我认为最短、最快、最简单的方法是:

SELECT
    object_name(object_id) AS [Table],
    SUM(row_count) AS [Count]
FROM
    sys.dm_db_partition_stats
WHERE
    --object_schema_name(object_id) = 'dbo' AND 
    index_id < 2
GROUP BY
    object_id

接受的答案在Azure SQL上不适合我，这里有一个，它非常快，完全符合我的要求:

select t.name, s.row_count
from sys.tables t
join sys.dm_db_partition_stats s
  ON t.object_id = s.object_id
    and t.type_desc = 'USER_TABLE'
    and t.name not like '%dss%'
    and s.index_id = 1
order by s.row_count desc

SELECT 
    T.NAME AS 'TABLE NAME',
    P.[ROWS] AS 'NO OF ROWS'
FROM SYS.TABLES T 
INNER JOIN  SYS.PARTITIONS P ON T.OBJECT_ID=P.OBJECT_ID;

sp_MSForEachTable 'DECLARE @t AS VARCHAR(MAX); 
SELECT @t = CAST(COUNT(1) as VARCHAR(MAX)) 
+ CHAR(9) + CHAR(9) + ''?'' FROM ? ; PRINT @t'

输出:

这个sql脚本给出了所选数据库中每个表的模式、表名和行数:

SELECT SCHEMA_NAME(schema_id) AS [SchemaName],
[Tables].name AS [TableName],
SUM([Partitions].[rows]) AS [TotalRowCount]
FROM sys.tables AS [Tables]
JOIN sys.partitions AS [Partitions]
ON [Tables].[object_id] = [Partitions].[object_id]
AND [Partitions].index_id IN ( 0, 1 )
-- WHERE [Tables].name = N'name of the table'
GROUP BY SCHEMA_NAME(schema_id), [Tables].name
order by [TotalRowCount] desc

裁判:https://blog.sqlauthority.com/2017/05/24/sql-server-find-row-count-every-table-database-efficiently/

另一种表达方式:

SELECT  o.NAME TABLENAME,
  i.rowcnt 
FROM sysindexes AS i
  INNER JOIN sysobjects AS o ON i.id = o.id 
WHERE i.indid < 2  AND OBJECTPROPERTY(o.id, 'IsMSShipped') = 0
ORDER BY i.rowcnt desc

我认为最短、最快、最简单的方法是:

SELECT
    object_name(object_id) AS [Table],
    SUM(row_count) AS [Count]
FROM
    sys.dm_db_partition_stats
WHERE
    --object_schema_name(object_id) = 'dbo' AND 
    index_id < 2
GROUP BY
    object_id