在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?

我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。

代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。


当前回答

您还可以使用CodeFluent Runtime,这是一组免费的工具。它提供了一个SingleInstance类来实现单个实例应用程序。

其他回答

Just some thoughts: There are cases when requiring that only one instance of an application is not "lame" as some would have you believe. Database apps, etc. are an order of magnitude more difficult if one allows multiple instances of the app for a single user to access a database (you know, all that updating all the records that are open in multiple instances of the app on the users machine, etc.). First, for the "name collision thing, don't use a human readable name - use a GUID instead or, even better a GUID + the human readable name. Chances of name collision just dropped off the radar and the Mutex doesn't care. As someone pointed out, a DOS attack would suck, but if the malicious person has gone to the trouble of getting the mutex name and incorporating it into their app, you are pretty much a target anyway and will have to do MUCH more to protect yourself than just fiddle a mutex name. Also, if one uses the variant of: new Mutex(true, "some GUID plus Name", out AIsFirstInstance), you already have your indicator as to whether or not the Mutex is the first instance.

[我在下面提供了控制台和wpf应用程序的示例代码。]

在创建命名的Mutex实例后,只需检查createdNew变量的值(示例如下!)。

布尔值createdNew将返回false:

如果命名为“YourApplicationNameHere”的互斥锁实例已经存在 在系统某处创建

布尔值createdNew将返回true:

如果这是第一个名为“YourApplicationNameHere”的互斥锁 系统。

控制台应用程序-示例:

static Mutex m = null;

static void Main(string[] args)
{
    const string mutexName = "YourApplicationNameHere";
    bool createdNew = false;

    try
    {
        // Initializes a new instance of the Mutex class with a Boolean value that indicates 
        // whether the calling thread should have initial ownership of the mutex, a string that is the name of the mutex, 
        // and a Boolean value that, when the method returns, indicates whether the calling thread was granted initial ownership of the mutex.

        using (m = new Mutex(true, mutexName, out createdNew))
        {
            if (!createdNew)
            {
                Console.WriteLine("instance is alreday running... shutting down !!!");
                Console.Read();
                return; // Exit the application
            }

            // Run your windows forms app here
            Console.WriteLine("Single instance app is running!");
            Console.ReadLine();
        }


    }
    catch (Exception ex)
    {

        Console.WriteLine(ex.Message);
        Console.ReadLine();
    }
}

WPF-Example:

public partial class App : Application
{
static Mutex m = null;

protected override void OnStartup(StartupEventArgs e)
{

    const string mutexName = "YourApplicationNameHere";
    bool createdNew = false;

    try
    {
        // Initializes a new instance of the Mutex class with a Boolean value that indicates 
        // whether the calling thread should have initial ownership of the mutex, a string that is the name of the mutex, 
        // and a Boolean value that, when the method returns, indicates whether the calling thread was granted initial ownership of the mutex.

        m = new Mutex(true, mutexName, out createdNew);

        if (!createdNew)
        {
            Current.Shutdown(); // Exit the application
        }

    }
    catch (Exception)
    {
        throw;
    }

    base.OnStartup(e);
}


protected override void OnExit(ExitEventArgs e)
{
    if (m != null)
    {
        m.Dispose();
    }
    base.OnExit(e);
}
}

看起来有一个很好的方法来处理这个问题:

WPF单实例应用程序

这提供了一个类,您可以添加它来管理所有互斥量和消息传递的cruff,从而将实现简化到非常简单的程度。

这是我的两分钱

 static class Program
    {
        [STAThread]
        static void Main()
        {
            bool createdNew;
            using (new Mutex(true, "MyApp", out createdNew))
            {
                if (createdNew) {
                    Application.EnableVisualStyles();
                    Application.SetCompatibleTextRenderingDefault(false);
                    var mainClass = new SynGesturesLogic();
                    Application.ApplicationExit += mainClass.tray_exit;
                    Application.Run();
                }
                else
                {
                    var current = Process.GetCurrentProcess();
                    foreach (var process in Process.GetProcessesByName(current.ProcessName).Where(process => process.Id != current.Id))
                    {
                        NativeMethods.SetForegroundWindow(process.MainWindowHandle);
                        break;
                    }
                }
            }
        }
    }

请检查这里提出的解决方案,它使用信号量来确定现有实例是否已经在运行,适用于WPF应用程序,并且可以通过使用TcpListener和TcpClient将参数从第二个实例传递给第一个已经运行的实例:

它不仅适用于。net Framework,也适用于。net Core。