如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
当前回答
SELECT
T.NAME AS 'TABLE NAME',
P.[ROWS] AS 'NO OF ROWS'
FROM SYS.TABLES T
INNER JOIN SYS.PARTITIONS P ON T.OBJECT_ID=P.OBJECT_ID;
其他回答
如图所示,这将返回正确的计数,而使用元数据表的方法将只返回估计值。
CREATE PROCEDURE ListTableRowCounts
AS
BEGIN
SET NOCOUNT ON
CREATE TABLE #TableCounts
(
TableName VARCHAR(500),
CountOf INT
)
INSERT #TableCounts
EXEC sp_msForEachTable
'SELECT PARSENAME(''?'', 1),
COUNT(*) FROM ? WITH (NOLOCK)'
SELECT TableName , CountOf
FROM #TableCounts
ORDER BY TableName
DROP TABLE #TableCounts
END
GO
这种方法使用字符串连接来动态生成包含所有表及其计数的语句,就像原始问题中给出的示例:
SELECT COUNT(*) AS Count,'[dbo].[tbl1]' AS TableName FROM [dbo].[tbl1]
UNION ALL SELECT COUNT(*) AS Count,'[dbo].[tbl2]' AS TableName FROM [dbo].[tbl2]
UNION ALL SELECT...
最后用EXEC执行:
DECLARE @cmd VARCHAR(MAX)=STUFF(
(
SELECT 'UNION ALL SELECT COUNT(*) AS Count,'''
+ QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
+ ''' AS TableName FROM ' + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
FROM INFORMATION_SCHEMA.TABLES AS t
WHERE TABLE_TYPE='BASE TABLE'
FOR XML PATH('')
),1,10,'');
EXEC(@cmd);
如果您使用MySQL >4。X你可以用这个:
select TABLE_NAME, TABLE_ROWS from information_schema.TABLES where TABLE_SCHEMA="test";
请记住,对于某些存储引擎,TABLE_ROWS只是一个近似值。
接受的答案在Azure SQL上不适合我,这里有一个,它非常快,完全符合我的要求:
select t.name, s.row_count
from sys.tables t
join sys.dm_db_partition_stats s
ON t.object_id = s.object_id
and t.type_desc = 'USER_TABLE'
and t.name not like '%dss%'
and s.index_id = 1
order by s.row_count desc
Shnugo的答案是唯一一个工作在Azure的Externa表。(1) Azure SQL根本不支持sp_MSforeachtable;External表的partitions总是0。