如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
当前回答
从这个问题中: https://dba.stackexchange.com/questions/114958/list-all-tables-from-all-user-databases/230411#230411
我在@Aaron Bertrand提供的答案中添加了记录计数,该答案列出了所有数据库和所有表。
DECLARE @src NVARCHAR(MAX), @sql NVARCHAR(MAX);
SELECT @sql = N'', @src = N' UNION ALL
SELECT ''$d'' as ''database'',
s.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''schema'',
t.name COLLATE SQL_Latin1_General_CP1_CI_AI as ''table'' ,
ind.rows as record_count
FROM [$d].sys.schemas AS s
INNER JOIN [$d].sys.tables AS t ON s.[schema_id] = t.[schema_id]
INNER JOIN [$d].sys.sysindexes AS ind ON t.[object_id] = ind.[id]
where ind.indid < 2';
SELECT @sql = @sql + REPLACE(@src, '$d', name)
FROM sys.databases
WHERE database_id > 4
AND [state] = 0
AND HAS_DBACCESS(name) = 1;
SET @sql = STUFF(@sql, 1, 10, CHAR(13) + CHAR(10));
PRINT @sql;
--EXEC sys.sp_executesql @sql;
其他回答
这种方法使用字符串连接来动态生成包含所有表及其计数的语句,就像原始问题中给出的示例:
SELECT COUNT(*) AS Count,'[dbo].[tbl1]' AS TableName FROM [dbo].[tbl1]
UNION ALL SELECT COUNT(*) AS Count,'[dbo].[tbl2]' AS TableName FROM [dbo].[tbl2]
UNION ALL SELECT...
最后用EXEC执行:
DECLARE @cmd VARCHAR(MAX)=STUFF(
(
SELECT 'UNION ALL SELECT COUNT(*) AS Count,'''
+ QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
+ ''' AS TableName FROM ' + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
FROM INFORMATION_SCHEMA.TABLES AS t
WHERE TABLE_TYPE='BASE TABLE'
FOR XML PATH('')
),1,10,'');
EXEC(@cmd);
USE DatabaseName
CREATE TABLE #counts
(
table_name varchar(255),
row_count int
)
EXEC sp_MSForEachTable @command1='INSERT #counts (table_name, row_count) SELECT ''?'', COUNT(*) FROM ?'
SELECT table_name, row_count FROM #counts ORDER BY table_name, row_count DESC
DROP TABLE #counts
我想分享对我有效的方法
SELECT
QUOTENAME(SCHEMA_NAME(sOBJ.schema_id)) + '.' + QUOTENAME(sOBJ.name) AS [TableName]
, SUM(sdmvPTNS.row_count) AS [RowCount]
FROM
sys.objects AS sOBJ
INNER JOIN sys.dm_db_partition_stats AS sdmvPTNS
ON sOBJ.object_id = sdmvPTNS.object_id
WHERE
sOBJ.type = 'U'
AND sOBJ.is_ms_shipped = 0x0
AND sdmvPTNS.index_id < 2
GROUP BY
sOBJ.schema_id
, sOBJ.name
ORDER BY [TableName]
GO
数据库托管在Azure中,最终结果是:
来源:https://www.mssqltips.com/sqlservertip/2537/sql-server-row-count-for-all-tables-in-a-database/
如果你使用的是SQL Server 2005及以上版本,你也可以使用这个:
SELECT
t.NAME AS TableName,
i.name as indexName,
p.[Rows],
sum(a.total_pages) as TotalPages,
sum(a.used_pages) as UsedPages,
sum(a.data_pages) as DataPages,
(sum(a.total_pages) * 8) / 1024 as TotalSpaceMB,
(sum(a.used_pages) * 8) / 1024 as UsedSpaceMB,
(sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
t.NAME NOT LIKE 'dt%' AND
i.OBJECT_ID > 255 AND
i.index_id <= 1
GROUP BY
t.NAME, i.object_id, i.index_id, i.name, p.[Rows]
ORDER BY
object_name(i.object_id)
在我看来,它比sp_msforeachtable输出更容易处理。
如图所示,这将返回正确的计数,而使用元数据表的方法将只返回估计值。
CREATE PROCEDURE ListTableRowCounts
AS
BEGIN
SET NOCOUNT ON
CREATE TABLE #TableCounts
(
TableName VARCHAR(500),
CountOf INT
)
INSERT #TableCounts
EXEC sp_msForEachTable
'SELECT PARSENAME(''?'', 1),
COUNT(*) FROM ? WITH (NOLOCK)'
SELECT TableName , CountOf
FROM #TableCounts
ORDER BY TableName
DROP TABLE #TableCounts
END
GO