如何列出数据库中每个表的行数。相当于

select count(*) from table1
select count(*) from table2
...
select count(*) from tableN

我会张贴一个解决方案,但其他方法是受欢迎的


当前回答

如图所示,这将返回正确的计数,而使用元数据表的方法将只返回估计值。

    CREATE PROCEDURE ListTableRowCounts 
    AS 
    BEGIN 
        SET NOCOUNT ON 

        CREATE TABLE #TableCounts
        ( 
            TableName VARCHAR(500), 
            CountOf INT 
        ) 

        INSERT #TableCounts
            EXEC sp_msForEachTable 
                'SELECT PARSENAME(''?'', 1), 
                COUNT(*) FROM ? WITH (NOLOCK)' 

        SELECT TableName , CountOf 
            FROM #TableCounts
            ORDER BY TableName 

        DROP TABLE #TableCounts
    END
    GO

其他回答

如图所示,这将返回正确的计数,而使用元数据表的方法将只返回估计值。

    CREATE PROCEDURE ListTableRowCounts 
    AS 
    BEGIN 
        SET NOCOUNT ON 

        CREATE TABLE #TableCounts
        ( 
            TableName VARCHAR(500), 
            CountOf INT 
        ) 

        INSERT #TableCounts
            EXEC sp_msForEachTable 
                'SELECT PARSENAME(''?'', 1), 
                COUNT(*) FROM ? WITH (NOLOCK)' 

        SELECT TableName , CountOf 
            FROM #TableCounts
            ORDER BY TableName 

        DROP TABLE #TableCounts
    END
    GO

Shnugo的答案是唯一一个工作在Azure的Externa表。(1) Azure SQL根本不支持sp_MSforeachtable;External表的partitions总是0。

以下是我对这个问题的看法。它包含所有模式,只列出带行的表。YMMV

select distinct schema_name(t.schema_id) as schema_name, t.name as 
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = 
p.index_id
where p.[Rows] > 0
order by schema_name;

这种方法使用字符串连接来动态生成包含所有表及其计数的语句,就像原始问题中给出的示例:

          SELECT COUNT(*) AS Count,'[dbo].[tbl1]' AS TableName FROM [dbo].[tbl1]
UNION ALL SELECT COUNT(*) AS Count,'[dbo].[tbl2]' AS TableName FROM [dbo].[tbl2]
UNION ALL SELECT...

最后用EXEC执行:

DECLARE @cmd VARCHAR(MAX)=STUFF(
                    (
                        SELECT 'UNION ALL SELECT COUNT(*) AS Count,''' 
                              + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME) 
                              + ''' AS TableName FROM ' + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
                        FROM INFORMATION_SCHEMA.TABLES AS t
                        WHERE TABLE_TYPE='BASE TABLE'
                        FOR XML PATH('')
                    ),1,10,'');
EXEC(@cmd);

我想分享对我有效的方法

SELECT
      QUOTENAME(SCHEMA_NAME(sOBJ.schema_id)) + '.' + QUOTENAME(sOBJ.name) AS [TableName]
      , SUM(sdmvPTNS.row_count) AS [RowCount]
FROM
      sys.objects AS sOBJ
      INNER JOIN sys.dm_db_partition_stats AS sdmvPTNS
            ON sOBJ.object_id = sdmvPTNS.object_id
WHERE 
      sOBJ.type = 'U'
      AND sOBJ.is_ms_shipped = 0x0
      AND sdmvPTNS.index_id < 2
GROUP BY
      sOBJ.schema_id
      , sOBJ.name
ORDER BY [TableName]
GO

数据库托管在Azure中,最终结果是:

来源:https://www.mssqltips.com/sqlservertip/2537/sql-server-row-count-for-all-tables-in-a-database/