如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案，但其他方法是受欢迎的
当前回答
select T.object_id, T.name, I.indid, I.rows
from Sys.tables T
left join Sys.sysindexes I
on (I.id = T.object_id and (indid =1 or indid =0 ))
where T.type='U'
这里indid=1表示群集索引，而indid=0表示堆索引
其他回答
这种方法使用字符串连接来动态生成包含所有表及其计数的语句，就像原始问题中给出的示例:
SELECT COUNT(*) AS Count,'[dbo].[tbl1]' AS TableName FROM [dbo].[tbl1]
UNION ALL SELECT COUNT(*) AS Count,'[dbo].[tbl2]' AS TableName FROM [dbo].[tbl2]
UNION ALL SELECT...
最后用EXEC执行:
DECLARE @cmd VARCHAR(MAX)=STUFF(
(
SELECT 'UNION ALL SELECT COUNT(*) AS Count,'''
+ QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
+ ''' AS TableName FROM ' + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
FROM INFORMATION_SCHEMA.TABLES AS t
WHERE TABLE_TYPE='BASE TABLE'
FOR XML PATH('')
),1,10,'');
EXEC(@cmd);
Shnugo的答案是唯一一个工作在Azure的Externa表。(1) Azure SQL根本不支持sp_MSforeachtable;External表的partitions总是0。
我认为最短、最快、最简单的方法是:
SELECT
object_name(object_id) AS [Table],
SUM(row_count) AS [Count]
FROM
sys.dm_db_partition_stats
WHERE
--object_schema_name(object_id) = 'dbo' AND
index_id < 2
GROUP BY
object_id
首先想到的是使用sp_msForEachTable
exec sp_msforeachtable 'select count(*) from ?'
但是它没有列出表名，所以可以扩展到
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
这里的问题是，如果数据库有超过100个表，你会得到以下错误消息:
查询已超过最大值 可以的结果集的数目 显示在结果网格中。只有 前100个结果集是 显示在网格中。
所以我最终使用表变量来存储结果
declare @stats table (n sysname, c int)
insert into @stats
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
select
*
from @stats
order by c desc
我在http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=21021上找到了一个帮助我的片段:
select t.name TableName, i.rows Records
from sysobjects t, sysindexes i
where t.xtype = 'U' and i.id = t.id and i.indid in (0,1)
order by TableName;
