在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
当前回答
这是通过事件实现的相同的事情。
public enum ApplicationSingleInstanceMode
{
CurrentUserSession,
AllSessionsOfCurrentUser,
Pc
}
public class ApplicationSingleInstancePerUser: IDisposable
{
private readonly EventWaitHandle _event;
/// <summary>
/// Shows if the current instance of ghost is the first
/// </summary>
public bool FirstInstance { get; private set; }
/// <summary>
/// Initializes
/// </summary>
/// <param name="applicationName">The application name</param>
/// <param name="mode">The single mode</param>
public ApplicationSingleInstancePerUser(string applicationName, ApplicationSingleInstanceMode mode = ApplicationSingleInstanceMode.CurrentUserSession)
{
string name;
if (mode == ApplicationSingleInstanceMode.CurrentUserSession)
name = $"Local\\{applicationName}";
else if (mode == ApplicationSingleInstanceMode.AllSessionsOfCurrentUser)
name = $"Global\\{applicationName}{Environment.UserDomainName}";
else
name = $"Global\\{applicationName}";
try
{
bool created;
_event = new EventWaitHandle(false, EventResetMode.ManualReset, name, out created);
FirstInstance = created;
}
catch
{
}
}
public void Dispose()
{
_event.Dispose();
}
}
其他回答
下面是一个示例,它允许您拥有应用程序的单个实例。当加载任何新实例时,它们将参数传递给正在运行的主实例。
public partial class App : Application
{
private static Mutex SingleMutex;
public static uint MessageId;
private void Application_Startup(object sender, StartupEventArgs e)
{
IntPtr Result;
IntPtr SendOk;
Win32.COPYDATASTRUCT CopyData;
string[] Args;
IntPtr CopyDataMem;
bool AllowMultipleInstances = false;
Args = Environment.GetCommandLineArgs();
// TODO: Replace {00000000-0000-0000-0000-000000000000} with your application's GUID
MessageId = Win32.RegisterWindowMessage("{00000000-0000-0000-0000-000000000000}");
SingleMutex = new Mutex(false, "AppName");
if ((AllowMultipleInstances) || (!AllowMultipleInstances && SingleMutex.WaitOne(1, true)))
{
new Main();
}
else if (Args.Length > 1)
{
foreach (Process Proc in Process.GetProcesses())
{
SendOk = Win32.SendMessageTimeout(Proc.MainWindowHandle, MessageId, IntPtr.Zero, IntPtr.Zero,
Win32.SendMessageTimeoutFlags.SMTO_BLOCK | Win32.SendMessageTimeoutFlags.SMTO_ABORTIFHUNG,
2000, out Result);
if (SendOk == IntPtr.Zero)
continue;
if ((uint)Result != MessageId)
continue;
CopyDataMem = Marshal.AllocHGlobal(Marshal.SizeOf(typeof(Win32.COPYDATASTRUCT)));
CopyData.dwData = IntPtr.Zero;
CopyData.cbData = Args[1].Length*2;
CopyData.lpData = Marshal.StringToHGlobalUni(Args[1]);
Marshal.StructureToPtr(CopyData, CopyDataMem, false);
Win32.SendMessageTimeout(Proc.MainWindowHandle, Win32.WM_COPYDATA, IntPtr.Zero, CopyDataMem,
Win32.SendMessageTimeoutFlags.SMTO_BLOCK | Win32.SendMessageTimeoutFlags.SMTO_ABORTIFHUNG,
5000, out Result);
Marshal.FreeHGlobal(CopyData.lpData);
Marshal.FreeHGlobal(CopyDataMem);
}
Shutdown(0);
}
}
}
public partial class Main : Window
{
private void Window_Loaded(object sender, RoutedEventArgs e)
{
HwndSource Source;
Source = HwndSource.FromHwnd(new WindowInteropHelper(this).Handle);
Source.AddHook(new HwndSourceHook(Window_Proc));
}
private IntPtr Window_Proc(IntPtr hWnd, int Msg, IntPtr wParam, IntPtr lParam, ref bool Handled)
{
Win32.COPYDATASTRUCT CopyData;
string Path;
if (Msg == Win32.WM_COPYDATA)
{
CopyData = (Win32.COPYDATASTRUCT)Marshal.PtrToStructure(lParam, typeof(Win32.COPYDATASTRUCT));
Path = Marshal.PtrToStringUni(CopyData.lpData, CopyData.cbData / 2);
if (WindowState == WindowState.Minimized)
{
// Restore window from tray
}
// Do whatever we want with information
Activate();
Focus();
}
if (Msg == App.MessageId)
{
Handled = true;
return new IntPtr(App.MessageId);
}
return IntPtr.Zero;
}
}
public class Win32
{
public const uint WM_COPYDATA = 0x004A;
public struct COPYDATASTRUCT
{
public IntPtr dwData;
public int cbData;
public IntPtr lpData;
}
[Flags]
public enum SendMessageTimeoutFlags : uint
{
SMTO_NORMAL = 0x0000,
SMTO_BLOCK = 0x0001,
SMTO_ABORTIFHUNG = 0x0002,
SMTO_NOTIMEOUTIFNOTHUNG = 0x0008
}
[DllImport("user32.dll", SetLastError=true, CharSet=CharSet.Auto)]
public static extern uint RegisterWindowMessage(string lpString);
[DllImport("user32.dll")]
public static extern IntPtr SendMessageTimeout(
IntPtr hWnd, uint Msg, IntPtr wParam, IntPtr lParam,
SendMessageTimeoutFlags fuFlags, uint uTimeout, out IntPtr lpdwResult);
}
我添加了一个sendMessage方法到NativeMethods类。
显然,如果应用程序没有显示在任务栏中,postmessage方法不会工作,但是使用sendmessage方法解决了这个问题。
class NativeMethods
{
public const int HWND_BROADCAST = 0xffff;
public static readonly int WM_SHOWME = RegisterWindowMessage("WM_SHOWME");
[DllImport("user32")]
public static extern bool PostMessage(IntPtr hwnd, int msg, IntPtr wparam, IntPtr lparam);
[DllImport("user32.dll", CharSet = CharSet.Auto)]
public static extern IntPtr SendMessage(IntPtr hWnd, int Msg, IntPtr wParam, IntPtr lParam);
[DllImport("user32")]
public static extern int RegisterWindowMessage(string message);
}
这是我的两分钱
static class Program
{
[STAThread]
static void Main()
{
bool createdNew;
using (new Mutex(true, "MyApp", out createdNew))
{
if (createdNew) {
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
var mainClass = new SynGesturesLogic();
Application.ApplicationExit += mainClass.tray_exit;
Application.Run();
}
else
{
var current = Process.GetCurrentProcess();
foreach (var process in Process.GetProcessesByName(current.ProcessName).Where(process => process.Id != current.Id))
{
NativeMethods.SetForegroundWindow(process.MainWindowHandle);
break;
}
}
}
}
}
请检查这里提出的解决方案,它使用信号量来确定现有实例是否已经在运行,适用于WPF应用程序,并且可以通过使用TcpListener和TcpClient将参数从第二个实例传递给第一个已经运行的实例:
它不仅适用于。net Framework,也适用于。net Core。
基于Matt Davis的答案,为方便起见包装成一个类。
public static class SingleAppInstanceChecker
{
/// <summary>
/// Arbitrary unique string
/// </summary>
private static Mutex _mutex = new Mutex(true, "0d12ad74-026f-40c3-bdae-e178ddee8602");
public static bool IsNotRunning()
{
return _mutex.WaitOne(TimeSpan.Zero, true);
}
}
使用示例:
private void Application_Startup(object sender, StartupEventArgs e)
{
if (!SingleAppInstanceChecker.IsNotRunning())
{
MessageBox.Show("Application is already running.");
// Exit application using:
// Environment.Exit(1);
// Application.Current.Shutdown();
// Etc...
return;
}
// Allow startup and continue with normal processing
// ...
}