如何列出数据库中每个表的行数。相当于

select count(*) from table1
select count(*) from table2
...
select count(*) from tableN

我会张贴一个解决方案,但其他方法是受欢迎的


当前回答

Shnugo的答案是唯一一个工作在Azure的Externa表。(1) Azure SQL根本不支持sp_MSforeachtable;External表的partitions总是0。

其他回答

如果你使用的是SQL Server 2005及以上版本,你也可以使用这个:

SELECT 
    t.NAME AS TableName,
    i.name as indexName,
    p.[Rows],
    sum(a.total_pages) as TotalPages, 
    sum(a.used_pages) as UsedPages, 
    sum(a.data_pages) as DataPages,
    (sum(a.total_pages) * 8) / 1024 as TotalSpaceMB, 
    (sum(a.used_pages) * 8) / 1024 as UsedSpaceMB, 
    (sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
WHERE 
    t.NAME NOT LIKE 'dt%' AND
    i.OBJECT_ID > 255 AND   
    i.index_id <= 1
GROUP BY 
    t.NAME, i.object_id, i.index_id, i.name, p.[Rows]
ORDER BY 
    object_name(i.object_id) 

在我看来,它比sp_msforeachtable输出更容易处理。

从这个问题中: https://dba.stackexchange.com/questions/114958/list-all-tables-from-all-user-databases/230411#230411

我在@Aaron Bertrand提供的答案中添加了记录计数,该答案列出了所有数据库和所有表。

DECLARE @src NVARCHAR(MAX), @sql NVARCHAR(MAX);

SELECT @sql = N'', @src = N' UNION ALL 
SELECT ''$d'' as ''database'', 
    s.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''schema'',
    t.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''table'' ,
    ind.rows as record_count
  FROM [$d].sys.schemas AS s
  INNER JOIN [$d].sys.tables AS t ON s.[schema_id] = t.[schema_id]
  INNER JOIN [$d].sys.sysindexes AS ind ON t.[object_id] = ind.[id]
  where ind.indid < 2';

SELECT @sql = @sql + REPLACE(@src, '$d', name)
  FROM sys.databases
  WHERE database_id > 4
    AND [state] = 0
    AND HAS_DBACCESS(name) = 1;

SET @sql = STUFF(@sql, 1, 10, CHAR(13) + CHAR(10));

PRINT @sql;
--EXEC sys.sp_executesql @sql;

以下是我对这个问题的看法。它包含所有模式,只列出带行的表。YMMV

select distinct schema_name(t.schema_id) as schema_name, t.name as 
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = 
p.index_id
where p.[Rows] > 0
order by schema_name;

Shnugo的答案是唯一一个工作在Azure的Externa表。(1) Azure SQL根本不支持sp_MSforeachtable;External表的partitions总是0。

这种方法使用字符串连接来动态生成包含所有表及其计数的语句,就像原始问题中给出的示例:

          SELECT COUNT(*) AS Count,'[dbo].[tbl1]' AS TableName FROM [dbo].[tbl1]
UNION ALL SELECT COUNT(*) AS Count,'[dbo].[tbl2]' AS TableName FROM [dbo].[tbl2]
UNION ALL SELECT...

最后用EXEC执行:

DECLARE @cmd VARCHAR(MAX)=STUFF(
                    (
                        SELECT 'UNION ALL SELECT COUNT(*) AS Count,''' 
                              + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME) 
                              + ''' AS TableName FROM ' + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
                        FROM INFORMATION_SCHEMA.TABLES AS t
                        WHERE TABLE_TYPE='BASE TABLE'
                        FOR XML PATH('')
                    ),1,10,'');
EXEC(@cmd);