用法如下:

CloneableClass cc1 = new CloneableClass ();
CloneableClass cc2 = null;
CloneableClass cc3 = null;

cc3 = cc1.CloneOrNull (); // clone of cc1
cc3 = cc2.CloneOrNull (); // null
// look mom, no casts!

请随意在任何地方使用这个!

我觉得这个很有用:

public static class PaulaBean
{
    private static String paula = "Brillant";
    public static String GetPaula<T>(this T obj) {
        return paula;
    }
}

你可以在CodePlex上使用它。

在我的博客统计页面的最近搜索部分，我已经删除了所有重复的行，但需要一种方法来删除几乎重复的行。我会得到大量相似但不完全相同的谷歌查询。

我最终使用了匿名类型而不是字典，但想要一种方法来创建该匿名类型的List。你不能这样做，但是你可以在。net 4.0中创建一个List<dynamic>:)

我喜欢它的主要原因是我有效地得到了一个List<AnonymousType#1>()。

/// <summary>Remove extraneous entries for common word permutations</summary>
/// <param name="input">Incoming series of words to be filtered</param>
/// <param name="MaxIgnoreLength">Words this long or shorter will not count as duplicates</param>
/// <param name="words2">Instance list from BuildInstanceList()</param>
/// <returns>Filtered list of lines from input, based on filter info in words2</returns>
private static List<string> FilterNearDuplicates(List<string> input, int MaxIgnoreLength, List<dynamic> words2)
{
    List<string> output = new List<string>();
    foreach (string line in input)
    {
        int Dupes = 0;
        foreach (string word in line.Split(new char[] { ' ', ',', ';', '\\', '/', ':', '\"', '\r', '\n', '.' })
            .Where(p => p.Length > MaxIgnoreLength)
            .Distinct())
        {
            int Instances = 0;
            foreach (dynamic dyn in words2)
            if (word == dyn.Word)
            {
                Instances = dyn.Instances;
                if (Instances > 1)
                    Dupes++;
                break;
            }
        }
        if (Dupes == 0)
            output.Add(line);
    }
    return output;
}
/// <summary>Builds a list of words and how many times they occur in the overall list</summary>
/// <param name="input">Incoming series of words to be counted</param>
/// <returns></returns>
private static List<dynamic> BuildInstanceList(List<string> input)
{
    List<dynamic> words2 = new List<object>();
    foreach (string line in input)
    foreach (string word in line.Split(new char[] { ' ', ',', ';', '\\', '/', ':', '\"', '\r', '\n', '.' }))
    {
        if (string.IsNullOrEmpty(word))
            continue;
        else if (ExistsInList(word, words2))
            for (int i = words2.Count - 1; i >= 0; i--)
            {
                if (words2[i].Word == word)
                    words2[i] = new { Word = words2[i].Word, Instances = words2[i].Instances + 1 };
            }
        else
            words2.Add(new { Word = word, Instances = 1 });
    }

    return words2;
}
/// <summary>Determines whether a dynamic Word object exists in a List of this dynamic type.</summary>
/// <param name="word">Word to look for</param>
/// <param name="words">Word dynamics to search through</param>
/// <returns>Indicator of whether the word exists in the list of words</returns>
private static bool ExistsInList(string word, List<dynamic> words)
{
    foreach (dynamic dyn in words)
        if (dyn.Word == word)
            return true;
    return false;
}

有时使用自定义分隔符在列表中选中的元素上写出字符串是很方便的。

例如，如果你有一个List<Person>并且想要用逗号分隔姓氏，你可以这样做。

string result = string.Empty;
foreach (var person in personList) {
   result += person.LastName + ", ";
}
result = result.Substring(0, result.Length - 2);
return result;

或者你可以使用这个方便的扩展方法

public static string Join<T>(this IEnumerable<T> collection, Func<T, string> func, string separator)
{
  return String.Join(separator, collection.Select(func).ToArray());
}

像这样使用它

personList.Join(x => x.LastName, ", ");

这将产生相同的结果，在本例中是由逗号分隔的姓氏列表。

我总是使用格式，希望与StringBuilder的新行，所以下面这个非常简单的扩展节省了几行代码:

public static class Extensions
{
    public static void AppendLine(this StringBuilder builder,string format, params object[] args)
    {
        builder.AppendLine(string.Format(format, args));
    }
}

替代方案是StringBuilder中带\n或Environment.NewLine的AppendFormat。