在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
当前回答
我喜欢一个解决方案,以允许多个实例,如果exe是从其他路径调用。我修改了CharithJ溶液方法一:
static class Program {
[DllImport("user32.dll")]
private static extern bool ShowWindow(IntPtr hWnd, Int32 nCmdShow);
[DllImport("User32.dll")]
public static extern Int32 SetForegroundWindow(IntPtr hWnd);
[STAThread]
static void Main() {
Process currentProcess = Process.GetCurrentProcess();
foreach (var process in Process.GetProcesses()) {
try {
if ((process.Id != currentProcess.Id) &&
(process.ProcessName == currentProcess.ProcessName) &&
(process.MainModule.FileName == currentProcess.MainModule.FileName)) {
ShowWindow(process.MainWindowHandle, 5); // const int SW_SHOW = 5; //Activates the window and displays it in its current size and position.
SetForegroundWindow(process.MainWindowHandle);
return;
}
} catch (Exception ex) {
//ignore Exception "Access denied "
}
}
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
}
其他回答
下面是我使用的一个轻量级解决方案,它允许应用程序将一个已经存在的窗口带到前台,而无需求助于自定义窗口消息或盲目地搜索进程名。
[DllImport("user32.dll")]
static extern bool SetForegroundWindow(IntPtr hWnd);
static readonly string guid = "<Application Guid>";
static void Main()
{
Mutex mutex = null;
if (!CreateMutex(out mutex))
return;
// Application startup code.
Environment.SetEnvironmentVariable(guid, null, EnvironmentVariableTarget.User);
}
static bool CreateMutex(out Mutex mutex)
{
bool createdNew = false;
mutex = new Mutex(false, guid, out createdNew);
if (createdNew)
{
Process process = Process.GetCurrentProcess();
string value = process.Id.ToString();
Environment.SetEnvironmentVariable(guid, value, EnvironmentVariableTarget.User);
}
else
{
string value = Environment.GetEnvironmentVariable(guid, EnvironmentVariableTarget.User);
Process process = null;
int processId = -1;
if (int.TryParse(value, out processId))
process = Process.GetProcessById(processId);
if (process == null || !SetForegroundWindow(process.MainWindowHandle))
MessageBox.Show("Unable to start application. An instance of this application is already running.");
}
return createdNew;
}
编辑:你也可以静态地存储和初始化互斥量和createdNew,但是一旦你完成了它,你需要显式地释放/释放互斥量。就我个人而言,我更喜欢将互斥锁保持在本地,因为即使应用程序在未到达Main结束时就关闭,它也会被自动销毁。
好吧,我有一个一次性的类,对于大多数用例来说很容易:
像这样使用它:
static void Main()
{
using (SingleInstanceMutex sim = new SingleInstanceMutex())
{
if (sim.IsOtherInstanceRunning)
{
Application.Exit();
}
// Initialize program here.
}
}
下面就是:
/// <summary>
/// Represents a <see cref="SingleInstanceMutex"/> class.
/// </summary>
public partial class SingleInstanceMutex : IDisposable
{
#region Fields
/// <summary>
/// Indicator whether another instance of this application is running or not.
/// </summary>
private bool isNoOtherInstanceRunning;
/// <summary>
/// The <see cref="Mutex"/> used to ask for other instances of this application.
/// </summary>
private Mutex singleInstanceMutex = null;
/// <summary>
/// An indicator whether this object is beeing actively disposed or not.
/// </summary>
private bool disposed;
#endregion
#region Constructor
/// <summary>
/// Initializes a new instance of the <see cref="SingleInstanceMutex"/> class.
/// </summary>
public SingleInstanceMutex()
{
this.singleInstanceMutex = new Mutex(true, Assembly.GetCallingAssembly().FullName, out this.isNoOtherInstanceRunning);
}
#endregion
#region Properties
/// <summary>
/// Gets an indicator whether another instance of the application is running or not.
/// </summary>
public bool IsOtherInstanceRunning
{
get
{
return !this.isNoOtherInstanceRunning;
}
}
#endregion
#region Methods
/// <summary>
/// Closes the <see cref="SingleInstanceMutex"/>.
/// </summary>
public void Close()
{
this.ThrowIfDisposed();
this.singleInstanceMutex.Close();
}
public void Dispose()
{
this.Dispose(true);
GC.SuppressFinalize(this);
}
private void Dispose(bool disposing)
{
if (!this.disposed)
{
/* Release unmanaged ressources */
if (disposing)
{
/* Release managed ressources */
this.Close();
}
this.disposed = true;
}
}
/// <summary>
/// Throws an exception if something is tried to be done with an already disposed object.
/// </summary>
/// <remarks>
/// All public methods of the class must first call this.
/// </remarks>
public void ThrowIfDisposed()
{
if (this.disposed)
{
throw new ObjectDisposedException(this.GetType().Name);
}
}
#endregion
}
我在解决方案中使用互斥来防止多个实例。
static Mutex mutex = null;
//A string that is the name of the mutex
string mutexName = @"Global\test";
//Prevent Multiple Instances of Application
bool onlyInstance = false;
mutex = new Mutex(true, mutexName, out onlyInstance);
if (!onlyInstance)
{
MessageBox.Show("You are already running this application in your system.", "Already Running..", MessageBoxButton.OK);
Application.Current.Shutdown();
}
请看下面的代码。它是防止一个WPF应用程序有多个实例的一个很好的简单解决方案。
private void Application_Startup(object sender, StartupEventArgs e)
{
Process thisProc = Process.GetCurrentProcess();
if (Process.GetProcessesByName(thisProc.ProcessName).Length > 1)
{
MessageBox.Show("Application running");
Application.Current.Shutdown();
return;
}
var wLogin = new LoginWindow();
if (wLogin.ShowDialog() == true)
{
var wMain = new Main();
wMain.WindowState = WindowState.Maximized;
wMain.Show();
}
else
{
Application.Current.Shutdown();
}
}
这是一篇关于互斥锁解决方案的很好的文章。本文描述的方法有两个优点。
首先,它不需要依赖于Microsoft。VisualBasic组装。如果我的项目已经依赖于该程序集,我可能会建议使用另一个答案中显示的方法。但事实上,我不使用微软。VisualBasic程序集,我宁愿不向项目添加不必要的依赖项。
其次,本文将展示当用户试图启动另一个实例时,如何将应用程序的现有实例显示到前台。这是这里描述的其他互斥锁解决方案没有解决的问题。
更新
截至2014年8月1日,我上面链接的文章仍然活跃,但博客已经有一段时间没有更新了。这让我担心,它最终可能会消失,随之而来的是所倡导的解决方案。我在这里复制这篇文章的内容以供后人参考。这些文字仅属于Sanity Free Coding的博客所有者。
Today I wanted to refactor some code that prohibited my application from running multiple instances of itself. Previously I had use System.Diagnostics.Process to search for an instance of my myapp.exe in the process list. While this works, it brings on a lot of overhead, and I wanted something cleaner. Knowing that I could use a mutex for this (but never having done it before) I set out to cut down my code and simplify my life. In the class of my application main I created a static named Mutex:
static class Program
{
static Mutex mutex = new Mutex(true, "{8F6F0AC4-B9A1-45fd-A8CF-72F04E6BDE8F}");
[STAThread]
...
}
Having a named mutex allows us to stack synchronization across multiple threads and processes which is just the magic I'm looking for. Mutex.WaitOne has an overload that specifies an amount of time for us to wait. Since we're not actually wanting to synchronizing our code (more just check if it is currently in use) we use the overload with two parameters: Mutex.WaitOne(Timespan timeout, bool exitContext). Wait one returns true if it is able to enter, and false if it wasn't. In this case, we don't want to wait at all; If our mutex is being used, skip it, and move on, so we pass in TimeSpan.Zero (wait 0 milliseconds), and set the exitContext to true so we can exit the synchronization context before we try to aquire a lock on it. Using this, we wrap our Application.Run code inside something like this:
static class Program
{
static Mutex mutex = new Mutex(true, "{8F6F0AC4-B9A1-45fd-A8CF-72F04E6BDE8F}");
[STAThread]
static void Main() {
if(mutex.WaitOne(TimeSpan.Zero, true)) {
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
mutex.ReleaseMutex();
} else {
MessageBox.Show("only one instance at a time");
}
}
}
So, if our app is running, WaitOne will return false, and we'll get a message box. Instead of showing a message box, I opted to utilize a little Win32 to notify my running instance that someone forgot that it was already running (by bringing itself to the top of all the other windows). To achieve this I used PostMessage to broadcast a custom message to every window (the custom message was registered with RegisterWindowMessage by my running application, which means only my application knows what it is) then my second instance exits. The running application instance would receive that notification and process it. In order to do that, I overrode WndProc in my main form and listened for my custom notification. When I received that notification I set the form's TopMost property to true to bring it up on top. Here is what I ended up with: Program.cs
static class Program
{
static Mutex mutex = new Mutex(true, "{8F6F0AC4-B9A1-45fd-A8CF-72F04E6BDE8F}");
[STAThread]
static void Main() {
if(mutex.WaitOne(TimeSpan.Zero, true)) {
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
mutex.ReleaseMutex();
} else {
// send our Win32 message to make the currently running instance
// jump on top of all the other windows
NativeMethods.PostMessage(
(IntPtr)NativeMethods.HWND_BROADCAST,
NativeMethods.WM_SHOWME,
IntPtr.Zero,
IntPtr.Zero);
}
}
}
NativeMethods.cs
// this class just wraps some Win32 stuff that we're going to use
internal class NativeMethods
{
public const int HWND_BROADCAST = 0xffff;
public static readonly int WM_SHOWME = RegisterWindowMessage("WM_SHOWME");
[DllImport("user32")]
public static extern bool PostMessage(IntPtr hwnd, int msg, IntPtr wparam, IntPtr lparam);
[DllImport("user32")]
public static extern int RegisterWindowMessage(string message);
}
Form1.cs(正面部分)
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
protected override void WndProc(ref Message m)
{
if(m.Msg == NativeMethods.WM_SHOWME) {
ShowMe();
}
base.WndProc(ref m);
}
private void ShowMe()
{
if(WindowState == FormWindowState.Minimized) {
WindowState = FormWindowState.Normal;
}
// get our current "TopMost" value (ours will always be false though)
bool top = TopMost;
// make our form jump to the top of everything
TopMost = true;
// set it back to whatever it was
TopMost = top;
}
}