如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
如何列出数据库中每个表的行数。相当于
select count(*) from table1
select count(*) from table2
...
select count(*) from tableN
我会张贴一个解决方案,但其他方法是受欢迎的
当前回答
我认为最短、最快、最简单的方法是:
SELECT
object_name(object_id) AS [Table],
SUM(row_count) AS [Count]
FROM
sys.dm_db_partition_stats
WHERE
--object_schema_name(object_id) = 'dbo' AND
index_id < 2
GROUP BY
object_id
其他回答
select T.object_id, T.name, I.indid, I.rows
from Sys.tables T
left join Sys.sysindexes I
on (I.id = T.object_id and (indid =1 or indid =0 ))
where T.type='U'
这里indid=1表示群集索引,而indid=0表示堆索引
USE DatabaseName
CREATE TABLE #counts
(
table_name varchar(255),
row_count int
)
EXEC sp_MSForEachTable @command1='INSERT #counts (table_name, row_count) SELECT ''?'', COUNT(*) FROM ?'
SELECT table_name, row_count FROM #counts ORDER BY table_name, row_count DESC
DROP TABLE #counts
如果您使用MySQL >4。X你可以用这个:
select TABLE_NAME, TABLE_ROWS from information_schema.TABLES where TABLE_SCHEMA="test";
请记住,对于某些存储引擎,TABLE_ROWS只是一个近似值。
要在SQL Management Studio中获取该信息,右键单击数据库,然后选择Reports—> Standard Reports—> Disk Usage by Table。
我在http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=21021上找到了一个帮助我的片段:
select t.name TableName, i.rows Records
from sysobjects t, sysindexes i
where t.xtype = 'U' and i.id = t.id and i.indid in (0,1)
order by TableName;