如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
当前回答
SELECT ( Schema_name(A.schema_id) + '.' + A.NAME ) AS TableName,
Sum(B.rows)AS RecordCount
FROM sys.objects A INNER JOIN sys.partitions B
ON A.object_id = B.object_id WHERE A.type = 'U'
GROUP BY A.schema_id,A.NAME ;
QUERY_PHOTO
QUERY_RESULT_PHOTO
其他回答
这个sql脚本给出了所选数据库中每个表的模式、表名和行数:
SELECT SCHEMA_NAME(schema_id) AS [SchemaName],
[Tables].name AS [TableName],
SUM([Partitions].[rows]) AS [TotalRowCount]
FROM sys.tables AS [Tables]
JOIN sys.partitions AS [Partitions]
ON [Tables].[object_id] = [Partitions].[object_id]
AND [Partitions].index_id IN ( 0, 1 )
-- WHERE [Tables].name = N'name of the table'
GROUP BY SCHEMA_NAME(schema_id), [Tables].name
order by [TotalRowCount] desc
裁判:https://blog.sqlauthority.com/2017/05/24/sql-server-find-row-count-every-table-database-efficiently/
另一种表达方式:
SELECT o.NAME TABLENAME,
i.rowcnt
FROM sysindexes AS i
INNER JOIN sysobjects AS o ON i.id = o.id
WHERE i.indid < 2 AND OBJECTPROPERTY(o.id, 'IsMSShipped') = 0
ORDER BY i.rowcnt desc
你可以试试这个:
SELECT OBJECT_SCHEMA_NAME(ps.object_Id) AS [schemaname],
OBJECT_NAME(ps.object_id) AS [tablename],
row_count AS [rows]
FROM sys.dm_db_partition_stats ps
WHERE OBJECT_SCHEMA_NAME(ps.object_Id) <> 'sys' AND ps.index_id < 2
ORDER BY
OBJECT_SCHEMA_NAME(ps.object_Id),
OBJECT_NAME(ps.object_id)
从这个问题中: https://dba.stackexchange.com/questions/114958/list-all-tables-from-all-user-databases/230411#230411
我在@Aaron Bertrand提供的答案中添加了记录计数,该答案列出了所有数据库和所有表。
DECLARE @src NVARCHAR(MAX), @sql NVARCHAR(MAX);
SELECT @sql = N'', @src = N' UNION ALL
SELECT ''$d'' as ''database'',
s.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''schema'',
t.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''table'' ,
ind.rows as record_count
FROM [$d].sys.schemas AS s
INNER JOIN [$d].sys.tables AS t ON s.[schema_id] = t.[schema_id]
INNER JOIN [$d].sys.sysindexes AS ind ON t.[object_id] = ind.[id]
where ind.indid < 2';
SELECT @sql = @sql + REPLACE(@src, '$d', name)
FROM sys.databases
WHERE database_id > 4
AND [state] = 0
AND HAS_DBACCESS(name) = 1;
SET @sql = STUFF(@sql, 1, 10, CHAR(13) + CHAR(10));
PRINT @sql;
--EXEC sys.sp_executesql @sql;
接受的答案在Azure SQL上不适合我,这里有一个,它非常快,完全符合我的要求:
select t.name, s.row_count
from sys.tables t
join sys.dm_db_partition_stats s
ON t.object_id = s.object_id
and t.type_desc = 'USER_TABLE'
and t.name not like '%dss%'
and s.index_id = 1
order by s.row_count desc
如果您使用MySQL >4。X你可以用这个:
select TABLE_NAME, TABLE_ROWS from information_schema.TABLES where TABLE_SCHEMA="test";
请记住,对于某些存储引擎,TABLE_ROWS只是一个近似值。