如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案，但其他方法是受欢迎的
当前回答
如果您使用MySQL >4。X你可以用这个:
select TABLE_NAME, TABLE_ROWS from information_schema.TABLES where TABLE_SCHEMA="test";
请记住，对于某些存储引擎，TABLE_ROWS只是一个近似值。
其他回答
select T.object_id, T.name, I.indid, I.rows
from Sys.tables T
left join Sys.sysindexes I
on (I.id = T.object_id and (indid =1 or indid =0 ))
where T.type='U'
这里indid=1表示群集索引，而indid=0表示堆索引
SELECT ( Schema_name(A.schema_id) + '.' + A.NAME ) AS TableName,
Sum(B.rows)AS RecordCount
FROM sys.objects A INNER JOIN sys.partitions B
ON A.object_id = B.object_id WHERE A.type = 'U'
GROUP BY A.schema_id,A.NAME ;
QUERY_PHOTO
QUERY_RESULT_PHOTO
首先想到的是使用sp_msForEachTable
exec sp_msforeachtable 'select count(*) from ?'
但是它没有列出表名，所以可以扩展到
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
这里的问题是，如果数据库有超过100个表，你会得到以下错误消息:
查询已超过最大值 可以的结果集的数目 显示在结果网格中。只有 前100个结果集是 显示在网格中。
所以我最终使用表变量来存储结果
declare @stats table (n sysname, c int)
insert into @stats
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
select
*
from @stats
order by c desc
以下是我对这个问题的看法。它包含所有模式，只列出带行的表。YMMV
select distinct schema_name(t.schema_id) as schema_name, t.name as
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id =
p.index_id
where p.[Rows] > 0
order by schema_name;
查找SQL reference (http://www.codeproject.com/Tips/811017/Fastest-way-to-find-row-count-of-all-tables-in-SQL)中所有表的行数的最快方法
SELECT T.name AS [TABLE NAME], I.rows AS [ROWCOUNT]
FROM sys.tables AS T
INNER JOIN sys.sysindexes AS I ON T.object_id = I.id
AND I.indid < 2
ORDER BY I.rows DESC
