以下是我对这个问题的看法。它包含所有模式，只列出带行的表。YMMV

select distinct schema_name(t.schema_id) as schema_name, t.name as 
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = 
p.index_id
where p.[Rows] > 0
order by schema_name;

SELECT 
    T.NAME AS 'TABLE NAME',
    P.[ROWS] AS 'NO OF ROWS'
FROM SYS.TABLES T 
INNER JOIN  SYS.PARTITIONS P ON T.OBJECT_ID=P.OBJECT_ID;

以下是我对这个问题的看法。它包含所有模式，只列出带行的表。YMMV

select distinct schema_name(t.schema_id) as schema_name, t.name as 
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = 
p.index_id
where p.[Rows] > 0
order by schema_name;

如果您使用MySQL >4。X你可以用这个:

select TABLE_NAME, TABLE_ROWS from information_schema.TABLES where TABLE_SCHEMA="test";

请记住，对于某些存储引擎，TABLE_ROWS只是一个近似值。

要在SQL Management Studio中获取该信息，右键单击数据库，然后选择Reports—> Standard Reports—> Disk Usage by Table。

如图所示，这将返回正确的计数，而使用元数据表的方法将只返回估计值。

    CREATE PROCEDURE ListTableRowCounts 
    AS 
    BEGIN 
        SET NOCOUNT ON 

        CREATE TABLE #TableCounts
        ( 
            TableName VARCHAR(500), 
            CountOf INT 
        ) 

        INSERT #TableCounts
            EXEC sp_msForEachTable 
                'SELECT PARSENAME(''?'', 1), 
                COUNT(*) FROM ? WITH (NOLOCK)' 

        SELECT TableName , CountOf 
            FROM #TableCounts
            ORDER BY TableName 

        DROP TABLE #TableCounts
    END
    GO