如何列出数据库中每个表的行数。相当于

select count(*) from table1
select count(*) from table2
...
select count(*) from tableN

我会张贴一个解决方案,但其他方法是受欢迎的


当前回答

我认为最短、最快、最简单的方法是:

SELECT
    object_name(object_id) AS [Table],
    SUM(row_count) AS [Count]
FROM
    sys.dm_db_partition_stats
WHERE
    --object_schema_name(object_id) = 'dbo' AND 
    index_id < 2
GROUP BY
    object_id

其他回答

        SELECT ( Schema_name(A.schema_id) + '.' + A.NAME ) AS TableName,
 Sum(B.rows)AS RecordCount 
    FROM   sys.objects A INNER JOIN sys.partitions B 
    ON A.object_id = B.object_id WHERE  A.type = 'U' 
        GROUP  BY A.schema_id,A.NAME ;

QUERY_PHOTO

QUERY_RESULT_PHOTO

如果你使用的是SQL Server 2005及以上版本,你也可以使用这个:

SELECT 
    t.NAME AS TableName,
    i.name as indexName,
    p.[Rows],
    sum(a.total_pages) as TotalPages, 
    sum(a.used_pages) as UsedPages, 
    sum(a.data_pages) as DataPages,
    (sum(a.total_pages) * 8) / 1024 as TotalSpaceMB, 
    (sum(a.used_pages) * 8) / 1024 as UsedSpaceMB, 
    (sum(a.data_pages) * 8) / 1024 as DataSpaceMB
FROM 
    sys.tables t
INNER JOIN      
    sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN 
    sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN 
    sys.allocation_units a ON p.partition_id = a.container_id
WHERE 
    t.NAME NOT LIKE 'dt%' AND
    i.OBJECT_ID > 255 AND   
    i.index_id <= 1
GROUP BY 
    t.NAME, i.object_id, i.index_id, i.name, p.[Rows]
ORDER BY 
    object_name(i.object_id) 

在我看来,它比sp_msforeachtable输出更容易处理。

SELECT 
    T.NAME AS 'TABLE NAME',
    P.[ROWS] AS 'NO OF ROWS'
FROM SYS.TABLES T 
INNER JOIN  SYS.PARTITIONS P ON T.OBJECT_ID=P.OBJECT_ID;

这种方法使用字符串连接来动态生成包含所有表及其计数的语句,就像原始问题中给出的示例:

          SELECT COUNT(*) AS Count,'[dbo].[tbl1]' AS TableName FROM [dbo].[tbl1]
UNION ALL SELECT COUNT(*) AS Count,'[dbo].[tbl2]' AS TableName FROM [dbo].[tbl2]
UNION ALL SELECT...

最后用EXEC执行:

DECLARE @cmd VARCHAR(MAX)=STUFF(
                    (
                        SELECT 'UNION ALL SELECT COUNT(*) AS Count,''' 
                              + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME) 
                              + ''' AS TableName FROM ' + QUOTENAME(t.TABLE_SCHEMA) + '.' + QUOTENAME(t.TABLE_NAME)
                        FROM INFORMATION_SCHEMA.TABLES AS t
                        WHERE TABLE_TYPE='BASE TABLE'
                        FOR XML PATH('')
                    ),1,10,'');
EXEC(@cmd);

以下是我对这个问题的看法。它包含所有模式,只列出带行的表。YMMV

select distinct schema_name(t.schema_id) as schema_name, t.name as 
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = 
p.index_id
where p.[Rows] > 0
order by schema_name;