如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
当前回答
我想分享对我有效的方法
SELECT
QUOTENAME(SCHEMA_NAME(sOBJ.schema_id)) + '.' + QUOTENAME(sOBJ.name) AS [TableName]
, SUM(sdmvPTNS.row_count) AS [RowCount]
FROM
sys.objects AS sOBJ
INNER JOIN sys.dm_db_partition_stats AS sdmvPTNS
ON sOBJ.object_id = sdmvPTNS.object_id
WHERE
sOBJ.type = 'U'
AND sOBJ.is_ms_shipped = 0x0
AND sdmvPTNS.index_id < 2
GROUP BY
sOBJ.schema_id
, sOBJ.name
ORDER BY [TableName]
GO
数据库托管在Azure中,最终结果是:
来源:https://www.mssqltips.com/sqlservertip/2537/sql-server-row-count-for-all-tables-in-a-database/
其他回答
如果你使用的是SQL Server 2005及以上版本,你也可以使用这个:
SELECT
t.NAME AS TableName,
i.name as indexName,
p.[Rows],
sum(a.total_pages) as TotalPages,
sum(a.used_pages) as UsedPages,
sum(a.data_pages) as DataPages,
(sum(a.total_pages) * 8) / 1024 as TotalSpaceMB,
(sum(a.used_pages) * 8) / 1024 as UsedSpaceMB,
(sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
t.NAME NOT LIKE 'dt%' AND
i.OBJECT_ID > 255 AND
i.index_id <= 1
GROUP BY
t.NAME, i.object_id, i.index_id, i.name, p.[Rows]
ORDER BY
object_name(i.object_id)
在我看来,它比sp_msforeachtable输出更容易处理。
首先想到的是使用sp_msForEachTable
exec sp_msforeachtable 'select count(*) from ?'
但是它没有列出表名,所以可以扩展到
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
这里的问题是,如果数据库有超过100个表,你会得到以下错误消息:
查询已超过最大值 可以的结果集的数目 显示在结果网格中。只有 前100个结果集是 显示在网格中。
所以我最终使用表变量来存储结果
declare @stats table (n sysname, c int)
insert into @stats
exec sp_msforeachtable 'select parsename(''?'', 1), count(*) from ?'
select
*
from @stats
order by c desc
这种方法使用字符串连接来动态生成包含所有表及其计数的语句,就像原始问题中给出的示例:
SELECT COUNT(*) AS Count,'[dbo].[tbl1]' AS TableName FROM [dbo].[tbl1]
UNION ALL SELECT COUNT(*) AS Count,'[dbo].[tbl2]' AS TableName FROM [dbo].[tbl2]
UNION ALL SELECT...
最后用EXEC执行:
DECLARE @cmd VARCHAR(MAX)=STUFF(
(
SELECT 'UNION ALL SELECT COUNT(*) AS Count,'''
+ QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
+ ''' AS TableName FROM ' + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
FROM INFORMATION_SCHEMA.TABLES AS t
WHERE TABLE_TYPE='BASE TABLE'
FOR XML PATH('')
),1,10,'');
EXEC(@cmd);
SELECT
T.NAME AS 'TABLE NAME',
P.[ROWS] AS 'NO OF ROWS'
FROM SYS.TABLES T
INNER JOIN SYS.PARTITIONS P ON T.OBJECT_ID=P.OBJECT_ID;
以下是我对这个问题的看法。它包含所有模式,只列出带行的表。YMMV
select distinct schema_name(t.schema_id) as schema_name, t.name as
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id =
p.index_id
where p.[Rows] > 0
order by schema_name;