sp_MSForEachTable 'DECLARE @t AS VARCHAR(MAX); 
SELECT @t = CAST(COUNT(1) as VARCHAR(MAX)) 
+ CHAR(9) + CHAR(9) + ''?'' FROM ? ; PRINT @t'

输出:

这个sql脚本给出了所选数据库中每个表的模式、表名和行数:

SELECT SCHEMA_NAME(schema_id) AS [SchemaName],
[Tables].name AS [TableName],
SUM([Partitions].[rows]) AS [TotalRowCount]
FROM sys.tables AS [Tables]
JOIN sys.partitions AS [Partitions]
ON [Tables].[object_id] = [Partitions].[object_id]
AND [Partitions].index_id IN ( 0, 1 )
-- WHERE [Tables].name = N'name of the table'
GROUP BY SCHEMA_NAME(schema_id), [Tables].name
order by [TotalRowCount] desc

裁判:https://blog.sqlauthority.com/2017/05/24/sql-server-find-row-count-every-table-database-efficiently/

另一种表达方式:

SELECT  o.NAME TABLENAME,
  i.rowcnt 
FROM sysindexes AS i
  INNER JOIN sysobjects AS o ON i.id = o.id 
WHERE i.indid < 2  AND OBJECTPROPERTY(o.id, 'IsMSShipped') = 0
ORDER BY i.rowcnt desc

以下是我对这个问题的看法。它包含所有模式，只列出带行的表。YMMV

select distinct schema_name(t.schema_id) as schema_name, t.name as 
table_name, p.[Rows]
from sys.tables as t
INNER JOIN sys.indexes as i ON t.OBJECT_ID = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = 
p.index_id
where p.[Rows] > 0
order by schema_name;

我认为最短、最快、最简单的方法是:

SELECT
    object_name(object_id) AS [Table],
    SUM(row_count) AS [Count]
FROM
    sys.dm_db_partition_stats
WHERE
    --object_schema_name(object_id) = 'dbo' AND 
    index_id < 2
GROUP BY
    object_id

首先想到的是使用sp_msForEachTable

exec sp_msforeachtable 'select count(*) from ?'

但是它没有列出表名，所以可以扩展到

exec sp_msforeachtable 'select parsename(''?'', 1),  count(*) from ?'

这里的问题是，如果数据库有超过100个表，你会得到以下错误消息:

查询已超过最大值 可以的结果集的数目 显示在结果网格中。只有 前100个结果集是 显示在网格中。

所以我最终使用表变量来存储结果

declare @stats table (n sysname, c int)
insert into @stats
    exec sp_msforeachtable 'select parsename(''?'', 1),  count(*) from ?'
select 
    * 
from @stats
order by c desc

我在http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=21021上找到了一个帮助我的片段:

select t.name TableName, i.rows Records
from sysobjects t, sysindexes i
where t.xtype = 'U' and i.id = t.id and i.indid in (0,1)
order by TableName;