如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案，但其他方法是受欢迎的
当前回答
select T.object_id, T.name, I.indid, I.rows
from Sys.tables T
left join Sys.sysindexes I
on (I.id = T.object_id and (indid =1 or indid =0 ))
where T.type='U'
这里indid=1表示群集索引，而indid=0表示堆索引
其他回答
我认为最短、最快、最简单的方法是:
SELECT
object_name(object_id) AS [Table],
SUM(row_count) AS [Count]
FROM
sys.dm_db_partition_stats
WHERE
--object_schema_name(object_id) = 'dbo' AND
index_id < 2
GROUP BY
object_id
我想分享对我有效的方法
SELECT
QUOTENAME(SCHEMA_NAME(sOBJ.schema_id)) + '.' + QUOTENAME(sOBJ.name) AS [TableName]
, SUM(sdmvPTNS.row_count) AS [RowCount]
FROM
sys.objects AS sOBJ
INNER JOIN sys.dm_db_partition_stats AS sdmvPTNS
ON sOBJ.object_id = sdmvPTNS.object_id
WHERE
sOBJ.type = 'U'
AND sOBJ.is_ms_shipped = 0x0
AND sdmvPTNS.index_id < 2
GROUP BY
sOBJ.schema_id
, sOBJ.name
ORDER BY [TableName]
GO
数据库托管在Azure中，最终结果是:
来源:https://www.mssqltips.com/sqlservertip/2537/sql-server-row-count-for-all-tables-in-a-database/
要在SQL Management Studio中获取该信息，右键单击数据库，然后选择Reports—> Standard Reports—> Disk Usage by Table。
如果你使用的是SQL Server 2005及以上版本，你也可以使用这个:
SELECT
t.NAME AS TableName,
i.name as indexName,
p.[Rows],
sum(a.total_pages) as TotalPages,
sum(a.used_pages) as UsedPages,
sum(a.data_pages) as DataPages,
(sum(a.total_pages) * 8) / 1024 as TotalSpaceMB,
(sum(a.used_pages) * 8) / 1024 as UsedSpaceMB,
(sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
t.NAME NOT LIKE 'dt%' AND
i.OBJECT_ID > 255 AND
i.index_id <= 1
GROUP BY
t.NAME, i.object_id, i.index_id, i.name, p.[Rows]
ORDER BY
object_name(i.object_id)
在我看来，它比sp_msforeachtable输出更容易处理。
SELECT
T.NAME AS 'TABLE NAME',
P.[ROWS] AS 'NO OF ROWS'
FROM SYS.TABLES T
INNER JOIN SYS.PARTITIONS P ON T.OBJECT_ID=P.OBJECT_ID;
