在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?

我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。

代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。


当前回答

我添加了一个sendMessage方法到NativeMethods类。

显然,如果应用程序没有显示在任务栏中,postmessage方法不会工作,但是使用sendmessage方法解决了这个问题。

class NativeMethods
{
    public const int HWND_BROADCAST = 0xffff;
    public static readonly int WM_SHOWME = RegisterWindowMessage("WM_SHOWME");
    [DllImport("user32")]
    public static extern bool PostMessage(IntPtr hwnd, int msg, IntPtr wparam, IntPtr lparam);
    [DllImport("user32.dll", CharSet = CharSet.Auto)]
    public static extern IntPtr SendMessage(IntPtr hWnd, int Msg, IntPtr wParam, IntPtr lParam);
    [DllImport("user32")]
    public static extern int RegisterWindowMessage(string message);
}

其他回答

简单地使用一个StreamWriter,怎么样?

System.IO.File.StreamWriter OpenFlag = null;   //globally

and

try
{
    OpenFlag = new StreamWriter(Path.GetTempPath() + "OpenedIfRunning");
}
catch (System.IO.IOException) //file in use
{
    Environment.Exit(0);
}

从这里。

跨进程互斥锁的一个常见用途是确保一个程序一次只能运行一个实例。以下是如何做到的:

class OneAtATimePlease {

  // Use a name unique to the application (eg include your company URL)
  static Mutex mutex = new Mutex (false, "oreilly.com OneAtATimeDemo");

  static void Main()
  {
    // Wait 5 seconds if contended – in case another instance
    // of the program is in the process of shutting down.
    if (!mutex.WaitOne(TimeSpan.FromSeconds (5), false))
    {
        Console.WriteLine("Another instance of the app is running. Bye!");
        return;
    }

    try
    {    
        Console.WriteLine("Running - press Enter to exit");
        Console.ReadLine();
    }
    finally
    {
        mutex.ReleaseMutex();
    }    
  }    
}

互斥锁的一个很好的特性是,如果应用程序在没有首先调用ReleaseMutex的情况下终止,CLR将自动释放互斥锁。

通常,这是我用于单实例Windows窗体应用程序的代码:

[STAThread]
public static void Main()
{
    String assemblyName = Assembly.GetExecutingAssembly().GetName().Name;

    using (Mutex mutex = new Mutex(false, assemblyName))
    {
        if (!mutex.WaitOne(0, false))
        {
            Boolean shownProcess = false;
            Process currentProcess = Process.GetCurrentProcess();

            foreach (Process process in Process.GetProcessesByName(currentProcess.ProcessName))
            {
                if (!process.Id.Equals(currentProcess.Id) && process.MainModule.FileName.Equals(currentProcess.MainModule.FileName) && !process.MainWindowHandle.Equals(IntPtr.Zero))
                {
                    IntPtr windowHandle = process.MainWindowHandle;

                    if (NativeMethods.IsIconic(windowHandle))
                        NativeMethods.ShowWindow(windowHandle, ShowWindowCommand.Restore);

                    NativeMethods.SetForegroundWindow(windowHandle);

                    shownProcess = true;
                }
            }

            if (!shownProcess)
                MessageBox.Show(String.Format(CultureInfo.CurrentCulture, "An instance of {0} is already running!", assemblyName), assemblyName, MessageBoxButtons.OK, MessageBoxIcon.Asterisk, MessageBoxDefaultButton.Button1, (MessageBoxOptions)0);
        }
        else
        {
            Application.EnableVisualStyles();
            Application.SetCompatibleTextRenderingDefault(false);
            Application.Run(new Form());
        }
    }
}

本地组件的位置:

[DllImport("User32.dll", CharSet = CharSet.Unicode, ExactSpelling = true, SetLastError = true)]
[return: MarshalAs(UnmanagedType.Bool)]
internal static extern Boolean IsIconic([In] IntPtr windowHandle);

[DllImport("User32.dll", CharSet = CharSet.Unicode, ExactSpelling = true, SetLastError = true)]
[return: MarshalAs(UnmanagedType.Bool)]
internal static extern Boolean SetForegroundWindow([In] IntPtr windowHandle);

[DllImport("User32.dll", CharSet = CharSet.Unicode, ExactSpelling = true, SetLastError = true)]
[return: MarshalAs(UnmanagedType.Bool)]
internal static extern Boolean ShowWindow([In] IntPtr windowHandle, [In] ShowWindowCommand command);

public enum ShowWindowCommand : int
{
    Hide                   = 0x0,
    ShowNormal             = 0x1,
    ShowMinimized          = 0x2,
    ShowMaximized          = 0x3,
    ShowNormalNotActive    = 0x4,
    Minimize               = 0x6,
    ShowMinimizedNotActive = 0x7,
    ShowCurrentNotActive   = 0x8,
    Restore                = 0x9,
    ShowDefault            = 0xA,
    ForceMinimize          = 0xB
}

永远不要使用命名互斥来实现单实例应用程序(至少在生产代码中不要这样做)。恶意代码可以很容易地DoS(拒绝服务)你的屁股…

我在这里找不到一个简单的解决方案,所以我希望有人会喜欢这个:

更新2018-09-20

把这段代码放在Program.cs中:

using System.Diagnostics;

static void Main()
{
    Process thisProcess = Process.GetCurrentProcess();
    Process[] allProcesses = Process.GetProcessesByName(thisProcess.ProcessName);
    if (allProcesses.Length > 1)
    {
        // Don't put a MessageBox in here because the user could spam this MessageBox.
        return;
    }

    // Optional code. If you don't want that someone runs your ".exe" with a different name:

    string exeName = AppDomain.CurrentDomain.FriendlyName;
    // in debug mode, don't forget that you don't use your normal .exe name.
    // Debug uses the .vshost.exe.
    if (exeName != "the name of your executable.exe") 
    {
        // You can add a MessageBox here if you want.
        // To point out to users that the name got changed and maybe what the name should be or something like that^^ 
        MessageBox.Show("The executable name should be \"the name of your executable.exe\"", 
            "Wrong executable name", MessageBoxButtons.OK, MessageBoxIcon.Error);
        return;
    }

    // Following code is default code:
    Application.EnableVisualStyles();
    Application.SetCompatibleTextRenderingDefault(false);
    Application.Run(new MainForm());
}