查询以列出数据库中每个表中的记录数量

如何列出数据库中每个表的行数。相当于

select count(*) from table1
select count(*) from table2
...
select count(*) from tableN

我会张贴一个解决方案，但其他方法是受欢迎的

当前回答

首先想到的是使用sp_msForEachTable

exec sp_msforeachtable 'select count(*) from ?'

但是它没有列出表名，所以可以扩展到

exec sp_msforeachtable 'select parsename(''?'', 1),  count(*) from ?'

这里的问题是，如果数据库有超过100个表，你会得到以下错误消息:

查询已超过最大值可以的结果集的数目显示在结果网格中。只有前100个结果集是显示在网格中。

所以我最终使用表变量来存储结果

declare @stats table (n sysname, c int)
insert into @stats
    exec sp_msforeachtable 'select parsename(''?'', 1),  count(*) from ?'
select 
    * 
from @stats
order by c desc

2009-09-18 10:28:52

其他回答

从这个问题中: https://dba.stackexchange.com/questions/114958/list-all-tables-from-all-user-databases/230411#230411

我在@Aaron Bertrand提供的答案中添加了记录计数，该答案列出了所有数据库和所有表。

DECLARE @src NVARCHAR(MAX), @sql NVARCHAR(MAX);

SELECT @sql = N'', @src = N' UNION ALL 
SELECT ''$d'' as ''database'', 
    s.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''schema'',
    t.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''table'' ,
    ind.rows as record_count
  FROM [$d].sys.schemas AS s
  INNER JOIN [$d].sys.tables AS t ON s.[schema_id] = t.[schema_id]
  INNER JOIN [$d].sys.sysindexes AS ind ON t.[object_id] = ind.[id]
  where ind.indid < 2';

SELECT @sql = @sql + REPLACE(@src, '$d', name)
  FROM sys.databases
  WHERE database_id > 4
    AND [state] = 0
    AND HAS_DBACCESS(name) = 1;

SET @sql = STUFF(@sql, 1, 10, CHAR(13) + CHAR(10));

PRINT @sql;
--EXEC sys.sp_executesql @sql;

2019-02-21 17:02:07

我在http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=21021上找到了一个帮助我的片段:

select t.name TableName, i.rows Records
from sysobjects t, sysindexes i
where t.xtype = 'U' and i.id = t.id and i.indid in (0,1)
order by TableName;

2013-01-04 19:47:32

接受的答案在Azure SQL上不适合我，这里有一个，它非常快，完全符合我的要求:

select t.name, s.row_count
from sys.tables t
join sys.dm_db_partition_stats s
  ON t.object_id = s.object_id
    and t.type_desc = 'USER_TABLE'
    and t.name not like '%dss%'
    and s.index_id = 1
order by s.row_count desc

2015-10-06 21:53:50