如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
当前回答
USE DatabaseName
CREATE TABLE #counts
(
table_name varchar(255),
row_count int
)
EXEC sp_MSForEachTable @command1='INSERT #counts (table_name, row_count) SELECT ''?'', COUNT(*) FROM ?'
SELECT table_name, row_count FROM #counts ORDER BY table_name, row_count DESC
DROP TABLE #counts
其他回答
我认为最短、最快、最简单的方法是:
SELECT
object_name(object_id) AS [Table],
SUM(row_count) AS [Count]
FROM
sys.dm_db_partition_stats
WHERE
--object_schema_name(object_id) = 'dbo' AND
index_id < 2
GROUP BY
object_id
我在http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=21021上找到了一个帮助我的片段:
select t.name TableName, i.rows Records
from sysobjects t, sysindexes i
where t.xtype = 'U' and i.id = t.id and i.indid in (0,1)
order by TableName;
要在SQL Management Studio中获取该信息,右键单击数据库,然后选择Reports—> Standard Reports—> Disk Usage by Table。
查找SQL reference (http://www.codeproject.com/Tips/811017/Fastest-way-to-find-row-count-of-all-tables-in-SQL)中所有表的行数的最快方法
SELECT T.name AS [TABLE NAME], I.rows AS [ROWCOUNT]
FROM sys.tables AS T
INNER JOIN sys.sysindexes AS I ON T.object_id = I.id
AND I.indid < 2
ORDER BY I.rows DESC
如果您使用MySQL >4。X你可以用这个:
select TABLE_NAME, TABLE_ROWS from information_schema.TABLES where TABLE_SCHEMA="test";
请记住,对于某些存储引擎,TABLE_ROWS只是一个近似值。