如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案，但其他方法是受欢迎的
当前回答
从这个问题中: https://dba.stackexchange.com/questions/114958/list-all-tables-from-all-user-databases/230411#230411
我在@Aaron Bertrand提供的答案中添加了记录计数，该答案列出了所有数据库和所有表。
DECLARE @src NVARCHAR(MAX), @sql NVARCHAR(MAX);
SELECT @sql = N'', @src = N' UNION ALL
SELECT ''$d'' as ''database'',
s.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''schema'',
t.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''table'' ,
ind.rows as record_count
FROM [$d].sys.schemas AS s
INNER JOIN [$d].sys.tables AS t ON s.[schema_id] = t.[schema_id]
INNER JOIN [$d].sys.sysindexes AS ind ON t.[object_id] = ind.[id]
where ind.indid < 2';
SELECT @sql = @sql + REPLACE(@src, '$d', name)
FROM sys.databases
WHERE database_id > 4
AND [state] = 0
AND HAS_DBACCESS(name) = 1;
SET @sql = STUFF(@sql, 1, 10, CHAR(13) + CHAR(10));
PRINT @sql;
--EXEC sys.sp_executesql @sql;
其他回答
要在SQL Management Studio中获取该信息，右键单击数据库，然后选择Reports—> Standard Reports—> Disk Usage by Table。
查找SQL reference (http://www.codeproject.com/Tips/811017/Fastest-way-to-find-row-count-of-all-tables-in-SQL)中所有表的行数的最快方法
SELECT T.name AS [TABLE NAME], I.rows AS [ROWCOUNT]
FROM sys.tables AS T
INNER JOIN sys.sysindexes AS I ON T.object_id = I.id
AND I.indid < 2
ORDER BY I.rows DESC
以下是我对这个问题的看法。它包含所有模式，只列出带行的表。YMMV
select distinct schema_name(t.schema_id) as schema_name, t.name as
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id =
p.index_id
where p.[Rows] > 0
order by schema_name;
select T.object_id, T.name, I.indid, I.rows
from Sys.tables T
left join Sys.sysindexes I
on (I.id = T.object_id and (indid =1 or indid =0 ))
where T.type='U'
这里indid=1表示群集索引，而indid=0表示堆索引
接受的答案在Azure SQL上不适合我，这里有一个，它非常快，完全符合我的要求:
select t.name, s.row_count
from sys.tables t
join sys.dm_db_partition_stats s
ON t.object_id = s.object_id
and t.type_desc = 'USER_TABLE'
and t.name not like '%dss%'
and s.index_id = 1
order by s.row_count desc
