你可以使用Mutex类，但是你很快就会发现你需要自己实现传递参数的代码。当我读Chris Sell的书时，我学到了一个用WinForms编程的技巧。这个技巧使用了框架中已经可用的逻辑。我不知道你怎么想，但当我了解到可以在框架中重用的东西时，这通常是我采取的路线，而不是重新发明轮子。当然，除非它不能做到我想要的一切。

当我进入WPF时，我想到了一种使用相同代码的方法，但在WPF应用程序中。基于您的问题，这个解决方案应该能够满足您的需求。

首先，我们需要创建应用程序类。在这个类中，我们将重写OnStartup事件并创建一个名为Activate的方法，该方法将在稍后使用。

public class SingleInstanceApplication : System.Windows.Application
{
    protected override void OnStartup(System.Windows.StartupEventArgs e)
    {
        // Call the OnStartup event on our base class
        base.OnStartup(e);

        // Create our MainWindow and show it
        MainWindow window = new MainWindow();
        window.Show();
    }

    public void Activate()
    {
        // Reactivate the main window
        MainWindow.Activate();
    }
}

Second, we will need to create a class that can manage our instances. Before we go through that, we are actually going to reuse some code that is in the Microsoft.VisualBasic assembly. Since, I am using C# in this example, I had to make a reference to the assembly. If you are using VB.NET, you don't have to do anything. The class we are going to use is WindowsFormsApplicationBase and inherit our instance manager off of it and then leverage properties and events to handle the single instancing.

public class SingleInstanceManager : Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase
{
    private SingleInstanceApplication _application;
    private System.Collections.ObjectModel.ReadOnlyCollection<string> _commandLine;

    public SingleInstanceManager()
    {
        IsSingleInstance = true;
    }

    protected override bool OnStartup(Microsoft.VisualBasic.ApplicationServices.StartupEventArgs eventArgs)
    {
        // First time _application is launched
        _commandLine = eventArgs.CommandLine;
        _application = new SingleInstanceApplication();
        _application.Run();
        return false;
    }

    protected override void OnStartupNextInstance(StartupNextInstanceEventArgs eventArgs)
    {
        // Subsequent launches
        base.OnStartupNextInstance(eventArgs);
        _commandLine = eventArgs.CommandLine;
        _application.Activate();
    }
}

基本上，我们使用VB位来检测单个实例并进行相应的处理。OnStartup将在第一个实例加载时被触发。当应用程序再次运行时，OnStartupNextInstance被触发。如您所见，我可以通过事件参数获得在命令行上传递的内容。我将值设置为一个实例字段。您可以在这里解析命令行，也可以通过构造函数和对Activate方法的调用将它传递给应用程序。

第三，是时候创建我们的入口点了。我们将利用SingleInstanceManager，而不是像通常那样更新应用程序。

public class EntryPoint
{
    [STAThread]
    public static void Main(string[] args)
    {
        SingleInstanceManager manager = new SingleInstanceManager();
        manager.Run(args);
    }
}

好吧，我希望您能够理解所有内容，能够使用这个实现并使其成为您自己的实现。

这么简单的问题有这么多答案。稍微改变一下这里是我对这个问题的解决方案。

Creating a Mutex can be troublesome because the JIT-er only sees you using it for a small portion of your code and wants to mark it as ready for garbage collection. It pretty much wants to out-smart you thinking you are not going to be using that Mutex for that long. In reality you want to hang onto this Mutex for as long as your application is running. The best way to tell the garbage collector to leave you Mutex alone is to tell it to keep it alive though out the different generations of garage collection. Example:

var m = new Mutex(...);
...
GC.KeepAlive(m);

我从这个网页上获得了灵感:http://www.ai.uga.edu/~mc/SingleInstance.html

下面是我使用的一个轻量级解决方案，它允许应用程序将一个已经存在的窗口带到前台，而无需求助于自定义窗口消息或盲目地搜索进程名。

[DllImport("user32.dll")]
static extern bool SetForegroundWindow(IntPtr hWnd);

static readonly string guid = "<Application Guid>";

static void Main()
{
    Mutex mutex = null;
    if (!CreateMutex(out mutex))
        return;

    // Application startup code.

    Environment.SetEnvironmentVariable(guid, null, EnvironmentVariableTarget.User);
}

static bool CreateMutex(out Mutex mutex)
{
    bool createdNew = false;
    mutex = new Mutex(false, guid, out createdNew);

    if (createdNew)
    {
        Process process = Process.GetCurrentProcess();
        string value = process.Id.ToString();

        Environment.SetEnvironmentVariable(guid, value, EnvironmentVariableTarget.User);
    }
    else
    {
        string value = Environment.GetEnvironmentVariable(guid, EnvironmentVariableTarget.User);
        Process process = null;
        int processId = -1;

        if (int.TryParse(value, out processId))
            process = Process.GetProcessById(processId);

        if (process == null || !SetForegroundWindow(process.MainWindowHandle))
            MessageBox.Show("Unable to start application. An instance of this application is already running.");
    }

    return createdNew;
}

编辑:你也可以静态地存储和初始化互斥量和createdNew，但是一旦你完成了它，你需要显式地释放/释放互斥量。就我个人而言，我更喜欢将互斥锁保持在本地，因为即使应用程序在未到达Main结束时就关闭，它也会被自动销毁。

我在这里找不到一个简单的解决方案，所以我希望有人会喜欢这个:

更新2018-09-20

把这段代码放在Program.cs中:

using System.Diagnostics;

static void Main()
{
    Process thisProcess = Process.GetCurrentProcess();
    Process[] allProcesses = Process.GetProcessesByName(thisProcess.ProcessName);
    if (allProcesses.Length > 1)
    {
        // Don't put a MessageBox in here because the user could spam this MessageBox.
        return;
    }

    // Optional code. If you don't want that someone runs your ".exe" with a different name:

    string exeName = AppDomain.CurrentDomain.FriendlyName;
    // in debug mode, don't forget that you don't use your normal .exe name.
    // Debug uses the .vshost.exe.
    if (exeName != "the name of your executable.exe") 
    {
        // You can add a MessageBox here if you want.
        // To point out to users that the name got changed and maybe what the name should be or something like that^^ 
        MessageBox.Show("The executable name should be \"the name of your executable.exe\"", 
            "Wrong executable name", MessageBoxButtons.OK, MessageBoxIcon.Error);
        return;
    }

    // Following code is default code:
    Application.EnableVisualStyles();
    Application.SetCompatibleTextRenderingDefault(false);
    Application.Run(new MainForm());
}

这里有一个解决方案:

Protected Overrides Sub OnStartup(e As StartupEventArgs)
    Const appName As String = "TestApp"
    Dim createdNew As Boolean
    _mutex = New Mutex(True, appName, createdNew)
    If Not createdNew Then
        'app is already running! Exiting the application
        MessageBox.Show("Application is already running.")
        Application.Current.Shutdown()
    End If
    MyBase.OnStartup(e)
End Sub

基于Matt Davis的答案，为方便起见包装成一个类。

public static class SingleAppInstanceChecker
{
    /// <summary>
    /// Arbitrary unique string
    /// </summary>
    private static Mutex _mutex = new Mutex(true, "0d12ad74-026f-40c3-bdae-e178ddee8602");

    public static bool IsNotRunning()
    {
        return _mutex.WaitOne(TimeSpan.Zero, true);
    }
}

使用示例:

private void Application_Startup(object sender, StartupEventArgs e)
{
    if (!SingleAppInstanceChecker.IsNotRunning())
    {
        MessageBox.Show("Application is already running.");

        // Exit application using:
        // Environment.Exit(1);
        // Application.Current.Shutdown();
        // Etc...

        return;
    }
    
    // Allow startup and continue with normal processing
    // ...
}