在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
当前回答
请看下面的代码。它是防止一个WPF应用程序有多个实例的一个很好的简单解决方案。
private void Application_Startup(object sender, StartupEventArgs e)
{
Process thisProc = Process.GetCurrentProcess();
if (Process.GetProcessesByName(thisProc.ProcessName).Length > 1)
{
MessageBox.Show("Application running");
Application.Current.Shutdown();
return;
}
var wLogin = new LoginWindow();
if (wLogin.ShowDialog() == true)
{
var wMain = new Main();
wMain.WindowState = WindowState.Maximized;
wMain.Show();
}
else
{
Application.Current.Shutdown();
}
}
其他回答
我添加了一个sendMessage方法到NativeMethods类。
显然,如果应用程序没有显示在任务栏中,postmessage方法不会工作,但是使用sendmessage方法解决了这个问题。
class NativeMethods
{
public const int HWND_BROADCAST = 0xffff;
public static readonly int WM_SHOWME = RegisterWindowMessage("WM_SHOWME");
[DllImport("user32")]
public static extern bool PostMessage(IntPtr hwnd, int msg, IntPtr wparam, IntPtr lparam);
[DllImport("user32.dll", CharSet = CharSet.Auto)]
public static extern IntPtr SendMessage(IntPtr hWnd, int Msg, IntPtr wParam, IntPtr lParam);
[DllImport("user32")]
public static extern int RegisterWindowMessage(string message);
}
我在这里找不到一个简单的解决方案,所以我希望有人会喜欢这个:
更新2018-09-20
把这段代码放在Program.cs中:
using System.Diagnostics;
static void Main()
{
Process thisProcess = Process.GetCurrentProcess();
Process[] allProcesses = Process.GetProcessesByName(thisProcess.ProcessName);
if (allProcesses.Length > 1)
{
// Don't put a MessageBox in here because the user could spam this MessageBox.
return;
}
// Optional code. If you don't want that someone runs your ".exe" with a different name:
string exeName = AppDomain.CurrentDomain.FriendlyName;
// in debug mode, don't forget that you don't use your normal .exe name.
// Debug uses the .vshost.exe.
if (exeName != "the name of your executable.exe")
{
// You can add a MessageBox here if you want.
// To point out to users that the name got changed and maybe what the name should be or something like that^^
MessageBox.Show("The executable name should be \"the name of your executable.exe\"",
"Wrong executable name", MessageBoxButtons.OK, MessageBoxIcon.Error);
return;
}
// Following code is default code:
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new MainForm());
}
下面是我使用的一个轻量级解决方案,它允许应用程序将一个已经存在的窗口带到前台,而无需求助于自定义窗口消息或盲目地搜索进程名。
[DllImport("user32.dll")]
static extern bool SetForegroundWindow(IntPtr hWnd);
static readonly string guid = "<Application Guid>";
static void Main()
{
Mutex mutex = null;
if (!CreateMutex(out mutex))
return;
// Application startup code.
Environment.SetEnvironmentVariable(guid, null, EnvironmentVariableTarget.User);
}
static bool CreateMutex(out Mutex mutex)
{
bool createdNew = false;
mutex = new Mutex(false, guid, out createdNew);
if (createdNew)
{
Process process = Process.GetCurrentProcess();
string value = process.Id.ToString();
Environment.SetEnvironmentVariable(guid, value, EnvironmentVariableTarget.User);
}
else
{
string value = Environment.GetEnvironmentVariable(guid, EnvironmentVariableTarget.User);
Process process = null;
int processId = -1;
if (int.TryParse(value, out processId))
process = Process.GetProcessById(processId);
if (process == null || !SetForegroundWindow(process.MainWindowHandle))
MessageBox.Show("Unable to start application. An instance of this application is already running.");
}
return createdNew;
}
编辑:你也可以静态地存储和初始化互斥量和createdNew,但是一旦你完成了它,你需要显式地释放/释放互斥量。就我个人而言,我更喜欢将互斥锁保持在本地,因为即使应用程序在未到达Main结束时就关闭,它也会被自动销毁。
一个新的使用互斥和IPC的东西,也传递任何命令行参数到运行的实例,是WPF单实例应用程序。
这是我的两分钱
static class Program
{
[STAThread]
static void Main()
{
bool createdNew;
using (new Mutex(true, "MyApp", out createdNew))
{
if (createdNew) {
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
var mainClass = new SynGesturesLogic();
Application.ApplicationExit += mainClass.tray_exit;
Application.Run();
}
else
{
var current = Process.GetCurrentProcess();
foreach (var process in Process.GetProcessesByName(current.ProcessName).Where(process => process.Id != current.Id))
{
NativeMethods.SetForegroundWindow(process.MainWindowHandle);
break;
}
}
}
}
}