简单地使用一个StreamWriter，怎么样?

System.IO.File.StreamWriter OpenFlag = null;   //globally

and

try
{
    OpenFlag = new StreamWriter(Path.GetTempPath() + "OpenedIfRunning");
}
catch (System.IO.IOException) //file in use
{
    Environment.Exit(0);
}

你可以使用Mutex类，但是你很快就会发现你需要自己实现传递参数的代码。当我读Chris Sell的书时，我学到了一个用WinForms编程的技巧。这个技巧使用了框架中已经可用的逻辑。我不知道你怎么想，但当我了解到可以在框架中重用的东西时，这通常是我采取的路线，而不是重新发明轮子。当然，除非它不能做到我想要的一切。

当我进入WPF时，我想到了一种使用相同代码的方法，但在WPF应用程序中。基于您的问题，这个解决方案应该能够满足您的需求。

首先，我们需要创建应用程序类。在这个类中，我们将重写OnStartup事件并创建一个名为Activate的方法，该方法将在稍后使用。

public class SingleInstanceApplication : System.Windows.Application
{
    protected override void OnStartup(System.Windows.StartupEventArgs e)
    {
        // Call the OnStartup event on our base class
        base.OnStartup(e);

        // Create our MainWindow and show it
        MainWindow window = new MainWindow();
        window.Show();
    }

    public void Activate()
    {
        // Reactivate the main window
        MainWindow.Activate();
    }
}

Second, we will need to create a class that can manage our instances. Before we go through that, we are actually going to reuse some code that is in the Microsoft.VisualBasic assembly. Since, I am using C# in this example, I had to make a reference to the assembly. If you are using VB.NET, you don't have to do anything. The class we are going to use is WindowsFormsApplicationBase and inherit our instance manager off of it and then leverage properties and events to handle the single instancing.

public class SingleInstanceManager : Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase
{
    private SingleInstanceApplication _application;
    private System.Collections.ObjectModel.ReadOnlyCollection<string> _commandLine;

    public SingleInstanceManager()
    {
        IsSingleInstance = true;
    }

    protected override bool OnStartup(Microsoft.VisualBasic.ApplicationServices.StartupEventArgs eventArgs)
    {
        // First time _application is launched
        _commandLine = eventArgs.CommandLine;
        _application = new SingleInstanceApplication();
        _application.Run();
        return false;
    }

    protected override void OnStartupNextInstance(StartupNextInstanceEventArgs eventArgs)
    {
        // Subsequent launches
        base.OnStartupNextInstance(eventArgs);
        _commandLine = eventArgs.CommandLine;
        _application.Activate();
    }
}

基本上，我们使用VB位来检测单个实例并进行相应的处理。OnStartup将在第一个实例加载时被触发。当应用程序再次运行时，OnStartupNextInstance被触发。如您所见，我可以通过事件参数获得在命令行上传递的内容。我将值设置为一个实例字段。您可以在这里解析命令行，也可以通过构造函数和对Activate方法的调用将它传递给应用程序。

第三，是时候创建我们的入口点了。我们将利用SingleInstanceManager，而不是像通常那样更新应用程序。

public class EntryPoint
{
    [STAThread]
    public static void Main(string[] args)
    {
        SingleInstanceManager manager = new SingleInstanceManager();
        manager.Run(args);
    }
}

好吧，我希望您能够理解所有内容，能够使用这个实现并使其成为您自己的实现。

但是不使用互斥，简单的回答:

System.Diagnostics;    
...
string thisprocessname = Process.GetCurrentProcess().ProcessName;

if (Process.GetProcesses().Count(p => p.ProcessName == thisprocessname) > 1)
                return;

把它放在Program.Main()中。 例子:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.Diagnostics;

namespace Sample
{
    static class Program
    {
        /// <summary>
        /// The main entry point for the application.
        /// </summary>
        [STAThread]
        static void Main()
        {
            //simple add Diagnostics namespace, and these 3 lines below 
            string thisprocessname = Process.GetCurrentProcess().ProcessName;
            if (Process.GetProcesses().Count(p => p.ProcessName == thisprocessname) > 1)
                return;

            Application.EnableVisualStyles();
            Application.SetCompatibleTextRenderingDefault(false);
            Application.Run(new Sample());
        }
    }
}

您可以添加MessageBox。在if语句中显示并输入“应用程序已运行”。 这可能对某些人有帮助。

这么简单的问题有这么多答案。稍微改变一下这里是我对这个问题的解决方案。

Creating a Mutex can be troublesome because the JIT-er only sees you using it for a small portion of your code and wants to mark it as ready for garbage collection. It pretty much wants to out-smart you thinking you are not going to be using that Mutex for that long. In reality you want to hang onto this Mutex for as long as your application is running. The best way to tell the garbage collector to leave you Mutex alone is to tell it to keep it alive though out the different generations of garage collection. Example:

var m = new Mutex(...);
...
GC.KeepAlive(m);

我从这个网页上获得了灵感:http://www.ai.uga.edu/~mc/SingleInstance.html

基于命名互斥的方法不是跨平台的，因为命名互斥在Mono中不是全局的。基于进程枚举的方法没有任何同步，可能会导致不正确的行为(例如，同时启动的多个进程可能都根据时间自行终止)。在控制台应用程序中不需要基于windows系统的方法。这个解决方案建立在Divin的答案之上，解决了所有这些问题:

using System;
using System.IO;

namespace TestCs
{
    public class Program
    {
        // The app id must be unique. Generate a new guid for your application. 
        public static string AppId = "01234567-89ab-cdef-0123-456789abcdef";

        // The stream is stored globally to ensure that it won't be disposed before the application terminates.
        public static FileStream UniqueInstanceStream;

        public static int Main(string[] args)
        {
            EnsureUniqueInstance();

            // Your code here.

            return 0;
        }

        private static void EnsureUniqueInstance()
        {
            // Note: If you want the check to be per-user, use Environment.SpecialFolder.ApplicationData instead.
            string lockDir = Path.Combine(
                Environment.GetFolderPath(Environment.SpecialFolder.CommonApplicationData),
                "UniqueInstanceApps");
            string lockPath = Path.Combine(lockDir, $"{AppId}.unique");

            Directory.CreateDirectory(lockDir);

            try
            {
                // Create the file with exclusive write access. If this fails, then another process is executing.
                UniqueInstanceStream = File.Open(lockPath, FileMode.Create, FileAccess.Write, FileShare.None);

                // Although only the line above should be sufficient, when debugging with a vshost on Visual Studio
                // (that acts as a proxy), the IO exception isn't passed to the application before a Write is executed.
                UniqueInstanceStream.Write(new byte[] { 0 }, 0, 1);
                UniqueInstanceStream.Flush();
            }
            catch
            {
                throw new Exception("Another instance of the application is already running.");
            }
        }
    }
}

我喜欢一个解决方案，以允许多个实例，如果exe是从其他路径调用。我修改了CharithJ溶液方法一:

   static class Program {
    [DllImport("user32.dll")]
    private static extern bool ShowWindow(IntPtr hWnd, Int32 nCmdShow);
    [DllImport("User32.dll")]
    public static extern Int32 SetForegroundWindow(IntPtr hWnd);
    [STAThread]
    static void Main() {
        Process currentProcess = Process.GetCurrentProcess();
        foreach (var process in Process.GetProcesses()) {
            try {
                if ((process.Id != currentProcess.Id) && 
                    (process.ProcessName == currentProcess.ProcessName) &&
                    (process.MainModule.FileName == currentProcess.MainModule.FileName)) {
                    ShowWindow(process.MainWindowHandle, 5); // const int SW_SHOW = 5; //Activates the window and displays it in its current size and position. 
                    SetForegroundWindow(process.MainWindowHandle);
                    return;
                }
            } catch (Exception ex) {
                //ignore Exception "Access denied "
            }
        }

        Application.EnableVisualStyles();
        Application.SetCompatibleTextRenderingDefault(false);
        Application.Run(new Form1());
    }
}